A bag contains 99 red marbles and 99 blue marbles. Taking two marbles out of the bag, you: • put a red marble in the bag if the two marbles you drew are the same color (both red or both
blue), and
• put a blue marble in the bag if the two marbles you drew are different colors.
Repeat this step (reducing the number of marbles in the bag by one each time) until only one
marble is left in the bag. What is the color of that marble?

The final marble left in the bag will be red.

Let, analyze the process step by step:

Initially, the bag contains 99 red marbles and 99 blue marbles.

When you take two marbles out of the bag, there are two possibilities: either you get two red marbles or two blue marbles, or you get one red and one blue marble.

a. If you get two marbles of the same color (both red or both blue), you put a red marble in the bag.

b. If you get one red and one blue marble, you put a blue marble in the bag.

After putting a marble back in the bag, you have one less marble in the bag.

You repeat this process, reducing the number of marbles in the bag by one each time, until only one marble is left in the bag.

Now, let's think about the outcomes at each step:

If the bag contains an odd number of marbles (99 red + 99 blue = 198), the final marble will be red because at each step, you are adding a red marble back to the bag.

If the bag contains an even number of marbles (e.g., 100 red + 100 blue = 200), the final marble will be blue because at each step, you are adding a blue marble back to the bag.

In this case, the bag contains 99 red marbles and 99 blue marbles, which is an odd number (198 marbles).

Therefore, the final marble left in the bag will be red.

To learn more on probability click:

brainly.com/question/11234923

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