How many decimeters are there in 27 meters

Answers

Answer 1

Answer: There are 270 decimeters in 27 meters.

Answer 2

Answer: 27 meters = 270 decimeters
to find this you multiply the number of meters by 10

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Maria works 24.5 hours each week at a bookstore . she earns 8.76 per hour . How much does she earn each week

Answers

Since Maria works 24.5 hours a week and 8.76 per hour, you find the total amount by multiplying 24.5 (hours) by 8.76 (amount per hour)

That gets you $214.62.

She earns 24.5 x 8.76 = 214.62

the area of a rectangular ice skating rink is 900 square yards if the length of the rink is 100 yards with is the width of the rink

Answers

Area/Length=Width
900yds^2/100 yds=Width
9 yds=Width

Kendra is making a bracelet for herself and her friend she is also making a necklace. The necklace is 3 times the length of one bracelet. She can use at most 30 inches of string. What is the length of one bracelet? What is the length of one necklace?

Answers

You would probably need to divide. Inches
-------- = 30/3 = 10.

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Which set is a function? A)
{(0,3), (3,0), (0,4), (4,0)}

B)
{(0,2), (2,0), (4,6), (6,4)}

C)
{(2,6), (3,6), (4,6), (2,0)}

D)
{(6,2), (2,0), (4,6), (6,4)}

D)

Answers

Answer: The answer is B

Step-by-step explanation:

in all of the other sets, there is one that has a repeating X, make them not a function

Answer:

Step-by-step explanation:

A function cannot have a repeated x-coordinate
In set A, the number 0 is repeated twice
In set C, the number 2 is repeated twice
In set D, the number 6 is repeated twice
Therefore, the correct answer is B because none of the x-coordinates are repeated.

The equation 7^2=a^3 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in astronomical units, AU. If planet Y is k times the mean distance from the sun as planet X, by what factor is the orbital period increased?

Answers

Answer:

The period of Y increases by a factor of $k^ {3/2}$ with respect to the period of X

Step-by-step explanation:

The equation $T ^ 2 = a ^ 3$ shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?

For the planet Y:

$T_y ^ 2 = a_y ^ 3$

For planet X:

$T_x ^ 2 = a_x ^ 3$

To know the factor of aumeto we compared $T_x$ with $T_y$

We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:

$a_y ^ 3 = (a_xk) ^ 3$

$(T_y ^ 2)/(T_x ^ 2)=(a_y ^ 3)/(a_x^ 3)\n\n(T_y ^ 2)/(T_x ^ 2)=((a_xk)^3)/(a_x ^ 3)\n\n(T_y^ 2)/(T_x^ 2)=\frac{k ^ {3}a_(x)^ 3}{a_(x)^ 3}\n\n(T_(y)^ 2)/(T_(x)^ 2)=k ^ 3\n\nT_(y)^ 2 = T_(x)^(2)k^(3)\n\nT_(y) =k^{(3)/(2)}T_x$

Finally the period of Y increases by a factor of $k^ {3/2}$ with respect to the period of X

A cylinder has a volume of 321 cubic units. If a cone has the same height and radius as the cylinder, what is the volume in cubic units?A.107 cubic units
B.214 cubic units
C.642 cubic units
D.963 cubic units

Answers

The volume of the cone which has the radius and height same as the cylinder of volume 321 cubic units is 107 cubic units.

What is the volume?

A cylinder is defined as a surface made up of all the points on all the parallel lines that pass through a set plane curve in a plane that is not parallel to the provided line.

The volume of the cylinder is given by the formula,

$\text{Volume of cylinder} = \pi r^2 h$