Answer:
True
Explanation:
In a collision between two objects, both objects experience forces that are equal in magnitude and opposite in direction. Such forces often cause one object to speed up (gain momentum) and the other object to slow down (lose momentum).
With what minimum horizontal velocity must the cliff divers leave the top of the cliff if they are to miss the rock?
Answer in units of $m / s$.
Answer:
To solve this problem, we can use the kinematic equation for horizontal motion, which relates the initial velocity ($v_{0}$), final velocity ($v_{f}$), acceleration ($a$), and displacement ($d$) of an object:
$d = v_{0} t + \frac{1}{2}at^{2}$
In this case, we want to find the minimum initial velocity ($v_{0}$) that the divers must have to clear the rock. To do this, we can assume that the divers just graze the rock at the start of their trajectory, so the displacement in the horizontal direction is equal to the distance from the cliff to the rock ($d = 9.34 m$). We also know that the acceleration in the horizontal direction is zero, so the only force acting on the divers is gravity in the vertical direction, which gives an acceleration of $a = 9.8 m/s^{2}$.
At the instant the divers leave the cliff, they have zero horizontal velocity, so $v_{0} = 0$. We can use the equation above to solve for the time it takes for the divers to fall from the cliff to the level of the rock:
$d = \frac{1}{2}at^{2} \Rightarrow t = \sqrt{\frac{2d}{a}}$
Plugging in the numbers, we get:
$t = \sqrt{\frac{2(9.34 m)}{9.8 m/s^{2}}} \approx 1.44 s$
Since the cliff divers want to clear the rock, they need to travel a horizontal distance of at least $9.34 m$ during this time. We can use the equation for horizontal motion again to solve for the minimum initial velocity:
$d = v_{0}t \Rightarrow v_{0} = \frac{d}{t} = \frac{9.34 m}{1.44 s} \approx 6.49 m/s$
Therefore, the minimum horizontal velocity that the cliff divers must have to clear the rock is approximately $6.49 m/s$.
At certain altitude, the temperature of air decrease, The air becomes saturated and water vapour molecules starts condensing.
As the altitude of air increase, the atmospheric pressure decrease due to which the temperature of the air decrease. The water molecules in the atmosphere start condensing, which saturate the air (that is air can no hold water molecules), due to which the water vapour molecules starts condensing and falls on the earth in the form of rain.
Given:
V1 = 4m3
T1 = 290k
P1 = 475 kpa = 475000 Pa
V2 = 6.5m3
T2 = 277K
Required:
P
Solution:
n = PV/RT
n = (475000 Pa)(4m3) / (8.314 Pa-m3/mol-K)(290k)
n = 788 moles
P = nRT/V
P = (788 moles)(8.314 Pa-m3/mol-K)(277K)/(6.5m3)
P = 279,204 Pa or 279 kPa
Answer:
True.
This is because, from the information provided so far, it could be concluded that, the policy makers don't have any single idea of what they are doing regarding to the economy.
This could be seen in the series of poor performance of the economic indicators as shown which has lead to poor economic growth in our country.
Explanation:
B).The Earth is Round
C).Force of Gravity Between 2 objects Decreases with Distance
D).Planets Move in circles
That is false. I just took the test and it is not the wavelength. The correct answer is antinode NOT wavelength.