Answer:
Average speed
Explanation:
We have given current through power i = 20 A
Diameter d = 1 cm = 0.01 m
So radius r = 0.005 m
So area
Charge on electron e =
We know that current is given by , here n is nuber density of free electron, e is charge on electron, A is area and is average speed
We know that for copper n =
So average speed
Answer:
e. f2 < f < f1
Explanation:
According to Doppler's Effect:
......................................(1)
where:
are observed frequency and source frequency respectively.
S = velocity of sound in the air from a stationary source
are the velocity of the observer and the velocity of sound source with respect to a stationary frame of reference.
Here
Then eq. (1) becomes:
Now, the value:
Now the eq. (1) becomes
∵the direction of motion of the source is away from the observer so a negative sign has been introduced.
Now, the value:
Answer:
Explanation:
given,
mass of the both ball = 5 Kg
length of rod = 2 L
where L = 0.55 m
angular speed = 45.6 rev/s
ω = 45.6 x 2 π
ω = 286.51 rad/s
v₁ = r₁ ω₁
v₁ =0.55 x 286.51 = 157.58 m/s
v₂ = r₂ ω₂
v₂ = 1.10 x 286.51 = 315.161 m/s
finding tension on the first half of the rod
r₁ = 0.55 r₂ = 2 x r₁ = 1.10
Answer:
λ = -47 nC / m
Explanation:
The missing question is as follows:
" The potential difference between the surface of a 2.2 cm -diameter power line and a point 1.9 m distant is 3.8 kV. What is the magnitude of the line charge density on the power line? Express your answer using two significant figures. "
Given:
- The Diameter of the power line D = 2.2 cm
- The distance between two ends of power line L = 1.9m
- The potential difference across two ends V = 3.8 KV
Find:
What is the magnitude of the line charge density on the power line?
Solution:
- The derivation of the line of charges for a length L oriented along any axis centered at origin and the potential difference between two ends is as follows:
V = 2*k*λ*Ln( D / L )
Where,
k : Coulomb's Constant = 8.99*10^9
λ : The line charge density
- Re-arrange and solve for λ:
λ = V / 2*k*Ln( D / L )
Plug in the values:
λ = 3800 / 2*8.99*10^9*Ln( 2.2 / 190 )
λ = -4.74022*10^-8 C / m
λ = -47 nC / m
Line charge density is the total charge distributed along the length of a wire, expressed in coulombs per meter. To calculate it, divide the total charge by the total length of the wire. Without specific numbers for charge and length, a numerical value can't be given.
To calculate the magnitude of the line charge density of a power line, you need to know the total charge (Q) distributed along the total length (L) of the wire. The line charge density (λ) is then defined as λ = Q/L. Unfortunately, without any specific numbers provided for these parameters, I can't provide a numerical answer.
Line charge density is a significant concept in electromagnetism and is measured in coulombs per meter (C/m).
Remember that the charge can be uniform or non-uniform along the length of the line.
For example, if a power line has a total charge of 0.02 C spread along its length of 50 m, it would have a line charge density of λ = Q/L = 0.02 C / 50 m = 0.0004 C/m
#SPJ3
b 2.5 m/s
c 10 m/s
d 5.2 m/s
Answer:
Explanation:
Step one:
given data
mass of ball m1=5kg
initial velocity of ball u1=10m/s
mass of pin m2=2kg
initial velocity of pin u2= 0m/s
final velocity of ball v2=8m/s
final velocity of pin v2=?
Step two:
The expression for elastic collision is given as
m1u1+m2u2=m1v1+m2v2
substituting we have
5*10+2*0=5*8+2*v2
50+0=40+2v2
50-40=2v2
10=2v2
divide both sides by 2
v2=10/2
v2=5m/s
The pin's final velocity is 5m/s
B) 16 sqrt 2 V
C) 256 V
D) 8
Answer:
A)
Explanation:
Maximum voltage =
Maximum voltage and rms voltage are related to each other by
Answer:
D. 39 N m
Explanation:
m = mass of the weight used in crossfit workout = 7.0 kg
Force due to the weight used is given as
F = mg
F = (7.0) (9.8)
F = 68.6 N
d = distance of point of action of weight from shoulder joint = 0.57 m
τ = Torque about the shoulder joint due to the weight
Torque about the shoulder joint due to the weight is given as
τ = F d
Inserting the values
τ = (68.6) (0.57)
τ = 39 Nm