Some hypothetical alloy is composed of 12.5 wt% of metal A and 87.5 wt% of metal B. If the densities of metals A and B are 4.27 and 6.35 g/cm3, respectively, and their respective atomic weights are 61.4 and 125.7 g/mol, determine whether the crystal structure for this alloy is simple cubic, face-centered cubic, or body-centered cubic. Assume a unit cell edge length of 0.395 nm.

Answers

Answer 1

Answer:

The number of atoms in the unit cell of hypothetical alloy composed of metal A and B is 2 so the crystal structure is body-centered cubic.

What is crystal structure?

The crystal structure is the order of the atom arrangement in a repeating way. types of crystal structure are-

Simple cubic-In this arrangement, one atom is placed at each corner of the unit cell.
Face-centered cubic-In this arrangement, one atom is placed at each corner of the unit cell and one atom is placed at each face of the unit cell.
Body-centered cubic-In this arrangement, one atom is placed at each corner of the unit cell and one atom is placed at center of the unit cell.

Number of atom can be find out with the following formula,

$n=(N\rho)/(m)[\tex]Here, (m) is the mass of the object and (N) is Avogadro's number.Given information-Hypothetical alloy is composed with metal A of 12.5 wt%.Hypothetical alloy is composed with metal B of 87.5 wt%.Densities of metals A and B are 4.27 and 6.35 g/cm 3,Atomic weights of A and B are 61.4and 125.7 g/mol,The density of the alloy is,[tex]\rho=(1)/((12.5)/(4.27)+(87.5)/(6.35))*100=5.98[\tex]Similarly the mass of the alloy is,[tex]m=(1)/((12.5)/(61.4)+(87.5)/(125.7))*100=111.15[\tex]As the mass and the density of the alloy has been obtained and the Avogadro's number is 6.023*10²³.Put the value in the above equation to find the number of atom, we get,[tex]n=2$

Thus the number of atoms in the unit cell is 2. The crystal structure is body-centered cubic.

Learn more about the crystal structure here;

brainly.com/question/10816130

Answer 2

Answer:

Answer:

The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

Explanation:

Given that,

Weight of metal A = 12.5%

Weight of metal B = 87.5%

Length of unit cell = 0.395 nm

Density of A = 4.27 g/cm³

Density of B= 6.35 g/cm³

Weight of A = 61.4 g/mol

Weight of B = 125.7 g/mol

We need to calculate the density of the alloy

Using formula of density

$\rho=n*(m)/(V_(c)* N_(A))$

$n=(\rho*V_(c)* N)/(m)$ ....(I)

Where, n = number of atoms per unit cells

m = Mass of the alloy

V=Volume of the unit cell

N = Avogadro number

We calculate the density of alloy

$\rho=(1)/((12.5)/(4.27)+(87.5)/(6.35))*100$

$\rho=5.98$

We calculate the mass of the alloy

$m=(1)/((12.5)/(61.4)+(87.5)/(125.7))*100$

$m=111.15$

Put the value into the equation (I)

$n=(5.9855*(0.395*10^(-9)*10^(2))^3*6.023*10^(23))/(111.15)$

$n=1.99\approx 2\ atoms/cell$

Hence, The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

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When celery is placed in a glass of pure water the solution inside its cells is _____ compared to the water.?

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The correct answer to the question above is hypertonic. When celery is being placed in a glass of pure water, the solution inside its cells is going to appear as hypertonic compared to the water. This means that the cells inside has a higher concentration than outside.

a ball has mass of 0.1 kg and an initial velocity of 20 m/s the ball is given an acceleration of 30 m/s^2 for 5s what is the net force on the ball during acceleration

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Does your body get all its energy from the Sun

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An electromagnetic wave traveling through a vacuum has a wavelength of .15 meter. What is the period of this electromagnetic wave?

Answers

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While standing on a balcony a child drops a penny. The penny lands on the ground floor 1.5 s later. How fast was the penny traveling vertically when it struck the ground floor? *The height of the balcony is 11.025 meters

Answers

Answer:

14.7 m/s.

Explanation:

From the question given above, the following data were obtained:

Time (t) = 1.5 s

Acceleration due to gravity (g) = 9.8 m/s².

Height = 11.025 m

Final velocity (v) = 0 m/s

Initial velocity (u) =?

We, can obtain the initial velocity of the penny as follow:

H = ½(v + u) t

11.025 = ½ (0 + u) × 1.5

11.025 = ½ × u × 1.5

11.025 = u × 0.75

Divide both side by 0.75

u = 11.025/0.75

u = 14.7 m/s

Therefore, the penny was travelling at 14.7 m/s before hitting the ground.

A sled with rider having a combined mass of 110 kg travels over the perfectly smooth icy hill shown in the accompanying figure. How far does the sled land from the foot of the cliff?

Answers

The sled land is "25.531 m" far from the foot of the cliff.

According to the question,

The velocity of the top = $V_t$

then,

→ $0.5 \ Vt^2-0.5 \ Vi^2 = -mgh$

→ $0.5 \ Vt^2 = 0.5 \ Vi^2- 9.8* 11$

→ $0.5 \ Vt^2 = 0.5 \ Vi^2- 107.8$

→ $=17.04 \ m/sec$

Now,

The projectile motion in horizontal direction,

→ $S_y = 11 = ut-0.5 \ gt^2$

$= 0-0.5* 9.8 \ t^2$

or,

→ $S_x = 17.04* 1.498$

$= 25.53 \ m$

Thus the above answer is the correct one.

Learn more:

brainly.com/question/13027204

Find the speed the sled has at the top of the hill from the law of conservation of mechanical energy. Equate the kinetic energy at the bottom of the hill to the kinetic plus potential energy at the top :

0.5mv₀² = 0.5mv² + mgh
v = √[v₀² - 2gh]
= √[(22.5m/s)² - (2 x 9.80m/s² x 11.0m)]
= 17.0m/s

From the time independent kinematics equation, find the vertical component of the sleds final velocity (note that the vertical component of the sleds initial velocity is zero) :

v² = v₀² + 2gΔy
= 0 + 2(-9.80m/s²)(-11.0m)
= -14.7m/s (select the neg root, because motion is downward)

With this you can find the time vertically which is the same horizontally :

v = v₀ + gt
t = (v - v₀) / g
= (-14.7m/s - 0) / -9.80m/s²
= 1.50s

Now, the horizontal distance is :

Δx = (v₀ + v)t / 2
= (17.0m/s + 17.0m/s)1.50s / 2
= 25.5m

tell me if you need more help :)

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