Answer:
The specific heat of magnesium is 1.04 J/g°C.
Explanation:
Heat lost by the magnesium = Q
Mass of the magnesium = m = 62.08 g
Heat capacity of magnesium= c = ?
Initial temperature of the magnesium =
Final temperature of the magnesium= T = 35.60 °C
Heat absorbed by coffee cup calorimeter = Q'
Heat capacity of coffee cup calorimeter = C = 1.79 J/°C
Initial temperature of coffee cup calorimete = = 23.19°C
Final temperature of coffee cup calorimete = T = 35.60 °C
Heat absorbed by the water = q
Mass of water = m' = 77.81 g
Heat capacity of water = c' = 4.18 J/g°C
Initial temperature of water = = 0°C
Final temperature of water = T
According law of conservation of energy , energy lost by coffee will equal to heat required to raise temperature of water and coffee cup calorimeter.
On solving we get:
c = 1.04 J/g°C
The specific heat of magnesium is 1.04 J/g°C.
conduction
convection
radiation
liquid 1 and 2 have the same color and mass so the answer would be liquid 1 and 2
Explanation:
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Answer:
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Answer:
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Explanation:
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Answer:
0.295 mol/L
Explanation:
Given data:
Volume of solution = 3.25 L
Mass of BaBr₂ = 285 g
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of solute:
Number of moles = mass/ molar mass
Molar mass of BaBr₂ = 297.1 g/mol
Number of moles = 285 g/ 297.1 g/mol
Number of moles= 0.959 mol
Molarity:
M = 0.959 mol / 3.25 L
M = 0.295 mol/L
The question is about calculating the molarity of a solution. First, convert the given mass of solute into moles using the molar mass. Then, using the molarity formula, divide the moles of solute by the volume of the solution in liters.
In order to determine the molarity of the solution, we will divide the amount of solute (in moles) by the volume of the solution (in liters). The formula for molarity (M) is:
M = moles of solute/volume of solution in liters
First, we need to convert the mass of BaBr2 into moles. The molecular weight of BaBr2 is 297.14 g/mol. So, 285 g of BaBr2 is equal to 285/297.14 = 0.959 moles.
The volume of the solution is given as 3.25 L. So, plugging these values into the formula gives us the molarity of the solution:
M = 0.959 moles/3.25 L = 0.295 M
So, the molarity of the solution is 0.295 M.
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Answer:
All of the reactions are examples of combustion reactions.
Explanation: