MATHEMATICS HIGH SCHOOL

Select all statements that are true about the graph of ordered pair (5, −1) . The point is 5 units below the x-axis. The point is 1 unit below the x-axis. The point is 1 unit to the left of the y-axis. The point is in the fourth quadrant. The point is on the x-axis.

Answers

Answer 1
Answer:

The statements (B) and (D) are "true" about the graph of ordered pair (5, −1).

What is a graph?

A graph can be defined as a pictorial representation or a diagram that represents data or values.

The graph of the ordered pair (5, -1). The point (5, -1) is located 5 units to the right of the y-axis and 1 unit below the x-axis.

So statement A is false. It is not 5 units below the x-axis.

So, statement B is true.

The fourth quadrant is the region where x > 0 and y < 0, so it lies in the fourth quadrant.

Thus, statements (B) and (D) are "true" about the given graph.

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Answer 2
Answer:

Answer:

The point is below the x-axis and The point is in the fourth quadrant.

Step-by-step explanation:

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HELP MEEE!7th grade mathhhh

Is 5/6 is greater than 10/12

Answers

The fraction (5)/(6) is the fraction, which is not greater than the fraction given as (10)/(12). They are equal.

Given are two fractions.

(5)/(6) and (10)/(12)

It is required to find the relationship between these fractional numbers.

In order to find the relationship between two fractions, it is first required to make the denominators of the fraction equal.

Here, the denominator of one fraction is 6 and the other fraction is 12.

Since 6 is a factor of 12, multiply the numerator and the denominator by 2 to make it 12.

So, (5)/(6) , can be multiplied by both the numerator and denominator to get (10)/(12)So, the fractions are equal.

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NO. 5/6 is 10/12, since all your doing is multiplying the fraction 5/6 by 2 on both the denominator and the numerator to get 10/12. Since 2 is commonly multiplied, it can be factored out as well, thus leaving 5/6 = 10/12.

Organize the following polynomial expressions from least to greatest based on their degree:I x + 2xyz
II 3x + y + z
III 2x3y + y2x - 3x + 4
IV 9x3yz

A II, III, I, IV

B III, I, IV, II

C I, II, IV, III

D II, I, III, IV

Answers

The degree of a polynomial is equal to the highest sum of the variables among the terms. In I, degree is equal to 3, II is equal to 1, II is equal to 4, and IV is equal to 5. Hence, the order from least to greatest then, the order is II, I, III and IV. Answer is A>

Answer: 2134

Step-by-step explanation:

For the school recycling project, the seventh grade collected sixteen more than five times as many cans as the eighth grade. The seventh grade collected 251 cans. Select all of the equations that can be used to find the number of cans, c, the eighth grade collected.5c=251−16

5c=251+16

5c+16c=251

5c+16=251
which one?

Answers

251-16=235

235/5=47

so a

Answer:don't know like if you want

Step-by-step explanation: H I H I H I H I

Figure ABCD is a parallelogram with point C (3, −2). Figure ABCD is rotated 90° clockwise to form figure A′B′C′D′. What coordinate would be the output for point C'? (5 points)A.C' (2, −3)
B.C' (−2, −3)
C.C' (−2, 3)
D.C' (2, 3)

Answers

After rotation the output for point C´ would be  ( - 2 . -3 ).  There is also a graph showing rotation in the attachment.

What is the difference between: |x+3| = 10 & |x| + 3 = 10

Answers

Answer:

Step-by-step explanation:

|x+3| = 10  means the absolute value of x+3 equal 10, so the answer to that means x= -13 or x= 7 (i.e. |-13+3| = |-10| =10, |7+3| = |10| = 10)

|x| + 3 = 10 means the absolute value of just x, so the answer to that would be x= -7 or x= 7 (i.e. |-7|+3 = 7+3 = 10, |7|+3 = 7+3 = 10)

However, take everything I say with a grain of salt, because I struggle some with Absolute Value Equations as well.

I hope this helps give you an idea of what you're looking at, though :)

Identify a horizontal or vertical stretch or compression of the function by observing the equation of the function .

Answers

Bdbxbcjncnxndnsnns Identify a horizontal or vertical stretch or compression of the function by observing the equation of the function .hdbdbebqb
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