MATHEMATICS COLLEGE

Fortune is distributed as follows : the 1st $5 million to the dog,1/2 the remainder to the teacher,$50 million to hospital,of the remaining 50% to wife,40% to daughter,9% to lawyer,1% to son... son is getting $10,000-How much was the fortune?
- who gets the most money and how much?
-​

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

Working backward, $10,000 is 1% of $1,000,000, so that is the amount of the "remaining."

Apparently that is what is left of 1/2 the "remainder" after $50 million goes to the hospital. So 1/2 the "remainder" is $51M, which is also the amount the teacher gets. Those came out of a total of 2×$51M = $102M, which is the amount after the dog's $5M share.

The fortune was $107 million. The shares were ...

  • dog: $5 M
  • teacher: $51 M (the most money)
  • hospital: $50 M
  • wife: $500,000
  • daughter: $400,000
  • lawyer: $90,000
  • son: $10,000

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Please help someone

Which option correctly shows 4 6 as a division expression? A. 4 ÷ 1 6 B. 6 ÷ 1 4 C. 4 ÷ 6 D. 6 ÷ 4

Answers

The answer is to the problem is d

Answer: D

Step-by-step explanation:

I took the quiz

When a number is increased by 26, the result is tripled. Then the result is increased by 72. If the final result is 1/2 of the number, what is the value of this number?

Answers

Answer:

-60.

Step-by-step explanation:

Let the unknown number be x.

Number is increased by 26 = x+26

Then result is tripled = 3(x+26)

Then the result is increased by 72 = 3(x+26)+72

Final result is (1)/(2) of the number = (1)/(2)x

3(x+26)+72=(x)/(2)

3x+78+72=(x)/(2)

3x+150=(x)/(2)

Isolate variable terms.

3x-(x)/(2)=-150

(6x-x)/(2)=-150

Multiply both sides by 2.

5x=-300

Divide both sides by 5.

x=-(300)/(5)

x=-60

Therefore, the required number is -60.

Y=3x+4. Find an equation of a line that is:parallel to the given line

y=3x+4. Find an equation of a line that is:

perpendicular to the given line

PLZ ANSWER FAST 50 POINTS

Answers

Answer:

Parallel: y = 3x +b, where b ≠ 4

Perpendicular: y = -1/3x + b

Step-by-step explanation:

Parallel Lines have the same slope but different y-intercepts.

Perpendicular Lines have a negative reciprocal in slope.

Solve this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7 ​

Answers

Answer:

Solving this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7 ​we get x=2 and y=-3

Solution set = {2,-3}

Step-by-step explanation:

We need to solve this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7 ​

let:

3x-2y=12--eq(1)\nx+3y=-7 --eq(2)

Finding value of x from equation 2 and putting in eq(1)

From \ eq(2)\nx+3y=-7\nx=-7-3y

Putting value of x in eq(1)

3x-2y=12\nPut \ x=-7-3y\n3(-7-3y)-2y=12\nSolving\n-21-9y-2y=12\n-11y=12+21\n-11y=33\ny=(33)/(-11)\ny=-3

So, we get y=-3

Now put value of y in equation 2 to find value of x

x+3y=-7\nx+3(-3)=-7\nx-9=-7\nx=-7+9\nx=2

So, we get value of x =2

So, solving this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7 ​we get x=2 and y=-3

Solution set = {2,-3}

These triangles are similar. What is the value for it?

Answers

Answer:

The vault of h is 10

Step-by-step explanation:

Since the whole triangle is 27 and the one side is 9 we know the other side must be 18. You multiply by 2 to get get from 9. That means they are similar and you just multiply 5 by 2 to get h=10.

Product of 6 and 6r and the product of 8s and 4

Answers

The product of the numbers are 36r and 32s.

What is product?

When we multiply two numbers the resultant is called their product.

Given that, what can be the products of 6 and 6r and 8s and 4

a) 6 and 6r =

We can write it as =

6 x 6 x r

now multiply the numeric parts,

36 x r

= 36r

Similarly,

b) 8s and 4 =

We can write it as,

8 x s x 4

= 8 x 4 x s

now multiply the numeric parts,

= 32 x s

= 32s

Hence, the products are 36r and 32s.

Learn more about products, click;

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Product tells us we’re going to multiply.

6 x 6r = 36r

8s x 4 = 32s

We don’t have a number value to substitute in for r or s, so we just leave those variables as they are.

LMK if you have questions
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