What is the slope of the line that contains the points (-1,-1) and (3, 15)?O A.
1
4
B. 4
O C. -
4
D. -4

Answers

Answer 1

Answer:

Answer:

its b

Step-by-step explanation:

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Find the value of z such that 0.11 of the area lies to the right of z. Round your answer to two decimal places.

Jacqueline buys 2 fourths yard of green ribbon and 1 fourths yard of pink ribbon. How many yards of ribbon does she buy?

Answers

Answer:

3/4

Step-by-step explanation:

Please Help Me Thanks!

Answers

Answer:

No solution

Step-by-step explanation:

add 3 both side

\sqrt{x-4}=-2

Find the slope of the line passing through each of the following pairs of points. (−3, 9), (−3, −5

Answers

The formula of a slope:

$m=(y_2-y_1)/(x_2-x_1)$

We have the points (-3, 9) and (-3, -5). Substitute:

$m=(-5-9)/(-3-(-3))=(-14)/(-3+3)=(-14)/(0)\qquad\large{!!!!}\n\n\large\boxed{\text{Division by 0}}!!!$

Conclusion: The slope is not exist.

Given line is a horizontal line. Horizontal line has not a slope.

Answer:

Undefined Slope

Step-by-step explanation:

Well, we can first do (-5-9)÷[-3-(-3)].

We get -14/0.

We know anythingn divided by zero is impossible or undefined, so the answer to this is just undefined. If you can't enter it in your homework portal, then ask your teacher. Please don't report this, as I'm correct. Thank you!

Consider three boxes with numbered balls in them. Box A con- tains six balls numbered 1, . . . , 6. Box B contains twelve balls numbered 1, . . . , 12. Finally, box C contains four balls numbered 1, . . . , 4. One ball is selected from each urn uniformly at random. (a) What is the probability that the ball chosen from box A is labeled 1 if exactly two balls numbered 1 were selected
(b) What is the probability that the ball chosen from box B is 12 if the arithmetic mean of the three balls selected is exactly 7?

Answers

Answer:

a) 0.73684

b) 2/3

Step-by-step explanation:

part a)

$P ( A is 1 / exactly two balls are 1) = (P ( A is 1 and that exactly two balls are 1))/(P (Exactly two balls are one))$

Using conditional probability as above:

(A,B,C)

Cases for numerator when:

P( A is 1 and exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1)

= $((1)/(6)* (11)/(12)*(1)/(4)) + ((1)/(6)*(1)/(12)*(3)/(4)) = 0.048611111$

Cases for denominator when:

P( Exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1) + P(not 1, 1 , 1)

$= ((1)/(6)* (11)/(12)*(1)/(4)) + ((1)/(6)*(1)/(12)*(3)/(4)) + ((5)/(6)*(1)/(12)*(1)/(4))= 0.0659722222$

Hence,

$P ( A is 1 / exactly two balls are 1) = (P ( A is 1 and that exactly two balls are 1))/(P (Exactly two balls are one)) = (0.048611111)/(0.06597222) \n\n= 0.73684$

Part b

$P ( B = 12 / A+B+C = 21) = (P ( B = 12 and A+B+C = 21))/(P (A+B+C = 21))$

Cases for denominator when:

P ( A + B + C = 21) = P(5,12,4) + P(6,11,4) + P(6,12,3)

$= 3*P(5,12,4 ) =3* (1)/(6)*(1)/(12)*(1)/(4)\n\n= (1)/(96)$

Cases for numerator when:

P (B = 12 & A + B + C = 21) = P(5,12,4) + P(6,12,3)

$= 2*P(5,12,4 ) =2* (1)/(6)*(1)/(12)*(1)/(4)\n\n= (1)/(144)$

Hence,

$P ( B = 12 / A+B+C = 21) = ((1)/(144) )/((1)/(96) )\n\n= (2)/(3)$

A 224 cm rope is cut so that one part is 3/4 of the other. How long is the shorter rope? The longer rope?

Answers

Given that:

Length of a rope = 224 cm

Rope is cut so that one part is 3/4 of the other.

Solution:

Let one part of a rope be x cm.

So other part of the rope is $(3)/(4)x$ .

Total length $=x+(3)/(4)x$

Now,

$x+(3)/(4)x=224$

$(4x+3x)/(4)=224$

Multiply both sides by 4.

$7x=896$

Divide both sides by 7.

$x=(896)/(7)$

$x=128$

The value of one part 128 cm.

Second part $=(3)/(4)x$

$=(3)/(4)* 128$

$=3* 32$

$=96$

Therefore, the length of shorter rope is 96 cm and the length of longer rope is 128 cm.

In a survey of 1016 ?adults, a polling agency? asked, "When you? retire, do you think you will have enough money to live comfortably or not. Of the 1016 ?surveyed, 535 stated that they were worried about having enough money to live comfortably in retirement. Construct a 99?% confidence interval for the proportion of adults who are worried about having enough money to live comfortably in retirement.A. There is a 99?% probability that the true proportion of worried adults is between ___ and ___.

B. 99?% of the population lies in the interval between ___ and ___.

C. There is 99?% confidence that the proportion of worried adults is between ___ and ___.

Answers

Answer:

C. There is 99% confidence that the proportion of worried adults is between 0.487 and 0.567

Step-by-step explanation:

1) Data given and notation

n=1016 represent the random sample taken

X=535 represent the people stated that they were worried about having enough money to live comfortably in retirement

$\hat p=(535)/(1016)=0.527$ estimated proportion of people stated that they were worried about having enough money to live comfortably in retirement

$\alpha=0.01$ represent the significance level

Confidence =0.99 or 99%

z would represent the statistic

p= population proportion of people stated that they were worried about having enough money to live comfortably in retirement

2) Confidence interval

The confidence interval would be given by this formula

$\hat p \pm z_(\alpha/2) \sqrt{(\hat p(1-\hat p))/(n)}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_(\alpha/2)=2.58$

And replacing into the confidence interval formula we got:

$0.527 - 2.58 \sqrt{(0.527(1-0.527))/(1016)}=0.487$

$0.527 + 2.58 \sqrt{(0.527(1-0.527))/(1016)}=0.567$

And the 99% confidence interval would be given (0.487;0.567).

There is 99% confidence that the proportion of worried adults is between 0.487 and 0.567

Final answer:

To build a 99% confidence interval, we first calculate our sample proportion by dividing the number of such instances by the total sample size. Next, we determine the standard error of the proportion, then our margin of error by multiplying the standard error by the Z value of the selected confidence level. Lastly, we determine the confidence interval by adding and subtracting the margin of error from the sample proportion.

Explanation:

To construct a 99% confidence interval for the proportion of adults worried about having enough money to live comfortably in retirement, we will utilize statistical methods and proportions. First, we must calculate the sample proportion. The sample proportion (p) is equal to 535 (the number who are worried) divided by 1016 (the total number of adults surveyed).

Then, we find the standard error of the proportion which we get by multiplying the square root of ((p*(1-p))/n) where n is the number of adults sampled. The margin of error is found using the Z value corresponding to the desired confidence level, in this case, 99%. Multiply the standard error by this Z value. Lastly, we construct the confidence interval by taking the sample proportion (p) ± the margin of error.

The result will give you the 99% confidence interval - meaning we are 99% confident that the true proportion of adults who are worried about having enough money to live comfortably in retirement lies within this interval.