What is the area of this figure?

Answers

Answer 1

Answer: Each little square is 1 inch high and 1 inch wide, so
the area of each little square is 1 square inch.

The bug figure is made of 23 little squares, so the area
of the big figure is 23 square inches.

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Use the discriminant to determine the number and type of solutions to the quadratic equation. Show all work for full credit! 2+ 8= 13

Answers

Answer:

The equation has two different real solutions

Step-by-step explanation:

The discriminant of the quadratic equation ax² + bx + c = 0 is Δ = b² - 4ac, it used to find the number and type of solutions

Δ > 0, means two different real solutions
Δ = 0, means one real solution
Δ < 0, means no real solutions

∵ The equation is a² + 8a = 13

- Put it in the form ax² + bx + c = 0

- Subtract 13 from both sides

∴ a² + 8a - 13 = 0

∴ The coefficient of a² = 1, the coefficient of a = 8 and the

numerical term = -13

∵ Δ = (coefficient of a)² - 4(coefficient of a²)(numerical term)

∴ Δ = (8)² - 4(1)(-13)

∴ Δ = 64 + 52

∴ Δ = 116

∵ Δ > 0

∴ The equation has two different real solutions

What is the area of a figure with vertices(1,1), (8,1) , and (5,5)?

Answers

It will be a triangle
Calculating sides of this triangle
A(1,1)
B(8,1)
C(5,5)
side a-AB= $\sqrt{(8-1)^(2)+( 1-1)^(2) ) }= \sqrt{ 7^(2) }=7$
side b-AC= $\sqrt{(5-1)^(2)+( 5-1)^(2) ) }= \sqrt{ 4^(2)+4^(2) }=[tex] √(36)$ =6 [/tex]
side c-BC= $\sqrt{(5-8)^(2)+( 5-1)^(2) ) }= \sqrt{ (-3)^(2)+4^(2) }=[tex] √(25)$ =5 [/tex]
Area of the triangle from Herone formula:
A= $√(p(p-a)(p-b)(p-c))$
p= $(1)/(2)(a+b+c)$ = $(1)/(2)(7+6+5)$ =9
A= $√(9(9-7)(9-6)(9-5))$ = $√(9*2*3*4)$ = $√(216)$
Area is $√(216)$

One half Of a number added to two thirds Of The number Is 21 . Find The number.

Answers

The number would be 18.
Half of 18 = 9
Two thirds of 18 = 12
9 + 12 = 21

18. 1/2 of 18 is 9. 1/3 is 6. 6+6+9 = 21

In January, a bookstore sells 450 books, but in February, it sells only 300 books. What is the percent of change from January to February?66.7%
-33.3%
50%
-50%

Answers

Answer:

- 33.33%

Step-by-step explanation:

Given,

The number of books sold on January = 450,

While, the number of books sold on February = 300

Thus, the percent of change from January to February = $\frac{\text{books sold on February-books sold on January}}{\text{books sold on January}}* 100$