When the temperature of a gas in a balloon is reduced by half, the average kinetic energy of the particles isa. reduced by half.
b. reduced by one-quarter.
c. increased by half.
d. increased by one-quarter.

Answers

Answer 1

Answer: according to KE = (3/2)kT

reducing temperature, in KELVIN, by half, average KE is reduced by half.

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For a winter fair, some students decide to build 30.0 kg wooden pull carts on sled skids. If two 90.0 kg passengers get in, how much force will the puller have to exert to move a pull cart? The coefficient of maximum static friction between the sled skids and the road is 0.15
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What are the four forms that water takes when it returns to earth from the clouds?

Answers

Precipitation from the sky to the earth can come in several forms. Four types are:1) Rain2) Snow3) Sleet (think of a more liquidity slushy snow)4) Hail (pretty much solid chunks of ice)

A worker kicks a flat rock lying on a roof. The rock slides up the incline 10.0 m to the apex of the roof, and flies off the roof as a projectile. What maximum height (in m) does the rock attain? Assume air resistance is negligible, vi = 15.0 m/s, μk = 0.425, and that the roof makes an angle of θ = 42.0° with the horizontal. (Assume the worker is standing at y = 0 when the rock is kicked.)

Answers

The maximum height that the rock attains is : 7.42 m

Given data :

Vi = 15.0 m/s

uk = 0.425

angle made by roof ( θ ) = 42.0°

Calculating the maximum height reached by the rock

First step : calculate the deceleration of the rock

a = g*sinθ + uk * g * cosθ

= 9.8 * sin 42° + 0.425 * 9.8 * cos 42°

= 9.65 m/s²

Applying motion formula

v² = u² + 2as

= 15² - 2 * 9.65 * 10

v = 5.66 m/s

Initial height attained ( h₁ ) = 10 sin θ

= 10 * sin 45°

= 6.69 m

considering vertical height

V (y) = v sin θ

= 5.66 sin 42

= 3.79 m/s

Next step : Calculate height ( h₂ )

v² = u² + 2 a s

0 = 3.79² - 2 * 9.8 * h₂

therefore : h₂ = 0.73 m

The maximum height attained by the rock ( H ) = h₁ + h₂

= 6.69 + 0.73 = 7.42 m

Hence we can conclude thatThe maximum height that the rock attains is : 7.42 m

Learn more about projectile : brainly.com/question/24216590

Answer:

h = 7.42 m

Explanation:

deceleration of the rock

$a = g sin \theta + \mu_kgcos \theta$

$a = 9.8 sin 42^0+0.425* 9.8 * cos 42^0$

a = 9.65 m/s²

using formula

v² = u² + 2 a s

v² = 15² - 2×9.65 × 10

v = 5.66 m/s

the height attained is

h₁ = 10 sin θ

= 10 sin 42

= 6.69 m

now with vertical velocity it will reach to the height h₂

v y = v sin θ

= 5.66 sin 42

= 3.79 m/s

height is

v² = u² + 2 a s

0 = 3.79² - 2 × 9.8 ×h₂

h₂ = 0.73 m

the maximum height is

h = h₁ + h₂

= 6.69 + 0.73

h = 7.42 m

Two identical beakers with the same volume of water are placed on each pan of a double-pan balance. A steel ball is suspended from a string and submerged in the water of one of the containers. A hollow plastic ball of the same volume is submerged in the water of the other container and fastened to the bottom of the beaker by a string. Will the balance move, and if so in which direction?

Answers

Answer:

The pan having beakers with steel ball will go down.

Explanation:

Both steel ball and plastic ball will experience buoyant force in upward direction . These forces will have same magnitude because they displace same volume of water. Both of them experience reaction force of buoyant force acting in downward direction which will try to lower the pan equally. But in case of plastic ball which is tied to the bottom , the tense string will apply a force equal to buoyant force in upward direction on the bottom of the beaker.

This force will balance the reaction buoyant force acting on the bottom of beaker in downward direction . Hence this pan will remain balanced but the other pan will go down.

A 17,000-kg airplane lands with a speed of 82 m/s on a stationary aircraft carrier deck that is 115 m long. find the work done by nonconservative forces in stopping the plane

Answers

Final answer:

The work done by nonconservative forces in stopping the 17,000-kilogram airplane landing at a speed of 82 m/s is 57,062,000 Joules. This is calculated by the change in kinetic energy of the airplane when it lands and comes to a stop.

Explanation:

The question refers to the concept of work-energy theorem in Physics, especially involving non-conservative forces. The airplane is initially moving and finally comes to rest. Its initial kinetic energy (KE) gets transferred to work done by nonconservative forces, which in this scenario includes friction due to the aircraft carrier deck and air resistance.

The initial kinetic energy of the plane is calculated using the formula 1/2 * m * v^2 where 'm' is the mass of the plane and 'v' is its speed. So, the initial kinetic energy of the plane is 1/2 * 17,000 kg * (82 m/s)^2 = 57,062,000 Joules. When the plane comes to rest, its final kinetic energy is 0. As per the work-energy theorem, the work done by nonconservative forces is equal to the change in the kinetic energy. Therefore, the work done by nonconservative forces in stopping the plane = Initial KE - Final KE = 57,062,000 Joules - 0 = 57,062,000 Joules.

Learn more about Work-energy theorem here:

brainly.com/question/30560150

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In which situation is no work being done?A. No force is applied
B. The force does not result in displacement
C. The force and displacement are perpendicular to each other
D. The force and displacement are in the same direction

Answers

Answer:

Work is said to occur when a force is able to cause displacement of an object in the direction of the applied force. It is given by the scalar product of force and displacement.

W = F.s = F s cos θ

Thus, no work is being done when no force is applied ( ∵ F = 0, W = 0) or the force does not result into displacement (∵ s = 0, F = 0) or when the force and displacement are perpendicular to each other (∵ θ =0, cos θ =0, W =0).

Answer: D. The force and displacement are in the same direction

Explanation: The guy above me is trying to hard to put information into his answer...

A car climbs 10.0 kilometers up a hill that inclines 8.0 degrees. What is the car's vertical displacement?