Why do prokaryotic cells usually reproduce more quickly than eukaryotic cells? Choose 1 answer:

(Choice A) A Eukaryotic cells are more structurally complex than prokaryotic cells.

(Choice B) B Eukaryotic cells have less DNA than prokaryotic cells.

(Choice C) C Eukaryotic cells have more cell walls than prokaryotic cells.

(Choice D) D Eukaryotic cells are smaller than prokaryotic cells.

Answers

Answer 1

Answer:

Prokaryotic cells reproduce more quickly than eukaryotic cells because the latter are more structurally complex. The correct option is A.

Structural complexity of cells

Eukaryotic cells have nuclei and membrane-bound organelles such as mitochondrion. This is unlike prokaryotic cells whose DNA lies freely in the cytoplasm and lacks membrane-bound organelles.

In order words, eukaryotic cells are structurally more complex than prokaryotic cells. Thus, reproductive times in prokaryotes are usually quicker than in eukaryotes.

More on the structural complexity of cells can be found here: brainly.com/question/3502696

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At what approximate altitude in the atmosphere can stratospheric ozone be found?

Answers

100 km is the answer to your question i will be happy to help you any time

two vectors of same units have magnitude of 8 unit and 5 unit. what are the maximum and minimum magnitude of resultant that can be obtained with the two vectors?

Answers

Explanation:

Max will be when they are in the same direction: 8 + 5 = 13 units

Min will be when they are in opposite directions 8-5 = 3 units

Work done by the resultant force is always equal to change in kinetic energy a)True b)False

Answers

b) False

The statement is not always true. The work done by the resultant force is equal to the change in kinetic energy only in the absence of other non-conservative forces, such as friction or air resistance. In the presence of such forces, the work-energy theorem may not hold, and the work done by the resultant force may not equal the change in kinetic energy.

In a physics experiment, two equal-mass carts roll towards each other on a level, low-friction track. One cart rolls rightward at 2 m/s and the other cart rolls leftward at 1 m/s. After the carts collide, they couple (attach together) and roll together with a speed of __________. Ignore resistive forces.a. 0.5 m/sb. 0.33 m/s
c. 0.67 m/s
d. 1.0 m/s
e. none of these

Answers

Answer:

The correct answer is option a.

Explanation:

Conservation of momentum :

$m_1u_1+m_2u_2=m_1v_1+m_1v_2$

Where :

$m_1, m_2$ = masses of object collided

$u_1,u_2$ = initial velocity before collision

$v_1,v_2$ = final velocity after collision

We have :

Two equal-mass carts roll towards each other.

$m_1=m_2=M$

Initial velocity of $m_1=u_1=2 m/s$

Initial velocity of $m_2=u_2=-1 m/s$ (opposite direction)

Final velocity of $m_1=v_1=v$ (same direction )

Final velocity of $m_2=v_2=v$ (same direction)

$M* 2 m/s+M(-1 m/s)=Mv+Mv$

$1 m/s=2v$

v = 0.5 m/s

rg135

The speed of the carts after their collision is 0.5 m/s.

What is the capital of prince edward island

Answers

Answer:

The capital of Prince Edward Island is Charlottetown.

Explanation:

hope this helps, and if it did, please mark brainliest :)

The wavelength of some violet light is 420.0 nm. what is the frequency of this violet light?

Answers

The equation relating wavelength and frequency of light is:
v = fλ; where v is the wave's speed, f is its frequency and λ is the wavelength.
The speed of violet light will be the same as for any elecromagnetic radiation, that is,
3 x 10⁸ m/s
3 x 10⁸ = f(420 x 10⁻⁹)
f = 7.14 x 10¹⁴ Hz

The frequency of light for which the wavelength is $420\,{\text{nm}}$ is $\boxed{7.14 * {{10}^(14)}\,{\text{Hz}}}$ .

Further explanation:

The frequency is a measure of number of wave’s that passes through a fixed point or place in a given time interval. The S.I unit of frequency is Hertz $\left( {{\text{Hz}}} \right)$ .

Wavelength is defined as the distance between two successive crests or troughs of a travelling wave.

Examples of waves are sound wave, light wave, mechanical waves, surface waves etc.

Given:

The wavelength of the light used is $420\,{\text{nm}}$ .

The speed of the light is $3 * {10^8}\,{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {\text{s}}}} \right. \kern-\nulldelimiterspace} {\text{s}}}$ .

Concept:

Light is an electromagnetic wave which carries energy in the form of electric field and magnetic field. The speed of light in vacuum is $3 * {10^8}\,{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {\text{s}}}} \right. \kern-\nulldelimiterspace} {\text{s}}}$ .

The speed of light can be expressed in terms of wavelength of the light and the frequency of the light.

The speed of light is:

$c = f \cdot \lambda$

Rearrange the above expression.

$\boxed{f=(c)/(\lambda )}$ …… (1)

Here, $f$ is the frequency of the light, $c$ is the speed of the light in vacuum and $\lambda$ is the wavelength of the light.

Substitute $3 * {10^8}\,{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {\text{s}}}} \right. \kern-\nulldelimiterspace} {\text{s}}}$ for $c$ and $420 * {10^( - 9)}\,{\text{m}}$ for $\lambda$ in equation (1).

$\begin{aligned}f&=\frac{{3*{{10}^8}\,{{\text{m}}\mathord{\left/ {\vphantom {{\text{m}} {\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}}{{420 * {{10}^(-9)}\,{\text{m}}}}\n&=7.14* {10^(14)}\,{\text{Hz}} \n \end{aligned}$

Thus, the frequency of light for which the wavelength is $420\,{\text{nm}}$ is $\boxed{7.14 * {{10}^(14)}\,{\text{Hz}}}$ .

Learn More:

1. What is the threshold frequency ν0 of cesium? Note that 1 ev (electron volt)=1.60×10−19 j. brainly.com/question/6953278

2. Calculate the wavelength of an electron (m = 9.11 × 10-28 g) moving at 3.66 × 106 m/s brainly.com/question/1979815

3. What is the frequency of light for which the wavelength is 7.1 × 102 nm brainly.com/question/9559140

Answer Details:

Grade: High School

Subject: Physics

Chapter: Electromagnetic Waves

Keywords:

Frequency, light, wavelength, 420 nm, 4.20x10^-7 m, 7.14x10^14 Hz, vacuum, air, crests, troughs, sound wave, light wave, mechanical wave.

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