Increase 28 by 7 percent

Answers

Answer 1
Answer: 7 percent... 7 percent of what?

AnswerP 7 % of 28!

so we need to know what 7% of 28 is:

(7*28)/(100) =1.96.

After the increase:

28+1.96=29.96

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Help answer 1/5x-2/3y=30 when y = 15

Answers

The value of the variable x at y = 15 will be 200.

What is the solution to the equation?

The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.

The equation is given below.

(1/5)x - (2/3)y = 30

Solve the equation for x, then we have

(1/5)x = 30 + (2/3)y

x = 150 + (10/3) y

The value of the variable x at y = 15 will be

x = 150 + (10/3) × 15

x = 150 + 50

x = 200

The value of the variable x at y = 15 will be 200.

More about the solution of the equation link is given below.

brainly.com/question/545403

#SPJ2

\frac{1}5x-\frac{2}3y=30

Plug in 15 for y.

\frac{1}5x-\frac{2}3(15)=30

2/3 of 15 is 10.

\frac{1}5x-10=30

Add 10 to each side.

\frac{1}5x=40

Divide each side by 1/5.
(dividing by a fraction is the same as multiplying by its reciprocal...flip 1/5...×5)

\boxed{x=200}

Helppp please 4-6 !!!

Answers

Answer: -2 ( negative two)

How many triangles can be constructed with angles measuring 35º, 62º, and 83º?A. 0

B. 1

C. 2

D. an infinite number

Answers

B)OPTION B only 1 is your answer.

2(1/2q+1)=−3(2q−1)+8q+4 .

Answers

Answer:the answer is 7

Step-by-step explanation: 7d9wid9

During every soccer game that Ronald plays, he runs all over the field. In his last game, he played on a soccer field that was 69,300 square feet. There are 3 feet in a yard. What is the area, in square yards (sq yd), of the soccer field where Ronald played his last game? Group of answer choices 7,700 sq yd 23,100 sq yd 207,900 sq yd 623,700 sq yd

Answers

Answer:

The area of the soccer field where Ronald played his last game is 7,700 sq yd.

Step-by-step explanation:

From the question,

The area of the soccer field where Ronald played his last game was 69,300 square feet.

To determine the area, in square yards (sq yd), of the soccer field where Ronald played his last game, we will convert 69,300 square feet to square yards.

Also, from the question

There are 3 feet in a yard, that is, 3 feet = 1 yard

If 3 feet = 1 yard

∴ 3² square feet (ft²) will be equal to 1² square yard (yd²)

That is,

9 square feet = 1 square yard

Now,

If 9 square feet = 1 square yard

Then, 69,300 square feet will be

(69,300 square feet × 1 square yard) / 9 square feet = (69300/9 )square yards

= 7700 square yards (sq yd)

Hence, the area of the soccer field where Ronald played his last game is 7,700 sq yd.

Write an equation that is perpendicular to the line y = 2x + 13?

Answers

An equation can't be perpendicular to a line, but the graph of the equation can.

When that happens, we recall that the slopes of perpendicular lines are negative reciprocals.

One line is the graph of [ y = 2x + 13 ].  The slope of the line is 2 .
So the slope of a line perpendicular to it must be -1/2 .

The equation of a line perpendicular to it is:    y = (-1/2 x) plus (any number).

The y-intercept of the perpendicular line doesn't matter.  Only its slope does.
k:\ y=m_1x+b_1\ \ \ and\ \ \ l:\ y=m_2x+b_2\n\nk\perp l\ \ \ \Leftrightarrow\ \ \ m_1\cdot m_2=-1\n------------------------\n\nk:\ y=2x+13\ \ \ \ and\ \ \ \ l:\ y=m_2x+b_2\n\n2\cdot m_2=-1\ \ \ \Leftrightarrow\ \ \ m_2=- (1)/(2) \n\nl:\ y=- (1)/(2) x+b_2\ \ \ and\ \ \ b_2\ \in\ R\n\nfor\ example:\n\ny=- (1)/(2) x,\ \ \ y=- (1)/(2) x+5 (1)/(7) ,\ \ \ y=- (1)/(2)x - √(13)\ ,\ ...