Answer: 2.93 L
Explanation:
AI-generated answer
To find the volume occupied by 0.108 mol of helium gas at a pressure of 0.909 atm and a temperature of 306 K, we can use the ideal gas law equation:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Rearranging the equation to solve for V:
V = (nRT) / P
Plugging in the given values:
n = 0.108 mol
R = 0.0821 L·atm/(mol·K) (the ideal gas constant)
T = 306 K
P = 0.909 atm
V = (0.108 mol * 0.0821 L·atm/(mol·K) * 306 K) / 0.909 atm
Calculating this expression, we find that the volume occupied by 0.108 mol of helium gas at a pressure of 0.909 atm and a temperature of 306 K is approximately 2.93 L.
Now, let's consider the second part of the question: Would the volume be different if the gas was argon (under the same conditions)?
The volume would be the same for argon gas.
According to the ideal gas law, at the same temperature, pressure, and number of moles, the volume occupied by a gas is the same regardless of the gas's identity. Therefore, if we replaced helium gas with argon gas while keeping the same conditions of pressure, temperature, and number of moles, the volume occupied by argon gas would be the same, approximately 2.93 L.
Answer:
you need to have a question or a problem first
Answer:
the answer is d.
Explanation:
Excuse me while I go kill Thanos.
A candle placed between two plane mirrors inclined at an angle of 45 degrees will form 7 images. This is due to multiple reflections between the mirrors. The number of images depends on the angle between the mirrors.
In physics, when a candle is placed between two plane mirrors inclined at an angle of 45 degrees, 7 images will be formed. This happens due to multiple reflections between the mirrors. As per the formula for number of images n = 360/θ - 1, where θ is the angle between the mirrors, for an angle of 45 degrees, we get n = 360/45 - 1 = 7. The actual number of images can be less than this if they overlap each other.
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Which changes occur when O2(g) is added tothis system?
(1) The equilibrium shifts to the right and the concentration of PCl3(g) increases.
(2) The equilibrium shifts to the right and the concentration of PCl3(g) decreases.
(3) The equilibrium shifts to the left and the concentration of PCl3(g) increases.
(4) The equilibrium shifts to the left and the concentration of PCl3(g) decreases.
Given the data from the question, the correct answer to the question is:
The equilibrium shifts to the left and the concentration of PCl₃(g) decreases. (Option 4)
This is simply defined as a state in a chemical system where there is no observable change in the properties of the system with time.
A French scientist postulated a principle which helps us to understand a chemical system in equilibrium.
The principle states as follow:
Considering the question given above, we are concerned with O₂ (i.e concentration) being added to the reaction
2POCl₃(g) + energy <=> 2PCl₃(g) + O₂(g)
According to the principle given above, if more O₂ is added, then, PCl₃ and O₂ will react to produce more POCl₃. Thus, the equilibrium will shift to the left and also PCl₃ will reduce.
Learn more about chemical equilibrium: