(B) What is the least squares regression line
(C) According to the model in (b), for every increase of $1000 in income, the ulcer rate (per 100 population) will go down by _________ points.
Answer:
B) y = -9.98×10⁻⁵ x + 13.95
C) 0.1
Step-by-step explanation:
Using Excel, the least squares regression line, rounded to two decimal places, is y = -9.98×10⁻⁵ x + 13.95.
The slope is -9.98×10⁻⁵, so if x increases by 1000, then y changes by -9.98×10⁻² = -0.0998. Rounded to one decimal place, the ulcer rate per 100 population will go down by 0.1 points.
(b) What is the probability that it is company
Answer:
attached below
Step-by-step explanation:
The exponential function representing the bacteria population after t hours is f(t) = 2000 * e^(ln(0.5)/3 * t).
To find the exponential function that represents the size of the bacteria population after t hours, we can use the formula N = N0 * e^(kt), where N0 is the initial population, e is Euler's number (approximately 2.71828), k is the growth/decay constant, and t is the time in hours.
In this case, the initial population N0 is 2,000 and the population after 3 hours is 1,000. Plugging these values into the formula, we get:
N = 2000 * e^(3k) = 1000
Solving for k, we find k = ln(0.5)/3. Therefore, the exponential function representing the bacteria population after t hours is f(t) = 2000 * e^(ln(0.5)/3 * t).
#SPJ3
The exponential decay function representing the bacteria population after t hours is f(t) = 2000 × 0.5^(t/3), where t is the number of hours passed.
The student has observed a population of bacteria decreasing from 2,000 to 1,000 over three hours and seeks an exponential function to model the decay of the population over time, expressed as f(t). Since the population is halving every three hours, we can represent this with the function f(t) = 2000 × 0.5^(t/3), where 2000 is the initial population, 0.5 represents the halving, and t is the time in hours. The exponent (t/3) is used because the halving occurs every three hours.
#SPJ2
Answer:
total no of outcomes are '15'
outcomes are shown below.
Step-by-step explanation:
A = {1, 2, 3, 4, 5 ,6 ,7}
subsets which will include {1, 3, 5}
hence, the outcome are :
{1,2,3,5}, {1,3,4,5}, {1,3,5,6}, {1,3,5,7}, {1,2,3,5,6},{1,2,3,5,7},{1,2,3,4,5}, {1,3,4,5,6}, {1,3,4,5,7}, {1,2,3,5,7},{1,2,3,5,6}, {1,3,5,6,7},{1,2,3,4,5,6},{1,2,3,4,5,7}, {1,2,3,4,5,6,7}
so the total no of outcomes are '15'