The concentration of a certain sodium hydroxide solution was determined by using the solution to titrate a sample of potassium hydrogen phthalate (abbreviated as KHP). KHP is an acid with one acidic hydrogen and a molar mass of 204.22 g/mol. In the titration, 24.46 mL of the sodium hydroxide solution was required to react with 0.1082 g KHP. Calculate the molarity of the sodium hydroxide.
Answers
Answer:
Explanation:
Moles of KHP :
Given, Mass of KHP = 0.1082 g
Molar mass of KHP = 204.22 g/mol
The formula for the calculation of moles is shown below:
Thus,
According to the reaction shown below:
KHP + NaOH ⇒ KNaP + H₂O
1 mole of KHP reacts with 1 mole of NaOH
So,
of KHP reacts with
of NaOH
Moles of NaOH =
Volume = 24.46 mL = 0.02446 L ( 1 mL = 0.001 L)
Related Questions
This section of the periodic table is called a(n)
Ionic equation for Sr3(PO4)2 and its solubility product (Ksp)?
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Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mLmL of water to produce a solution that freezes at −−14.5 ∘C? The freezing point for pure water is 0.0 ∘C∘C and Kf is equal to 1.86 ∘C/m.If the 3.90 m solution from Part A boils at 103.45 ∘C, what is the actual value of the van't Hoff factor, i? The boiling point of pure water is 100.00 ∘C and Kb is equal to 0.512 ∘C/m.
of this experiment?
Xe(g) + 2 F2 (g) - XeF. (g)
Answers
The percentage yield of XeF from the concentration of the given reactants will be 25%.
The reaction states that 1 mole of Xe will give 1 mole of XeF, and 2 moles of fluorine, will gives 1 mole of XeF.
The limiting reactant can be calculated:
1 mole Xe = 2 moles of
2.2 moles of Xe = 2.2 2 moles of
2.2 moles of Xe = 4.4 moles of
Since the amount of available has been in the limiting, thus
has been the limiting reactant.
So, the yield of XeF in terms of will be:
2 moles = 1 mole XeF
Thus the theoretical yield of XeF is 1 mole.
The yield of XeF we get = 0.25 moles.
Thus the percentage yield =
Percentage yield =
Percentage yield = 25%
Thus the percentage yield of XeF from the concentration of the given reactants will be 25%.
For more information about the percent yield, refer to the link:
Answers
Weight of lead = moles x atomic weight of lead
= 0.265x207.2
= 54.908 grams.
Hope this helps!
Answers
Answer:
5.56×10²² molecules of AlPO4
Explanation:
i think thats is the correct answer if its wrong im really sorry
Final answer:
Caffeine has two sp2 and one sp3 hybridized carbon atoms in its structure.
Explanation:
Caffeine has three carbon atoms in its structure, and the hybridization of these carbon atoms determines the types of bonds they form. Two of the carbon atoms in caffeine are sp2-hybridized, while the remaining carbon atom is sp3-hybridized.
The sp2-hybridized carbon atoms form double bonds with nitrogen atoms and are found in the pyrimidine and pyrazole rings of the caffeine molecule. They have trigonal planar geometry with bond angles of approximately 120 degrees.
The sp3-hybridized carbon atom is found in the methyl group (CH3) attached to the pyrimidine ring. It forms single bonds with three hydrogen atoms and has tetrahedral geometry with bond angles approximately 109.5 degrees.
Learn more about Chemical Bonding here:
#SPJ3
the specific heat of the resulting Nacl solutions is 4.06j/gc
calculate the heat of neutralisation of hcl and naoh in kj/mol nacl products
Answers
Answer:
62.12kJ/mol
Explanation:
The neutralization reaction of HCl and NaOH is:
HCl + NaOH → NaCl + H₂O + HEAT
You can find the released heat of the reaction and heat of neutralization (Released heat per mole of reaction) using the formula:
Q = C×m×ΔT
Where Q is heat, C specific heat of the solution (4.06J/gºC), m its mass and ΔT change in temperature (27.5ºC-20.0ºC = 7.5ºC).
The mass of the solution can be finded with the volume of the solution (50.0mL of HCl solution + 50.0mL of NaOH solution = 100.0mL) and its density (1.02g/mL), thus:
100.0mL × (1.02g / mL) = 102g of solution.
Replacing, heat produced in the reaction was:
Q = C×m×ΔT
Q = 4.06J/gºC×102g×7.5ºC
Q = 3106J = 3.106kJ of heat are released.
There are 50.0mL ×1M = 50.0mmoles = 0.0500 moles of HCl and NaOH that are reacting releasing 3.106kJ of heat. That means heat of neutralization is:
3.106kJ / 0.0500mol of reaction =
62.12kJ/mol is heat of neutralization
nitrogen in the compound N,H, (gram-formula
32 g/mol)?
(1) 13%
(3) 88%
(2) 44%
(4) 93%
Answers
Answer: 88%
Explanation:
Answers
Answer: The mass of carbon and hydrogen in the sample is 0.1087 g and 0.0066 g respectively and the percentage composition of carbon and hydrogen in the sample is 94.27 % and 5.72 % respectively.
Explanation:
The chemical equation for the combustion of hydrocarbon having carbon and hydrogen follows:
where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.
We are given:
Mass of
Mass of
Mass of sample = 0.1153 g
We know that:
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
- For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 0.3986 g of carbon dioxide, of carbon will be contained.
- For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 0.0578 g of water, of hydrogen will be contained.
To calculate the percentage composition of a substance in sample, we use the equation:
......(1)
- For Carbon:
Mass of sample = 0.1153 g
Mass of carbon = 0.1087 g
Putting values in equation 1, we get:
- For Hydrogen:
Mass of sample = 0.1153 g
Mass of hydrogen = 0.0066 g
Putting values in equation 1, we get:
Hence, the mass of carbon and hydrogen in the sample is 0.1087 g and 0.0066 g respectively and the percentage composition of carbon and hydrogen in the sample is 94.27 % and 5.72 % respectively.