Answer:
The given blank can be filled with research.
Explanation:
The procedure of looking for facts, which will lead to the truth is known as research. In the absence of research one cannot conclude that the facts or statements are right. Research is illustrated as a systematic and creative work performed to enhance the stock of knowledge, comprising knowledge of culture and society, humans, and the application of this knowledge stock to device novel uses.
b. Ionic solids have higher melting points than molecular solids.
c. Molecular solids have higher melting points than all other types of solids.
d. It is impossible for solids to melt; therefore solids do not have melting points.
B. Ionic solids have higher melting points than molecular solids.
John Dalton contribute to the understanding of the atom that all matter was composed of atoms, indivisible and indestructible building blocks.
While all atoms of an element were identical, different elements had atoms of differing sizes and mass.
An atom is a particle of matter that uniquely defines a chemical element.
An atom consists of a central nucleus that is usually surrounded by one or more electrons.
Dalton's atomic theory was the first complete attempt to describe all matter in terms of atoms and their properties.
Dalton based his theory on the law of conservation of mass and the law of constant composition.
The theory states that all matter is made of atoms, which are indivisible.
(1) All matter is composed of tiny, indivisible particles, called atoms, that cannot be destroyed or created.
(2) Each element has atoms that are identical to each other in all of their properties.
Learn more about the atom here:
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Answer:
The % yield of the reaction is 73.8 %
Explanation:
To solve this, we list out the given variables thus
Mass of aluminium in the experiment = 2.5 g
mass of oxygen gas in the experiment = 2.5 g
Molar mass of aluminium = 26.98 g/mol
molar mass of oxygen O₂ = 32 g/mol
The reaction between aluminium and gaseous oxygen can be written as follows
4Al + 3O₂ → 2Al₂O₃
Thus four moles of aluminium forms two moles of aluminium oxide
Thus (2.5 g)÷(26.98 g/mol) = 0.093 mole of aluminium and
(2.5 g)÷(32 g/mol) = 0.078125 moles of oxygen
However four moles of aluminium react with three moles of oxygen gas O₂
1 mole of aluminum will react with 3/4 moles of oxygen O₂ and 0.093 mole of aluminium will react with 0.093*3/4 moles of O₂ = 0.0695 moles of Oxygen hence aluminium is the limiting reagent and we have
1 mole of oxygen will react with 4/3 mole of aluminium
∴ 0.078125 mole of oxygen will react with 0.104 moles of aluminium
Therefore 0.093 mole of aluminium will react with O₂ to produce 2/4×0.093 or 0.0465 moles of 2Al₂O₃
The molar mass of 2Al₂O₃ = 101.96 g/mol
Hence the mass of 0.0465 moles = number of moles × (molar mass)
= 0.0465 moles × 101.96 g/mol = 4.74 g
The of aluminium oxide Al₂O₃ is 4.74 g, but the actual yield = 3.5 g
Therefore the Percentage yield = ×100 = × 100 = 73.8 % yield
(2) In the third shell, an electron has more energy and is farther from the nucleus.
(3) In the third shell, an electron has less energy and is closer to the nucleus.
(4) In the third shell, an electron has less energy and is farther from the nucleus.