1. What kind of intermolecular forces act between a chlorine monofluoride molecule and a hydrogen bromide moleculeNote: If there is more than one type of intermolecular force that acts, be sure to list them all, with a comma between the name of each force.

Answers

Answer 1

Answer:

Final answer:

The intermolecular forces that act between chlorine monofluoride (ClF) and hydrogen bromide (HBr) are dipole-dipole interactions. These types of forces result from the attraction between polar molecules.

Explanation:

The intermolecular forces that act between a chlorine monofluoride (ClF) molecule and a hydrogen bromide (HBr) molecule are

dipole-dipole interactions

. A

dipole-dipole interaction

is a type of force that results from the attraction between polar molecules. Since ClF and HBr are both polar molecules, they exhibit this kind of interaction. For instance, the positive end of the polar ClF molecule would be attracted to the negative end of the polar HBr molecule, and vice versa, leading to a

dipole-dipole interaction

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Answer 2

Answer:

Final answer:

Between chlorine monofluoride and hydrogen bromide, the intermolecular forces present are dipole-dipole forces and London dispersion forces due to their polar nature and instantaneous polarizations of electron clouds respectively.

Explanation:

The intermolecular forces that act between a chlorine monofluoride molecule and a hydrogen bromide molecule are primarily the dipole-dipole forces. Dipole-dipole forces are attractive forces that occur between the positive end of one polar molecule and the negative end of another polar molecule. Both chlorine monofluoride and hydrogen bromide are polar molecules, and as such, they interact through dipole-dipole forces. Apart from this, there exists London dispersion forces which are weak forces resulting from instantaneous polarizations of electron clouds in molecules. Hence, between chlorine monofluoride and hydrogen bromide, both dipole-dipole forces and London dispersion forces act.

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a student wants to remove the salt from a mixture of sand and salt in order to get only person he adds water to the mixture why it's the step help

I need to find the answer for
_ ML = 8,000,000 L

Answers

Answer:

To find the value of the blank in the equation "_ ML = 8,000,000 L," you can simply fill in the blank with a number:

"_ ML = 8,000,000 L" can be filled in as "8,000 ML = 8,000,000 L."

So, the answer is 8,000 ML.

Culled from AI

What is the molarity of the following solutions?a. 19.5 g NaHCO3 in 460.0 ml solution
b. 26.0 g H2SO4 in 200.0 mL solution
c. 15.0 g NaCl dissolved to make 420.0 mL solution

Answers

Answer:

a) NaHCO3 = 0.504 M

b) H2SO4 = 1.325 M

c) NaCl = 0.610 M

Explanation:

Step 1: Data given

Moles = mass / molar mass

Molarity = moles / volume

a. 19.5 g NaHCO3 in 460.0 ml solution

Step 1: Data given

Mass NaHCO3 = 19.5 grams

Volume = 460.0 mL = 0.460 L

Molar mass NaHCO3 = 84.0 g/mol

Step 2: Calculate moles NaHCO3

Moles NaHCO3 = 19.5 grams / 84.0 g/mol

Moles NaHCO3 = 0.232 moles

Step 3: Calculate molarity

Molarity = 0.232 moles / 0.460 L

Molarity = 0.504 M

b. 26.0 g H2SO4 in 200.0 mL solution

Step 1: Data given

Mass H2SO4 = 26.0 grams

Volume = 200.0 mL = 0.200 L

Molar mass H2SO4 = 98.08 g/mol

Step 2: Calculate moles H2SO4

Moles H2SO4 = 26.0 grams / 98.08 g/mol

Moles H2SO4 = 0.265 moles

Step 3: Calculate molarity

Molarity = 0.265 moles / 0.200 L

Molarity =1.325 M

c. 15.0 g NaCl dissolved to make 420.0 mL solution

Step 1: Data given

Mass NaCl = 15.0 grams

Volume = 420.0 mL = 0.420 L

Molar mass NaCl = 58.44 g/mol

Step 2: Calculate moles NaCl

Moles NaCl = 15.0 grams / 58.44 g/mol

Moles NaCl = 0.256 moles

Step 3: Calculate molarity

Molarity = 0.256 moles / 0.420 L

Molarity =0.610 M

Chlorine (Cl2Cl2) is a strong germicide used to disinfect drinking water and to kill microbes in swimming pools. If the product is Cl−Cl−, was the elemental chlorine oxidized or reduced?

Answers

Answer:

The elemental chlorine was reduced

Explanation: inl the elemental form, the oxidation state of chlorine is =0 on been reduced to Cl-Cl-, the oxidation state reduces to -1

If the partial pressure of N2 in a scuba divers blood at the surface is 0.79 atm, what will the pressure be if he/she descends to a depth of 30 meters (4 atm) and stays there long enough to reach equilibrium (b)

Answers

Answer:

Explanation:

for every 3m that the internal pressure is lowered, it increases in an atmosphere approximately, so when the blood pressure of nitrogen decreases 30m, it will increase by approximately 10 atm, being enough there for the body to enter into equilibrium

What is the molarity of a solution prepared from 25.0 grams of methanol (CH3OH, density = 0.792 g/mL) with 100.0 milliliters of ethanol (CH3CH2OH)? Assume the volumes are additive.

Answers

Final answer:

The molarity of a solution prepared from 25.0 grams of methanol and 100.0 milliliters of ethanol is approximately 7.80 M.

Explanation:

This is a question about calculating molarity, which is a measure of concentration using moles per liter. To calculate the molarity of a methanol in ethanol, we first have to convert the mass of methanol into moles. The molar mass of methanol (CH3OH) is about 32.04 g/mol. Therefore, 25.0 g of methanol equals about 0.780 moles (25.0 g ÷ 32.04 g/mol).

Next, the volume of ethanol needs to be converted from milliliters to liters. Thus, 100.0 mL becomes 0.100 L. Finally, the molarity is calculated by dividing the moles of methanol by the volume of the ethanol in liters, resulting in a molarity of approximately 7.80 M (0.780 moles ÷ 0.100 L).

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Benzene is a starting material in the synthesis of nylon fibers and polystyrene (styrofoam). Its specific heat capacity is 1.74 J/g·°C. If 16.7 kJ of energy is absorbed by a 225-g sample of benzene at 20.0°C, what is its final temperature?