Explain why It takes longer to heat a cinema to the same temperature as a house.

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Answer 1

Answer: i think because a cinema is bigger than a house.

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In 1911, Ernest Rutherford and his assistants Geiger and Marsden conducted an experiment in which they scattered alpha particles (nuclei of helium atoms) from thin sheets of gold. An alpha particle, having charge 2e and mass 6.64 10-27 kg, is a product of certain radioactive decays. The results of the experiment led Rutherford to the idea that most of an atom's mass is in a very small nucleus, with electrons in orbit around it. Assume an alpha particle, initially very far from a stationary gold nucleus, is fired with a velocity of 1.50 107 m/s directly toward the nucleus (charge 79e). What is the smallest distance between the alpha particle and the nucleus before the alpha particle reverses direction?
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Given two metal balls (that are identical) with charges LaTeX: q_1q 1and LaTeX: q_2q 2. We find a repulsive force one exerts on the other to be LaTeX: 1.35\times10^{-4}N1.35 × 10 − 4 N when they are 20 cm apart. Accidentally, one the the experimenters causes the balls to collide and then repositions them 20 cm apart . Now the repulsive force is found to be LaTeX: 1.406\times10^{-4}N1.406 × 10 − 4 N. What are the initial charges on the two metal balls?

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Answer:

$q_1=\pm0.03 \mu C$ and $q_2=\pm0.02 \mu C.$

Explanation:

According to Coulomb's law, the magnitude of force between two point object having change $q_1$ and $q_2$ and by a dicstanced is

$F_c=(1)/(4\pi\spsilon_0)(q_1q_2)/(d^2)-\;\cdots(i)$

Where, $\epsilon_0$ is the permitivity of free space and

$(1)/(4\pi\spsilon_0)=9*10^9$ in SI unit.

Before dcollision:

Charges on both the sphere are $q_1$ and $q_2$ , d=20cm=0.2m, and $F_c=1.35*10^(-4)$ N

So, from equation (i)

$1.35*10^(-4)=9*10^9(q_1q_2)/((0.2)^2)$

$\Rightarrow q_1q_2=6*10^(-16)\;\cdots(ii)$

After dcollision: Each ephere have same charge, as at the time of collision there was contach and due to this charge get redistributed which made the charge density equal for both the sphere t. So, both have equal amount of charhe as both are identical.

Charges on both the sphere are mean of total charge, i.e

$(q_1+q_2)/(2)$

d=20cm=0.2m, and $F_c=1.406*10^(-4)$ N

So, from equation (i)

$1.406*10^(-4)=9*10^9(\left((q_1+q_2)/(2)\right)^2)/((0.2)^2)$

$\Rightarrow (q_1+q_2)^2=2.50*10^(-15)$

$\Rightarrow q_1+q_2=\pm5* 10^(-8)$

As given that the force is repulsive, so both the sphere have the same nature of charge, either positive or negative, so, here take the magnitude of the charge.

$\Rightarrow q_1+q_2=5* 10^(-8)\;\cdots(iii)$

$\Rightarrow q_1=5* 10^(-8)-q_2$

The equation (ii) become:

$(5* 10^(-8)-q_2)q_2=6*10^(-16)$

$\Rightarrow -(q_2)^2+5* 10^(-8)q_2-6*10^(-16)=0$

$\Rightarrow q_2=3*10^(-8), 2*10^(-8)$

From equation (iii)

$q_1=2*10^(-8), 3*10^(-8)$

So, the magnitude of initial charges on both the sphere are $3*10^(-8)$ Coulombs $=0.03 \mu C$ and $2*10^(-8)$ Colombs or $0.02 \mu C$ .

Considerion the nature of charges too,

$q_1=\pm0.03 \mu C$ and $q_2=\pm0.02 \mu C.$

Which object has the least momentum? Object A: m = 1 kg, v = 100 m/s
Object B: m = 10 kg, v = 12 m/s
Object C: m = 0.5 kg, v = 1000 m/s
Object D: m = 100 kg, v = 2 m/s

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the answer is c m= 0.5kg ....
that one

An electron microscope is usually used for microorganisms that are _____. too small to be seen with the unaided eye too small to be seen with an optical microscope not possible to observe with any instrument

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Answer;

too small to be seen with an optical microscope

Explanation;

An electron microscope is a type of microscope that is used to observe very tiny specimens whose features can not be observed by other types of microscopes. It uses a beam of electrons to generate an image of a given specimen whose features can be clearly observed and studied.
Electron microscope has very high resolution and magnification as compared to other optical microscope hence can be observed in the study of micro-organisms such as viruses which would be difficult to study their features using optical microscopes.

An electron microscope is usually used for microorganisms that are too small to be seen with the unaided eye. You can adjust the size of the microorganism to see it more clearly by adjusting its magnification lens.

Two 100 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car B at –10 m/s when they collide head–on. If the resulting velocity of Car B after the collision is 8 m/s, what is the velocity of Car A after the collision?(I saw this question was asked previously, but the person did not provide the correct answer...)

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Answer:

$v_a = -10 m/s$

so car A will move with speed 10 m/s in opposite direction

Explanation:

As we know that when two cars collide then the momentum of two cars will remains conserved

so here we have

$P_i = P_f$

mass of two cars = 100 kg

speed of car A = 8 m/s

speed of car B = - 10 m/s

after collision the speed of car B = +8 m/s

now by momentum conservation equation

$m_1v_(1i) + m_2v_(2i) = m_1v_(1f) + m_2v_(2f)$

so we have

$100(8) + 100(-10) = 100(v_a) + 100(8)$

so we have

$v_a = -10 m/s$

so car A will move with speed 10 m/s in opposite direction

Which of the following is a result of reduced levels of red blood cells and elevated levels of white blood cells in the body?

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The cells that circulate in the bloodstream are generally divided into three types, white blood cells.

A duck is 12 m from the edge of a pond. A student stands in the middle of the pondand creates ripples that travel past the duck and towards the edge of the pond. The
ripples are produced uniformly at 2 ripples per second. The student determines that
the ripples take 3.0 seconds after they pass the duck to reach the edge of the pond.
Determine the wavelength of the ripples.

Answers

Answer:

The wavelength is 2 meters

Explanation:

The relationship between the frequency, the speed and the wavelength is given by the relation;

v = f × λ

The given parameters are;

The distance of the duck from the edge of the pond = 12 m

The number of ripples produced per second = Frequency, f = 2 Hz

The time it takes the ripple to reach the edge of the pond after travelling past the duck = 3 seconds

Therefore, speed of the wave, v = Distance/time = 12 m/(3 s) = 4 m/s

The wavelength, λ, is therefore;

λ = v/f = (4 m/s)/(2 Hz) = 2 meters.

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Explain why It takes longer to heat a cinema to the same temperature as a house.​

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Explain why It takes longer to heat a cinema to the same temperature as a house.