In order to balance this, you have to count each element where the elements in the reactants side and the product side should have equal number of molecules. The balanced reaction is as follows:
P4(s) + 6Cl2(g) = 4PCl3(l)
Thus, the answer is 4.
Answer:
4
Explanation:
I got it right on edge
Answer:
The % yield of the reaction is 73.8 %
Explanation:
To solve this, we list out the given variables thus
Mass of aluminium in the experiment = 2.5 g
mass of oxygen gas in the experiment = 2.5 g
Molar mass of aluminium = 26.98 g/mol
molar mass of oxygen O₂ = 32 g/mol
The reaction between aluminium and gaseous oxygen can be written as follows
4Al + 3O₂ → 2Al₂O₃
Thus four moles of aluminium forms two moles of aluminium oxide
Thus (2.5 g)÷(26.98 g/mol) = 0.093 mole of aluminium and
(2.5 g)÷(32 g/mol) = 0.078125 moles of oxygen
However four moles of aluminium react with three moles of oxygen gas O₂
1 mole of aluminum will react with 3/4 moles of oxygen O₂ and 0.093 mole of aluminium will react with 0.093*3/4 moles of O₂ = 0.0695 moles of Oxygen hence aluminium is the limiting reagent and we have
1 mole of oxygen will react with 4/3 mole of aluminium
∴ 0.078125 mole of oxygen will react with 0.104 moles of aluminium
Therefore 0.093 mole of aluminium will react with O₂ to produce 2/4×0.093 or 0.0465 moles of 2Al₂O₃
The molar mass of 2Al₂O₃ = 101.96 g/mol
Hence the mass of 0.0465 moles = number of moles × (molar mass)
= 0.0465 moles × 101.96 g/mol = 4.74 g
The of aluminium oxide Al₂O₃ is 4.74 g, but the actual yield = 3.5 g
Therefore the Percentage yield = ×100 = × 100 = 73.8 % yield
Answer:
The percent yield of reaction is 54.32%.
Explanation:
Moles of methane =
According to reaction, 1 mole of methane gives 2 moles of water .
The 0.3115 moles of methane will give:
of water
Mass of 0.9345 moles of water = 0.623 mol × 18.02 g/mol = 11.23 g.
Theoretical yield of methane = 11.23 g.
Experimental yield of methane = 6.10 g.
The percent yield of reaction:
The percent yield of reaction is :
Answer:54.5
Explanation:
not?
The characteristics of the density we can find that the answer for the effect of sugar is;
Density is the relationship between the mass and the volume of a body, this is a very useful relationship for fluid mechanics exercise.
Where ρ is the density, m the mass and V the volume
In this laboratory the liquid is possibly water since a solution is formed with the sugar, the volume of the solution does not change with the introduction of the solute (sugar), therefore the introduction of sugar creates a change in the mass of the solution.
Consequently, if the mass increases and the volume remains constant, the density should increase, possibly in a linear fashion with increasing mass.
The most important assumption is that the effect of the other ingredients of the drink is that it does not react with the sugar.
In conclusion using the density characteristics we find that the response for the sugar effect is;
Learn more about density here:
The assumption is that other ingredients do not noticeably affect the density of the beverage, and changes in density are attributed solely to sugar content. The validity of this assumption would depend on various factors such as the densities and quantities of the other ingredients.
The assumption in this lab is that the other ingredients in the beverage do not significantly impact its density. This would imply that the changes in density observed are due solely to the sugar content. The validity of this assumption would depend on several factors. For instance, if the other elements are in relatively small quantities, or their densities are similar to that of the primary component (water in most beverages), the assumption may hold true. Nonetheless, it's important to point that this is an approximation, as in reality, every ingredient may contribute to the overall density.
#SPJ3
(2) selenium (4) sodium
Selenium has the greatest density at STP.
According to Ideal gas equation,
P V = n R T
where;
n = m/M
Therefore,
P V = m R T / M
Rearranging,
P M = (m/V) R T
Also,
m/V = density = d
So,
P M = d R T
Solving for density,
d = P M / R T
According to this equation density is directly proportional to Molar mass of a substance. Hence, the Atomic masses of given compounds are listed below,
Scandium = 44.96 g.mol⁻¹
Selenium = 78.97 g.mol⁻¹
Silicon = 28.09 g.mol⁻¹
Sodium = 22.99 g.mol⁻¹
Therefore, selenium having the greatest Atomic Mass will have the greatest density. The densities of given elements are as follow;
Scandium = 2.98 g.cm⁻³
Selenium = 4.81 g.cm⁻³
Silicon = 2.33 g.cm⁻³
Sodium = 0.96 g.cm⁻³
has the greatest density at STP.
Further Explanation:
Ideal gas law is the equation of state for any hypothetical gas. The expression for the ideal gas equation is as follows:
…… (1)
Here,
P is the pressure.
V is the volume.
T is the absolute temperature.
n is the number of moles.
R is the universal gas constant.
The formula to calculate the number of moles is as follows:
...... (2)
Here,
n is the number of moles.
m is the mass.
M is the molar mass.
Substitute the value of n from equation (2) in equation (1).
…… (3)
Rearrange equation (3) as follows:
…… (4)
The formula to calculate density is as follows:
...... (5)
Here,
is the density.
m is the mass.
V is the volume.
Substitute equation (5) in equation (4).
…… (6)
Rearrange equation (6) to calculate the density.
...... (7)
At STP, T and P remain constant, R is already a constant. So according to equation (7), density of substance is directly proportional to the molar mass of the substance.
The molar mass of scandium is 44.96 g/mol.
The molar mass of selenium is 78.97 g/mol.
The molar mass of silicon is 28.09 g/mol.
The molar mass of sodium is 22.99 g/mol.
The molar mass of selenium is the highest among the given elements so its density will be the greatest.
Learn more:
1. Which statement is true for Boyle’s law: brainly.com/question/1158880
2. Calculation of volume of gas: brainly.com/question/3636135
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Ideal gas equation
Keywords: P, V, n, R, T, ideal gas, pressure, volume, selenium, sodium, scandium, silicon, 22.99 g/mol, 78.97 g/mol, 28.09 g/mol, 44.96 g/mol, density, molar mass.
Answer:
Explanation:
Given parameters:
Mass of ionic compound = 0.3257g
Mass of AgBr precipitate = 0.7165g
Unknown:
Percent mass of Br in the original compound.
Solution
The percent mass of Br in original compound =
Now we have to find the mass of Br⁻:
We must note that the same mass of Br⁻ would move through the ionic sample to form the precipitate.
Mass of Br in AgBr =
Mass of Br = x 0.7165
Mass of Br = 0.426 x 0.7165 = 0.305g
Percent mass of Br = x 100 = 93.7%