The value of the variable x at y = 15 will be 200.
The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.
The equation is given below.
(1/5)x - (2/3)y = 30
Solve the equation for x, then we have
(1/5)x = 30 + (2/3)y
x = 150 + (10/3) y
The value of the variable x at y = 15 will be
x = 150 + (10/3) × 15
x = 150 + 50
x = 200
The value of the variable x at y = 15 will be 200.
More about the solution of the equation link is given below.
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B. 1
C. 2
D. an infinite number
Answer:the answer is 7
Step-by-step explanation: 7d9wid9
Answer:
The area of the soccer field where Ronald played his last game is 7,700 sq yd.
Step-by-step explanation:
From the question,
The area of the soccer field where Ronald played his last game was 69,300 square feet.
To determine the area, in square yards (sq yd), of the soccer field where Ronald played his last game, we will convert 69,300 square feet to square yards.
Also, from the question
There are 3 feet in a yard, that is, 3 feet = 1 yard
If 3 feet = 1 yard
∴ 3² square feet (ft²) will be equal to 1² square yard (yd²)
That is,
9 square feet = 1 square yard
Now,
If 9 square feet = 1 square yard
Then, 69,300 square feet will be
(69,300 square feet × 1 square yard) / 9 square feet = (69300/9 )square yards
= 7700 square yards (sq yd)
Hence, the area of the soccer field where Ronald played his last game is 7,700 sq yd.