Answer:
amu = 34.055 or 34.1
Explanation:
to calculate the average mass, first convert the percentages into decimals. Then, calculate the mass numbers. To get this number, multiply the decimal by the mass number for each isotope and, then add them together.
( 0.315 x 32 ) + (0.685 x 35 ) = 34.055
75 K and 500 kPa
2
150. Kand 500 kPa
3
300. Kand 50 kPa
4
600. K and 50 kPa
Submit Answer
600k as well as 50kPa since the pressure seems to be the lowest as well as the temperature is the greatest throughout this situation.
Under high temperatures and low pressures, actual gases behaved like ideal gases. such as the rule
Even though at high temperatures, the kinetic energy of such gas particles surpasses the intermolecular attractive forces, — in other words this same potential energy of something like the molecules (gaseous).
Thus the above answer i.e., "option 4" is right.
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Answer: 600K and 50kPa
Explanation:
The volume of one mole of gas at STP is 22.4 liters.
In the combustion reaction of acetylene (C2H2), 60 liters of CO2 will be produced if 60 liters of O2 is used.
To determine the volume of CO2 produced in the combustion reaction of acetylene (C2H2), we need to use stoichiometry. From the balanced equation, we can see that 2 moles of C2H2 produce 4 moles of CO2. The ratio is 2:4 or 1:2. Given that 60 liters of O2 is used, we can assume the same volume of CO2 will be produced since both gases are at STP.
Therefore, the volume of CO2 produced would be 60 liters as well.
Keywords: combustion, volume, acetylene, O2, CO2, STP
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Answer: C
Explanation:
This is basic stoichiometry
4.5 X 10^20 Atoms x (1 mole/ 6.02 X 10^23 atoms) = 7.48 X 10^-4 moles Ag
so the answer would be C.