Answer: N (atomic number 7)
Explanation:
1) Due the electron distribution of each, taking into account Hund's rule to deal with pairing of electrons.
2) Hund's rule: each subshell orbital is occupied with single electrons of parallel spin before double occupation occurs.
That is, before any one orbital is doubly occupied, every orbital in a subshell is singly occupied with one electron, and all the electrons in singly occupied orbitals have the same spin, which means that they are unpaired.
3) Distributions:
a) C (atomic number 6) ⇒ 6 electrons:
⇒ 1s² 2s² 2p² ⇒ 1s² 2s² 2p ↑ ↑ : as per Hund's rule the two electrons on 2p are unpaired.
b) O (atomic number 8) ⇒ 8 electrons
⇒ 1s² 2s² 2p⁴ ⇒ 1s² 2s² 2p⇅ ↑ ↑: as per Hund's rule the two 2p electrons are unpaired
c) N (atomic number 7) ⇒ 7 electrons
1s² 2s² 2p³ ⇒ 1s² 2s² 2p↑ ↑ ↑: as per Hund's rule, the three 2p electrons are unpaired, so this is the answer to the question.
c) Be (atomic number 4) ⇒ 4 electrons
⇒ 1s² 2s² ⇒ none p electron.
Nitrogen has three unpaired electrons in its p orbital.
Among the given elements, nitrogen (atomic number 7) has three unpaired electrons in its p orbital.
In the electron configuration of nitrogen, it has a total of five electrons: 2 in the 1st energy level and 3 in the 2nd energy level. The p sublevel of the 2nd energy level contains three orbitals, each capable of holding 2 electrons. Therefore, the three unpaired electrons in nitrogen's p orbital are in three separate p orbitals in the 2nd energy level.
Carbon has two unpaired electrons in its p orbital, while oxygen has two unpaired electrons in its p orbital and two in its s orbital. Beryllium does not have any unpaired electrons in its p orbital.
#SPJ6
The percentage composition of a substance is determined to analyze how much of an element is present in the substance and and why they needed.
The percentage composition of a compound or element in a mixture is the ratio of mass of the element to the total mass multiplied by 100.
here are many scenarios in daily life where calculating the percentage composition of something may be useful, such as:
Cooking and baking: When following a recipe, it may be necessary to calculate the percentage of ingredients used in a recipe to adjust the quantities.
Nutrition: When tracking your diet, you may need to calculate the percentage composition of macronutrients like protein, carbohydrates, and fat.
Finance: When creating a budget, you may need to calculate the percentage of income allocated to different expenses, such as housing, transportation, and food.
Chemistry: In chemistry, calculating the percentage composition of a compound is an essential step in determining its chemical formula and properties.
Manufacturing: In manufacturing, calculating the percentage composition of raw materials and finished products is important for quality control and cost analysis.
Medicine: In medicine, calculating the percentage of drugs in a medication is essential for prescribing the appropriate dose.
These are just a few examples, but there are many other scenarios where calculating percentage composition is useful.
Find more on percentage composition :
#SPJ3
Mixture; compounds; elements
Element; compounds; mixture
Compound; elements; compounds
12.The number of _____ determines which element it is.
electrons
protons
positrons
neutrons
Answer:
Yes, this reaction will be spontaneous.
Explanation:
A reaction is spontaneous if ΔG < 0.
The coupling of glycerol to glycerol-3-phospate with ATP gives:
glycerol + HPO₄²⁻ ⟶ glycerol-3-phosphate + H₂O ΔG = +9,2 kJ/mol
ATP + H₂O ⟶ ADP + HPO₄²⁻ ΔG = -30,5 kJ/mol
glycerol + ATP ⟶ ADP + glycerol-3-phosphate
ΔG = +9,2 kJ/mol - 30,5 kJ/mol = -21,3 kJ/mol
As ΔG<0, this reaction will be spontaneous
I hope it helps!
Answer;
Yes; this reaction be spontaneous if coupled with the hydrolysis of ATP.
Explanation;
The reaction converting glycerol to glycerol-3-phosphate (energetically unfavorable) can be coupled with the conversion of ATP to ADP (energetically favorable):
Glycerol + HPO42 ⟶glycerol-3-phosphate+H2O
ATP + H2O⟶ ADP + HPO42− + H+
(2) beta particle (4) positron
Answer: Gamma ray
Explanation: Nuclear Emission explains the release of energy stored in the nucleus of an atom in the form of particles like alpha particles, beta particles, gamma ray etc.
Alpha particles are the helium atom having +2 charge.
Beta particles have -1 charge thus beta particle and the electron are same.
Positron has a charge of +1 electron having 1/2 spin.
Gamma rays are the rays which are neutral and have no mass.
A gamma ray is a nuclear emission that has no charge and no mass.
Nuclear radiation refers to the emission of particles or electromagnetic waves from atomic nuclei undergoing decay. Types include alpha, beta, and gamma radiation, each with varying properties and effects. It is a fundamental concept in nuclear physics and has applications in medicine, energy production, and weaponry.
The nuclear emission that has no charge and no mass is the gamma ray. Unlike the other options listed, which are particles, gamma rays are electromagnetic radiation and do not have mass or charge. They are highly penetrating and can pass through many materials without being deflected.
#SPJ6