Can anyone help me with this question?

Answers

Answer 1

Answer: in the owen, heat absorbed by two metals are different due to their specific heat(c -- Q=mct). the one that absorbed more heat, should cool down slower if their shapes are the same.

outside the owen, heat transferred to the air with related equation -- heat conductivity q=kAt/d. with the same amount of heat, block with better conductivity -- larger surface area(A), more thermal conductivity(k) and thiner(d), should have lower the temperature.

----- above is for you to understand where are the factors came from. not to answer as such.

in summary related factors are specific heat, thermal conductivity, surface area and thickness of the material. use this to explain such as 'one has larger surface area so it cool down faster'

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The spectrum produced by a prism or a raindrop is evidence that the average speed of light in the material depends on the light'sA. transmission qualities.
B. color.
C. wave nature.
D. particle nature.

Answers

The correct answer for the question that is being presented above is this one: "B. color." The spectrum produced by a prism or a raindrop is evidence that the average speed of light in the material depends on the light's color. White light is being refracted into different colors.

What is a normal force?

Answers

is the component perpendicular to the surface on contact of the contact force

Artists Michaelangelo, Raphael, and Leonardo da Vinci belong to which period of the Renaissance?a. Early Renaissance
b. High Renaissance
c. Late Renaissance

Answers

Answer:

The correct answer is option B, High Renaissance

Explanation:

The high renaissance period is the first half of the 16th century which marked its beginning from 1490s and ended by late 15th century. Some of the best known artist of this period were Michelangelo, Raphael, Bramante, Leonardo da Vinci etc. The period of existence of these artist was

a) Leobardo Da Vinci - 1452-1519

b) Michelangelo - 1475-1564

c) Raphael – 1483 -1520

Answer:

The correct answer is option B, High Renaissance

Explanation:

A 1.00-L bulb and a 1.50-L bulb, connected by a stopcock, are filled, respectively, with argon at 0.75 atm and helium at 1.20 atm at the same temperature. Calculate the total pressure and the partial pressures of each gas after the stopcock has been opened and the mole fraction of each gas. Assume ideal-gas behavior.

Answers

Answer:

Explanation:

If P₁(p) be the partial pressure of gas in first bulb then

P₁(p) (1 +1.5) = P₁V₁ = 1 X 0.75

P₁(p) = (1 / 2.5) x .75 = 0.3 atm

Similarly partial pressure of gas in second bulb

= ( 1.5 / 2.5) x 1.2 = .72 atm

Total pressure= .3 + .72 = 1.02 atms.

If n₁ and n₂ be their moles in the respective bulbs

P₁V₁ = n₁ R t

P₂ V₂ = n₂ R t

$(P_1V_1)/(P_2V_2) = (n_1)/(n_2)$

$(n_1)/(n_2+n_1 ) = (P_1V_1)/(P_1V_1+P_2V_2)$

mole fraction of argon = $(.75* 1)/(.75*1+1.2*1.5)$

= $(.75)/(2.55)$

= 15 / 51

Mole fraction of helium = 1 - 15 / 51 = 36 / 51

Answer:

The total pressure of the mixture is 1.02 atm.

Partial pressure of the argon : $p_(Ar)=0.30atm$

Partial pressure of the helium : $p_(He)=0.72atm$

Explanation:

Volume of argon in the bulb = $V_1$ = 1.00 L

Pressure of argon in the bulb = $P_1$ = 0.75 atm

Temperature of the both the gases = T

Moles of argon gases = $n_1$

$P_1V_1=n_1RT$ ..[1]

Volume of helium in the bulb = $V_2$ = 1.50 L

Pressure of helium in the bulb = $P_2$ = 1.20 atm

Moles of helium gases = $n_2$

$P_2V_2=n_2RT$ ..[2]

[1] ÷ [2]

$(P_1V_1)/(P_2V_2)=(n_1)/(n_2)$

$(n_1)/(n_2)=(0.75 atm* 1.00 L)/(1.20 atm* 1.50 L)$

$(n_1)/(n_2)=(5)/(12)$

$n_2=2.4* n_1$

After opening the stopcock, the gases are mixed.

The mole fraction of argon = $\chi_1=(n_1)/(n_1+n_2)$

$\chi_1=(n_1)/(n_1+2.4n_1)=0.2941$

The mole fraction of helium= $\chi_2=(n_2)/(n_1+n_2)$

$\chi_2=(2.4n_1)/(n_1+2.4n_1)=0.7059$

Volume of the mixture ,V= 1.00 L + 1.50 L =2.50 L

Total pressure in the mixture = P

Temperature is same = T

Total moles of gases in the mixtures = n

$PV=nRT$

$n=n_1+n_2$

$(PV)/(RT)=(P_1V_1)/(RT)+(P_1V_1)/(RT)$

$P* 2.50L=0.75 atm* 1.00 L+1.20 atm* 1.50 L$

$P* 2.50L=2.55 atm L$

$P=(2.55 atm L)/(2.50 L)=1.02 atm$

The total pressure of the mixture is 1.02 atm.

Partial pressure of the argon after mixing : $p_(Ar)$

$p_(Ar)=P* \chi_1=1.02* 0.2941=0.30 atm$

Partial pressure of the helium after mixing : $p_(He)$

$p_(He)=P* \chi_2=1.02* 0.7059=0.72 atm$

The driver of a car is driving the car very fast.The car hits a crash barrier and stops very quickly.
Describe why the driver is injured.

Answers

because the persons head is probably slammed into some part of the car and that means that the persons slammed on the brakes really hard so the person is probably injured
i hope this helps

The momentum of the car is probably very large before.When it crashes. the momentum changes suddenly in a short period of time.
Rate of change of momentum = Force

So, as the momentum changes in a very short period of time, the force exerted on the driver is very large.So, he gets injured

When a wave is acted upon by an external damping force what happens to the energy of the waveA-the energy of the wave decreases gradually
B-rhe energy of the wave increases gradually
C-there is no change in the energy of the wave
D-the propagation of the wave stops immediately

Answers

Answer:

A-the energy of the wave decreases gradually

Explanation:

when a wave is acted upon by an external damping force the energy of the wave decreases gradually.

The energy degrades into the form of heat which is considered to be of less value and use. The reason is because it disperses and spreads more widely.

So therefore it end up as heat with a little sound but that is close to none because that too disperses into heat i.e. decreased form of energy.

Answer:

Explanation:

PLATO

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