State charles's law. If a balloon occupies 885 cm3 volume at 20°C and 794 cm3 at - 10°C , prove that this is according to charles's law.

Answers

Answer 1

Answer:

find the distance between

the following points:

a) AC0₂0) and B(5, 2)

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The ____ contains the highest concentration of ozone.a. troposphere
c. stratosphere
b. mesosphere
d. exosphere

Answers

C. The stratosphere. About 90% of the ozone is in the stratosphere which begins about 8 miles above the Earth's surface.

Answer: Option (c) is the correct answer.

Explanation:

A layer above the troposphere and below the mesosphere is known as stratosphere.

This layer of stratosphere contains about 90% concentration of ozone and there is no occurrence of weather in this layer.

The occurrence of ozone in stratosphere makes it warmer.

Therefore, we can conclude that the stratosphere contains the highest concentration of ozone.

Mendeleev saw trends in the physical and chemical properties of elements when he organized them by _____.

Answers

Mendeleev saw the properties of the elements repeated in an orderly way when he organized them according to increasing atomic mass. Mendeleev was als the first one who successfully arranged the elements in the periodic table and this is what we have been using today.

Answer: Density

Explanation:

in a school’s laboratory, students require 50.0 mL of 2.50 M H2SO4 for an experiment, but the only available stock solution of the acid has a concentration of 18.0 M. What volume of the stock solution would they use to make the required solution? Use mc018-1.jpg.

Answers

Ans: Volume of stock H2SO4 required = 6.94 ml

Given:

Concentration of stock H2SO4 solution M1 = 18.0 M

Concentration of the final H2SO4 solution needed M2 = 2.50 M

Final volume of H2SO4 needed, V2 = 50.0 ml

To determine:

Volume of stock needed, V1

Explanation:

Use the dilution relation:

$M1V1 = M2V2\n\nV1 = (M2V2)/(M1) \n\nV1 = (2.50 M * 50.0 ml)/(18.0 M) = 6.94 ml$

Hello!

In a school’s laboratory, students require 50.0 mL of 2.50 M H2SO4 for an experiment, but the only available stock solution of the acid has a concentration of 18.0 M. What volume of the stock solution would they use to make the required solution?

We have the following data:

M1 (initial molarity) = 2.50 M (or mol/L)

V1 (initial volume) = 50.0 mL → 0.05 L

M2 (final molarity) = 18.0 M (or mol/L)

V2 (final volume) = ? (in mL)

Let's use the formula of dilution and molarity, so we have:

$M_(1) * V_(1) = M_(2) * V_(2)$

$2.50 * 0.05 = 18.0 * V_(2)$

$0.125 = 18.0\:V_2$

$18.0\:V_2 = 0.125$

$V_2 = (0.125)/(18.0)$

$V_2 \approx 0.00694\:L \to \boxed{\boxed{V_2 \approx 6.94\:mL}}\:\:\:\:\:\:\bf\green{\checkmark}$

Answer:

The volume is approximately 6.94 mL

_______________________________

$\bf\green{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}$

The recipe for pumpkin pie calls for 3 tablespoons of flour and 1.5 cups of sugar for each pie. Which of the following conversion factors would be used to find out how many pies could be made from 7.5 cups of sugar.

Answers

Answer:

5 pumpkin pies could be made with 7.5 cups of sugar.

Explanation:

The conversion factor to solve the problem is:

$7.5 cups of sugar*(1 pie)/(1.5 cups of sugar) = 5 pies$

Consider the following reaction: SO2Cl2(g)⇌SO2(g)+Cl2(g) A reaction mixture is made containing an initial [SO2Cl2] of 2.2×10−2M . At equilibrium, [Cl2]= 1.3×10−2M . Calculate the value of the equilibrium constant (Kc).

Answers

The value of equilibrium constant (Kc) will be 0.0188.

Equilibrium constant :

The equilibrium constant of a chemical reaction is the value of its reaction quotient at chemical equilibrium, a state approached by a dynamic chemical system after sufficient time has elapsed at which its composition has no measurable tendency towards further change.

Given reaction:

SO₂Cl₂(g)⇌SO₂(g)+Cl₂(g)

To find:

Kc=?

The equation that represents kc for the given reaction will be:

$k_c=([SO_2][Cl_2])/([SO_2Cl_2])$

On substituting the initial concentration:

$k_c=([SO_2][Cl_2])/([SO_2Cl_2])\n\nk_c=([1.3*10^(-2)][1.3*10^(-2)])/([2.2*10^(-2)-1.3*10^(-2)]) \n\nk_c=0.0188$

Thus, the value of equilibrium constant (Kc)will be 0.0188.

Find out more information about "equilibrium constant" here :

brainly.com/question/12858312

The value of equilibrium constant is equal to the quotient of the products raised to its stoichiometric coefficient over the reaction's reactants raised to its respective stoichiometric coeff. The equation is Kc=[SO2][Cl2]/[SO2Cl2]= [1.3*10^-2][1.3*10^-2]/[2.2*10^-2-1.3*10^-2]=0.0188. The final answer is Kc=0.0188.

Which list of elements is arranged in order of increasing atomic radii?(1) Li, Be, B, C (3) Sc, Ti, V, Cr(2) Sr, Ca, Mg, Be (4) F, Cl, Br, I

Answers

Elements which are arranged in increasing order of atomic radii are F,Cl,Br, I.

What is atomic radius ?

Atomic radius is defined as the distance between nucleus of an atom and the valence electrons.In a group, atomic radii increases up to down as electrons are added in the next successive shell which increases the size of atom.

In a period, as electrons are added to the same shell the force of attraction between nucleus and valence electrons increases as a result of which atom tend to shrink resulting in decrease in atomic size.

As fluorine, chlorine, bromine and iodine are present in the same group their atomic size increases as new shells are added from top to bottom of periodic table., while for the elements given in other options they are present in same period or in different group and hence do not show an gradual increase in atomic radii.

Learn more about atomic radius,here:

brainly.com/question/14544878

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Answer: F,Cl,Br,l

Explanation:these elements are all part of group 17

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