Answer:
Option E, two-proportion z test should be used to determine whether these data provide sufficient evidence to reject the hypothesis that the proportion of shoppers at the suburban mall who had been to a movie in the past month is the same as the proportion of shoppers in the large downtown shopping area who had been to a movie in the past month
Step-by-step explanation:
The complete question is
In a random sample of 60 shoppers chosen from the shoppers at a large suburban mall, 36 indicated that they had been to a movie in the past
month. In an independent random sample of 50 shoppers chosen from the shoppers in a large downtown shopping area, 31 indicated that
they had been to a movie in the past month. What significance test should be used to determine whether these data provide sufficient
evidence to reject the hypothesis that the proportion of shoppers at the suburban mall who had been to a movie in the past month is the same
as the proportion of shoppers in a large downtown shopping area who had been to a movie in the past month?
A one-proportion z interval B two-proportion z interval
B two-proportion z interval
C two-sample t test D one-proportion z test
D one-proportion z test
E two-proportion z test
Solution
Two proportion z test is used to compare two proportions. In this test the null hypothesis is that the two proportions are equal and the alternate hypothesis is that the proportions are not the same. The random sample of populations serve as two proportions.
Hence, option E is the best choice of answer
Answer here
Answer:
X>-3
Step-by-step explanation:
Hope I helped
Do u want the steps ?
Answer: x > -3
Step-by-step explanation: -5(4x + 7) <25
-20x - 35 < 25
-20x -35 + 35 < 25 + 35
-20x/20 < 60/20
x > -3
Answer:
?=8
Step-by-step explanation:
I substituted the ? for x
-3=x-11
first we want to isolate the x to do that, you have to find a way to move -11 to the other side. Well, x+0=x right? So all we have to do is find a way to go from -11 to 0! In this case you add 11 to both sides. This is very important so don't forget.
-3=x-11
+11 +11
-3+11=8
x=8
If you check your work, this should also go back in perfectly.
-3=8-11
or
-3=-11+8
I hope this helps!
Have a good day!
Answer:
(3,7)
Step-by-step explanation:
(7,4)
Moving left and right relates to x
Moving up and down relates to y
When you move to the left, you subtract
When you move to the right, you add
When moving up, you add
When moving down you subtract
X= 7-4 = 3
x=3
Y= 4+3 = 7
y = 7
(3,7)
(17x - 8)
For given question, x = 4
"It is a triangle with all three sides of equal length and each angle measures 60°."
"It is a statement which consists of equal symbol between two mathematical expressions."
From given figure,
we can observe that the all sides of the triangle are equal.
This means, the given triangle is an equilateral triangle.
So, each angle of triangle measures 60°.
So, we get an equation,
⇒ 17x - 8 = 60°
⇒ 17x = 60 + 8
⇒ 17x = 68
⇒ x = 68/17
⇒ x = 4
Learn more about an equilateral triangle here:
#SPJ2
Answer:x=4
Step-by-step explanation:
This triangle is an equilateral triangle with all angles equal.
Sum of angles in a triangle=180
17x-8+17x-8+17x-8=180
Collect like terms
17x+17x+17x-8-8-8=180
51x-24=180
51x=180+24
51x=204
Divide both sides by 51
51x/51=204/51
x=4
Answer:
The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.
Step-by-step explanation:
Using Bayes' Theorem
P(A|B) =
where
P(B|A) is probability of event B given event A
P(B|a) is probability of event B not given event A
and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.
For this problem,
Let P(B1) = Probability of machine B1 = 0.3
P(B2) = Probability of machine B2 = 0.2
P(B3) = Probability of machine B3 = 0.5
Let P(D) = Probability of a defective product
P(N) = Probability of a Non-defective product
P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003
P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006
P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010
Likewise,
P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997
P(N|B2) be probability of a non-defective product produced by machine 2 = 1 - P(D|B2) = 1 - 0.006 = 0.994
P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990
For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)
P(B1|N) = = = 0.1138
Hence the probability that a non-defective product is produced by machine B1 is 11.38%.