The cost of producing is $4760.
The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units.
For example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.
12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.
As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.
This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.
Given:
q = min{x, y} where x and y are the amounts of two factors used.
As, it depend on the two factor whose value given as
x= 18 and y= 10
So, for 170 Computers the cost of producing is
= 170 (18+10)
= 170 x 28
= 4760
Hence, the cost of producing is $4760.
Learn more about Unitary method here:
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Answer:
180
Step-by-step explanation:
X and y is used so 10 times 18 is 180
5x – 4y= -6
pls help me
Answer:
Hi! The correct answer is (-2,-1)!
Step-by-step explanation:
~Add the equations in order to solve for the first variable, Plug this value into the other equations in order to solve for the remaining variables~
Answer:
20%?
Step-by-step explanation:
Tyrese has used 7 out of his 35 initial tickets. This translates to a 20% decrease in the number of tickets he has.
Tyrese started with 35 tickets and now has 28 tickets. To find the percent of decrease in the number of tickets, first, we need to find how many tickets he has used. He has used 35 - 28 = 7 tickets.
Next, we find the percentage decrease using the formula:
Percent Decrease = (Decrease/Original amount) x 100%
So in this case, the decrease is 7 tickets, and the original amount is 35 tickets.
Percent Decrease = (7/35) x 100% = 20%.
Therefore, the percent of decrease in the number of tickets that Tyrese has is 20%.
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B) 0.12
C) 0.0036
D) 0.0030
Answer:
Option C - 0.0036
Step-by-step explanation:
Given : The probability that a new spark plug is defective is 0.06. You need two new spark plugs.
To find : What is the probability that both spark plugs you buy are defective?
Solution :
Probability of one spark plug being defective is 0.06
We have to find for two defective spark plugs.
This situation is a compound event in which there is more than one possible outcome.
So, The Probability of two spark plug being defective is
Therefore, The Probability of two spark plug being defective is 0.0036.
So, Option C is correct.
–0.191
0.191
0.872
Answer:
the answer is -0.872
Step-by-step explanation:
Answer:
I don't know
Step-by-step explanation:
I don't know what is with-draw, interest rates