(2) 2 mol of KI in 500. g of water
(3) 1 mol of KI in 1000. g of water
(4) 2 mol of KI in 1000. g of water
B. attracted to the anode of the voltage source.
C. considered an impurity in the crystal.
D. incapable of carrying a charge.
(D. is wrong)
Answer:
A. attracted to the negative terminal of the voltage source.
Explanation:
bc that is what the hole that's left behind does
Answer:
Humidity
Explanation:
plz pick brainliest
(Also this is Generation Genius so I got u bro! :D)
4% of the mass of air. Hot air can hold more water vapor than cold air, so the amount of water vapor is highest in hot, tropical areas and lowest in cold, polar regions
Explanation:
It is the type of cell used in electroplating
It uses an electric current to make a nonspontaneous reaction go.
All of the above
18. The products formed in the net reaction of the electrolysis of water are ____.
aqueous hydrogen ion and hydroxyl ion
hydrogen gas and oxygen gas
liquid hydrogen and oxygen gas
liquid oxygen and hydrogen gas
19. What occurs in electroplating?
decomposition of a metal layer
decomposition of a salt layer
deposition of a metal layer on a material
deposition of a salt layer on a metal
An electrolytic cell uses an electric current to make a nonspontaneous reaction go and is used in electroplating. The products formed in the electrolysis of water are hydrogen gas and oxygen gas. Electroplating involves the deposition of a metal layer on a material.
An electrolytic cell is a type of cell that uses an electric current to make a nonspontaneous reaction go. This means it can drive a chemical reaction in a direction that does not occur naturally. Electrolytic cells are commonly used in electroplating, where a metal layer is deposited onto a material. Therefore, all of the given options in question 17 are true about an electrolytic cell. For question 18, the products formed in the net reaction of the electrolysis of water are hydrogen gas and oxygen gas. Electrolysis of water involves the decomposition of water into its elemental components. In electroplating, the process involves the deposition of a metal layer on a material. This is achieved by passing an electric current through a solution containing metal ions, causing the metal ions to be reduced and deposit onto the material's surface.
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CIO4-=-1
CI=4O=-1
O has a 2- oxidation change so
CI+4(-2)=-1
CI+(-8)=-1
CI=-1+8=7
So the oxidation number of chlorine is 7 in this case