According to the Bronsted-Lowry concept of acids and bases, a base accepts protons. Here NH₃ accepts a proton to form the conjugate acid NH₄⁺. Hence, it acts as a base.
There are various theories regarding the nature of acids and bases. According Bronsted-Lowry concept of acids and bases, acids are substances which donates a proton and bases are proton accepters.
The species which is formed by donating a proton from the acid is called conjugate base of the acid and the species which is formed after a base accepts a proton is called the conjugate acid of the base.
Consider the given reaction of ammonia with water. Here water is a proton donor and thus acts as an acid whereas ammonia accepts the proton from water forming its conjugate acid NH₄⁺. Water forms its conjugate base OH-. Therefore NH₃ acts as a base in this reaction.
To find more on Bronsted-Lewis concept, refer here:
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10.0g
22.1g
32.9g
5.6g
Answer:
22.1 g
Explanation:
The balanced reaction equation which serves as a guide in solving the problem is given as;
CaO(s) + 2NaCl(aq) ------> Na2O(s) + CaCl2(aq)
The question clearly specifies that sodium chloride is the reactant in excess. This means that calcium oxide should be used to calculate the theoretical yield of sodium oxide.
Number of moles of calcium oxide reacted = mass of calcium oxide / molar mass of calcium oxide
Molar mass of calcium oxide = 56.0774 g/mol
Mass of calcium oxide = 20.0g
Number of moles of calcium oxide = 20.0 g/ 56.0774 g/mol = 0.3566 moles
From the balanced reaction equation;
1 mole of calcium oxide produces 1 mole of sodium oxide
Therefore, 0.3566 moles of calcium oxide will produce 0.3566 moles of sodium oxide.
Mass of sodium oxide produced = number of moles × molar mass
Molar mass of sodium oxide= 61.9789 g/mol
Mass of sodium oxide = 0.3566 moles × 61.9789 g/mol
Mass of sodium oxide= 22.1 g
Answer:
22.1g
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
CaO + 2NaCl —> Na2O + CaCl2
Next, we shall determine the mass of CaO that reacted and the mass of Na2O produced from the balanced equation.
This is illustrated below:
Molar mass of CaO = 40 + 16 = 56g/mol
Mass of CaO from the balanced equation = 1 x 56 = 56g
Molar mass of Na2O = (23x2) + 16 = 62g/mol
Mass of Na2O from the balanced equation = 1 x 62 = 62g
From the balanced equation above,
56g of CaO reacted to produce 62g of Na2O.
Finally, we can determine the theoretical yield of Na2O as follow:
From the balanced equation above,
56g of CaO reacted to produce 62g of Na2O.
Therefore, 20g of CaO will react to produce = (20 x 62)/56 = 22.1g of Na2O.
Therefore, the theoretical yield of Na2O is 22.1g
C6H12O6
MgO
Na2O
SiO2
Select one:
a. KF
b. MgF2
c. NO2
d. Na2S
3.44x10^23 divided by 6.02x10^23 equals 0.571 mol Cu.
increases to 100 times the original concentration
decreases to 1/100 of the original concentration
decreases to 1/2 of the original concentration
Answer: The correct answer is 'increases to 100 times the original concentration'.
Explanation:
let the initial pH be x
The original concentration of initially present be y
...(1)
Final concentration of when pH reduced by 2 be z
...(2)
Putting the value of 'x' from (1) into (2) we get :
When pH of a solution decreases by 2.0, hydronium ion concentration of the solution increases to 100 times the original concentration
Answer:
B, is the answer
b) 1.7 x 10²⁶ atoms
c) 1.2 x 10²⁵ atoms
d) 3.0 x 10²⁴ atoms
e) 3.0 x 10²³ atoms
Can anyone explain this one?