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The diameter of an atom is approximately 1 * 10 ^ - 10 * m . What is the diameter in decimeters?

Answers

Answer 1

Answer:

Answer:

$d=1x10^(-9)dm$

Explanation:

Hello,

In this case, considering that 1 m equals 10 dm, the required diameter of the atom in decimetres is:

$d=1x10^(-10)m*(10dm)/(1m) \n\nd=1x10^(-9)dm$

Best regards.

Answer 2

Answer:

Final answer:

The diameter of an atom is approximately 1 * 10^-10 * m, which translates to 1 * 10^-11 decimeters by multiplying the meter measurement by 10.

Explanation:

The subject of this question is a unit conversion. We are trying to convert the diameter of an atom from meters to decimeters.

The process is as follows:

First, we need to understand that 1 meter equals 10 decimeters because the prefix 'deci-' means one-tenth.
So, if the diameter of an atom is approximately 1 * 10^-10 * m, then in decimeters the diameter would be 1 * 10^-11 * dm

In essence, to convert meters to decimeters, we need to multiply the meter measurement by 10. But because the meter measurement of the atom is in the power of -10, the decimeter equivalent would be in the power of -11.

Learn more about Unit Conversion here:

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Which is the limiting reactant when 5.00g of H2 and 10.00g of O2 react and form water?

Note: Please show all work and calculation setups to get full credit. T. he following may be used on this assignment: specific heat of (water=4.184 J/g oC; ice=2.03 J/g oC; steam=1.99 184 J/g oC); heat of fusion of water=80. cal/g; heat of vaporization=540 cal/g; 1cal=4.184J.Calculate the energy required (in J) to convert 25 g of ice at -15 oC to water at 75 oC.

Answers

Answer:

1.7 × 10⁴ J

Explanation:

Step 1: Calculate the heat required to raise the temperature of ice from -15 °C to 0°C

We will use the following expression.

Q₁ = c(ice) × m × ΔT

Q₁ = 2.03 J/g.°C × 25 g × [0°C - (-15°C)] = 7.6 × 10² J

Step 2: Calculate the heat required to melt 25 g of ice

We will use the following expression.

Q₂ = C(fusion) × m

Q₂ = 80. cal/g × 25 g × 4.184 J/1 cal = 8.4 × 10³ J

Step 3: Calculate the heat required to raise the temperature of water from 0°C to 75 °C

We will use the following expression.

Q₃ = c(water) × m × ΔT

Q₃ = 4.184 J/g.°C × 25 g × (75°C - 0°C) = 7.8 × 10³ J

Step 4: Calculate the total heat required

Q = Q₁ + Q₂ + Q₃

Q = 7.6 × 10² J + 8.4 × 10³ J + 7.8 × 10³ J = 1.7 × 10⁴ J

a student wants to remove the salt from a mixture of sand and salt in order to get only person he adds water to the mixture why it's the step help

Answers

You would add water to the mixture to dissolve the salt. When the salt is dissolved, you have your sand alone.

Water dissolves the salt and pour out the water let it evaporate and you have separate salt and water

Which is the best description of a molecule?

Answers

Answer:

a molecule is the smallest particle in a chemical element or compound that has the chemical properties of that element or compound. Molecules are made up of atoms that are held together by chemical bonds. These bonds form as a result of the sharing or exchange of electrons among atoms

Answer:

: A molecule is the smallest particle in a chemical element or compound that has the chemical properties of that element or compound. Molecules are made up of atoms that are held together by chemical bonds. These bonds form as a result of the sharing or exchange of electrons among atoms.

Explanation:

i hope its right

In the important industrial process for producing ammonia (the Haber Process), the overall reaction is: N2(g) + 3H2(g) → 2NH3(g) + 24,000 calories A yield of ammonia, NH3, of approximately 98% can be obtained at 200°C and 1,000 atmospheres of pressure. How many grams of N2 must react to form 1.7 grams of ammonia?

Answers

Answer:

Mass of N2 required = 1.429 g

Explanation:

The given reaction is:

N2(g) + 3H2(g) → 2NH3(g)

Mass of NH3 formed = 1.7 g

Molar mass of NH3 = 17 g/mol

$Moles(NH3) = (Mass)/(Molar mass) = (1.7)/(17) = 0. 1$

Based on the reaction stoichiometry:

1 mole of N2 forms 2 moles of NH3

Therefore, moles of N2 required to produce 0.1 moles of NH3 is:

$= (1 mole(N2)*0.1moles(NH3))/(2 moles(NH3)) =0.05 moles(N2)$

Molar mass of N2 = 28 g/mol

Mass of N2 required = moles*molar mass = 0.05*28 = 1.4 g

This is the theoretical mass corresponding to a 100% yield. Since the yield of NH3 is 98%, the corresponding mass of N2 required would be:

$=(1.4)/(0.98) =1.429 g$

28g N2/(17 x 2 x 0.98) g NH3

1.7 g NH3 x 28g N2/(17 x 2 x 0.98) g NH3 =

47.6 / 33.32 = 1.43 g N2

A car travels for 0.5 hours and goes 25 miles. What is the car's speed? (Remember sad + t)

Answers

Answer:

s = 22.352 m/s

Explanation:

Given data:

Time taken = 0.5 hours

Distance cover = 25 miles

Car speed = ?

Solution:

First of all we will convert the units.

1 hour = 3600 sec

0.5 hr ×3600 sec / 1hr = 1800 sec

miles to meter:

25 mi × 1609 m/ 1 mi = 40233.6 m

Formula:

s = d/t

s = speed

d = distance

t = time

Now we will put the values in formula.

s = 40233.6 m / 1800 sec

s = 22.352 m/s

Final answer:

The speed of the car, calculated by dividing the distance travelled (25 miles) by the time taken (0.5 hours), is 50 miles per hour.

Explanation:

The subject of the question falls under Mathematics, specifically a section of it named rate, time, and distance problems. The problem is asking us to calculate the speed of a car which can be obtained by dividing the distance travelled by the time taken. Given that the distance travelled by the car is 25 miles and the time taken is 0.5 hours, we can calculate the speed as follows.