Answer:
2Al + 6HCl -> 2AlCl3 + 3H2
Explanation:
b. the absorption of energy.
c. no energy change.
Answer:
The correct answer is option a. the removal of energy.
Explanation:
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Freezing is a process by which a lot of heat is lost, this loss of heat leads to a loss of energy as well. It means that energy is eliminated so that heat loss occurs.
Therefore the correct answer is option a. the removal of energy.
The model most likely represents a reaction which
Select one:
a. takes place when atoms combine
b. takes place when atoms become inactive
c. does not produce energy in the sun
d. does not produce energy in nuclear power plants
Answer: b: takes place when atoms become inactive
Explanation: the model described above is a nuclear fission reaction, a reasonably controlled reaction that releases energy and is employed in nuclear power plants. In these reactions one Atom is split into two lighter ones and there's a resultant release of energy in the process. The original Atom becomes depleted (inactive) as is the case with Uranium 235.
This reaction is opposed to fusion reactions that occur in nature e.g. the sun, and are basically uncontrollable — involving the combination of two atoms into one.
The pressure of the gas will become double when its Kelvin temperature becomes its initial value.
Further Explanation:
Ideal gas equation:
Ideal gas is just a theoretical concept and practically no gas can act as ideal. It can be considered as group of random moving particles having perfectly elastic collisions between them.
Ideal gas equation for one mole of gas is mentioned below.
PV = RT …… (1)
Here,
P is the gas pressure.
V is the gas volume.
T is the absolute temperature of gas.
R is the universal gas constant.
Standard conditions refer to state when pressure of gas is 1 atm and its temperature is 273 K.
Consider P’ and T’ to be new pressure and temperature respectively while all other terms in ideal gas equation remains constant. Equation (1) then modifies as follows:
P’V = RT’ …… (2)
Since new pressure is doubled, P’ becomes 2P. Equation (2) becomes,
(2P)V = RT’ …… (3)
Dividing equation (3) by equation (1), we get:
…… (4)
Solving for T’,
Therefore pressure is doubled when temperature becomes twice its initial value.
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Ideal gas equation
Keywords: ideal gas equation, R, T, P, V, 2P, 2T, pressure, volume, universal gas constant, P’, T’, standard conditions.