Answer:
truuuuuuuuuuuuuue
Explanation:
Answer:
Your answer is true.
- Hope this helps!
N3- O2- F- Na
the answer is domains.................
iron? (8 points)
Answer:
first change cm to m and g to kg so you will find the volume first which is 0.02 by 0.03 by 0.02 your answer is 0.000012 m . using the formula density=mass/volume take 0.094/ 0.00012 then divide
The positive energy protons and negative electrons balance out.
THE ANSWER BOI:
27 g
HERE IS DA EXPLANATION FAM:
27 g
M(C6H12O6) = 6*12 + 12*1 + 6*16 = 180 g/mol
100 mL = 0.1 L solution
1.5 M = 1.5 mol/L
1.5 mol/L * 0.1 L = 0.15 mol C6H12O6
0.15 mol * 180 g/1 mol = 27 g C6H12O6
To find the needed grams of glucose for a 1.5 M solution in 100ml, you multiply the molarity by the molecular weight of glucose and the volume of the solution. The calculation is 1.5 mol/l * 180 g/mol * 0.1 l = 27 grams. Therefore, 27 grams of glucose is needed.
The problem in question requires you to make use of the formula M= mass (mol)/ Volume (L). To find the required grams of glucose, C6H12O6, for a 1.5 M solution in 100mL, you would multiply the molarity with the molecular weight of glucose - approximately 180g per mole - and the volume of the solution - 0.1L. Therefore, to solve the problem you would calculate it as: 1.5 mol/l X 180 g/mol x 0.1 l which equals 27g. Hence, you need 27 grams of glucose to make a 100ml, 1.5M solution.
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