Answer:
n=65th term
Step-by-step explanation:
AP:3,15,27,39......
From the AP
a=3
a+d=15
a+2d=27
3+d=15 (1)
3+2d=27 (2)
Subtract (1) from (2)
We have,
2d-d=27-15
d=12
54th term=a+(n-1)d
=3+(54-1)12
=3+(53)12
=3+636
=639
The term is 132 more than the 54th term
132+54th term
=132+639
=771
Find the term
771=a+(n-1)d
771=3+(n-1)12
771-3=12n-12
768=12n-12
768+12=12n
780=12n
n=780/12
=65
n=12
The term which is 132 more than the 54th term is the 65th term
$439
$422.95
$385.89
Answer:
The length of the case is 24 cm and its width is 17cm.
Step-by-step explanation:
The Length of a standard jewel case is 7cm more than its width.
Let the length be represented by L and the width be represented by W, this means that:
L = 7 + W
The area of the rectangular top of the case is 408cm². The area od a rectangle is given as:
A = L * W
Since L = 7 + W:
A = (7 + W) * W = 7W + W²
The area is 408 cm², hence:
408 = 7W + W²
Solving this as a quadratic equation:
=> W² + 7W - 408 = 0
W² + 24W - 17W - 408 = 0
W(W + 24) - 17(W + 24) = 0
(W - 17) (W + 24) = 0
=> W = 17cm or -24 cm
Since width cannot be negative, the width of the case is 17 cm.
Hence, the length, L, is:
L = 7 + 17 = 24cm.
The length of the case is 24 cm and its width is 17cm.
Answer:
3x^3+6x^+8x+24+47/x-2
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
How many problems of each point value are on the test?