Solve A=LW for A if L=12m and W=6

Answers

Answer 1

Answer: A=LW
L=12m
W=6

A=12*6
A=72

Answer 2

Answer: easy, multiply
A=L times W
A=12 times 6
A=72

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Six nickels is what percent of one dollar? What percent of $2.00 would it be? Please help.

Answers

$6\ nickels=6*\ \$0.05=\$0.30\n\n(0.03)/(1)\cdot100\%=3\%\n\n6\ nickels\ is\ 3\%\ of\ \$1.\n\n(0.03)/(2)\cdot100\%=1.5\%\n\n6\ nickels\ is\ 1.5\%\ of\ \$2.$

HELP ASAP PLEASE I NEED HELP

Answers

Answer:

Step-by-step explanation:

I think it is I'm not sure but I hope it is

5. The United States Air Force has 19 women for every 81 men enlisted. what is the ratio of men to women.

Answers

Answer: 81 to 19

Step-by-step explanation:

Final answer:

The ratio of men to women in the United States Air Force is 81:19, even when simplified, suggesting that there are significantly more men than women in the force.

Explanation:

To calculate the ratio of men to women in the United States Air Force, you need the numbers of men and women, which are given in the problem as 81 men and 19 women, respectively.

Thus, the ratio of men to women is 81:19. This signifies that, for every 81 men in the force, there are 19 women. The ratio of men to women can also be simplified by dividing both numbers by their greatest common divisor (in this case, 1), giving an equivalent simplified ratio of 81:19.

Remember, when you express a ratio, it should be in the simplest form or lowest terms, similar to simplifying fractions. For example, the ratio 2:4 should be reduced to 1:2, by dividing each side by 2, the greatest common divisor.

Learn more about Ratio here:

brainly.com/question/32531170

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What is 81 to the power of -1/4?

Answers

81^(-1/4) is the same as the fourth root of (1/81). Which can be written as 4th root of 1 divided by the 4th root of 81.
The 4th root of 1 is 1 (because 1x1x1x1x1=1).
The 4th root of 81 is 3 (because 3x3x3x3=81).
So 81^(-1/4) = 1/3

The hypotenuse AB of a right triangle ABC is 5 ft, and one leg, AC, is decreasing at the rate of 2 ft/sec. The rate, in square feet per second, at which the area is changing when AC = 3 is?

Answers

Answer: $-(7)/(4) \quad \text{ft}^(2)/\sec$

Step-by-step explanation:

Since ABC is a right triangle, at any moment it holds that

$5^2=(AC)^2+(BC)^2$

Moreover, the area A of the triangle is given by

$A= (1)/(2)(AC)(BC)$

and we know that the rate of change of the length (AC) is

constant decreasing 2, which may be written using the Leibniz

notation as

$(d(AC))/(dt)=-2$ .

Using the chain rule and the product rule for derivation, the two

first equations tell us

that

$0 = 2 (d(AC))/(dt)(AC) + 2 (d(BC))/(dt)(BC)$

and

$(dA)/(dt) = (1)/(2) \left( (d(AC))/(dt) \cdot (BC) + (d(BC))/(dt) \cdot (AC)\right)$

Moreover, using the first of the last two equations we get

$(AC)(d(AC))/(dt) = -(BC)(d(BC))/(dt) \Rightarrow\n\n\n(AC)(-2) = -(BC) (d(BC))/(dt) \quad \Rightarrow \quad (d(BC))/(dt)=2 ((AC))/((BC))$

Now, when (AC)=3, we have that

$25=(AC)^2 + (BC)^2 \quad \Rightarrow 25 = 9 + (BC)^2\n \n\Rightarrow \quad 16=(BC)^2 \quad \Rightarrow (BC)=4$

and

$(d(BC))/(dt) = 2 ((AC))/((BC))=2 (3)/(4)=(3)/(2)$ .

Hence, at this moment the rate of change of the area of the triangle is

$(dA)/(dt) = (1)/(2) \left( (d(AC))/(dt) \cdot (BC) + (d(BC))/(dt) \cdot(AC) \right)=(1)/(2)\left( -2 \cdot 4 + (3)/(2)\cdot 3\right ) = -(7)/(4)$

okay
we have the rate of change of AC = d(AC)/dt = -2
the rate of change od BC = d(BC)/dt
area = (1/2) *AC) (BC)
taking differential on both sides we ge
d(A)/dt = 1/2){ (BC) d(AC)/dt + (AC) d(BC)/dt)}....(1)
again
when AC= 3
applying pythagorous thm
we get
(5)^2 =(3)^2 +(BC)^2
hence we get BC = 4
now we need to find d(BC)/dt
we have
(5)^2 = (AC)^2 +(BC)^2
taking differenial
0=2(AC) d(AC/dt) +2BC d(BC)/dt
that is
d(BC)/dt = -(3) *(-2)/4 ..(at AC =3)
hence
d(BC)/dt = 3/2
substituting these values in equation (1)
d(A)/dt = (1/2) {4 * -2 + 3 *3/2}

which gives
d(A)/dt = -7/4

The rate, in square feet per second, at which the area is changing when AC = 3 is -7/4 ft/sec.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

The tuition costs, C, for a local community college are modeled by C(h) = 250 + 200h, where h represents the number of credit hours taken. The local state university has tuition costs, S, modeled by the function S(h) = 300 + 180h. How many credit hours will a student have to take for the two tuition costs to be equal? Round the answer to the nearest tenth of an hour. 250 + 200h = 300 + 180h 250 + 200h = 300 + 180h − 180h − 180h 250 + 20h = 300 h = credit hours

Answers

To solve how many credit hours will a student have to take for the two tuition costs to be equal, the two functions should be equated and solve for the number of hours
C (h) = S (h)
250 + 200h = 300 + 180h
200h – 180h = 300 – 250
20h = 50
H = 2.5 credit hours

The required equation is: $\mathbf{150 + 200h = 300 + 180h}$ and the number of credit hours is 7.5