Answer: A-B-C-E-G-K-H-I
Explanation:
Ok, we start at A.
16 pints = x gallons.
We know that:
1 pint = 0.125 al
then:
16pint = 16*(0.125gal) = 2 gal.
The second letter is B.
Now we have:
12,320 yd = X mi
And we know that:
1 mi = 1760 yd.
Then 12,320yd = (12,320/1760) mi = 7mi
the letter is C.
Now we have:
432 cups = X gals
and:
1 cup = 0.0625 gal
then 432 cups = 432*(0.0625 gal) = 27 gal.
The next letter is E.
Now we have:
1/4 ton = X pounds.
And 1 ton = 2000 pounds
then 1/4 ton = (1/4)*2000 pounds = 500 pounds
The next letter is G.
Now we have:
3.5 gal = X ounces.
and we know that:
1 gal = 128 oz
Then:
3.5 gal = 3.5*(128oz) = 448oz
The next letter is K.
Now we have:
1/2 day = x minutes.
and we know that:
1 day = 24*60 min = 1440 min
then 1/2 day = (1/2)*1440 min = 720 min.
The next letter is H.
Now we have:
360 in = x yd
And we know that:
1yd = 36 inches.
then 360 in = (360/36) = 10 yd.
The next letter is I
Now we have:
56 cups = x quarts.
and we know that;
1cup = 0.25 quart
then: 56 cups = 56*0.25 quart = 14
So here this ends.
Then the code is:
A-B-C-E-G-K-H-I
All points to the left of zero on a horizontal number line are negative
distance and the speed.
time and the direction.
direction and speed.
Answer:
direction and speed.
Explanation:
Answer: 3.4s
Explanation:
There are three stages in the motion of the ball, so you have to calculate the times for every stage.
1) Ball dropping from 9.5m: free fall
d = Vo + gt² / 2
Vo = 0 ⇒ d = gt² / 2 ⇒ t² = 2d / g = 2 × 9.5 m / 9.81 m/s² = 1.94 s²
⇒ t = √ (1.94 s²) = 1.39s
2) Ball rising 5.7m (vertical rise)
i) Determine the initial speed:
Vf² = Vo² - 2gd
Vf² = 0 ⇒ Vo² = 2gd = 2 × 9.81 m/s² × 5.7m = 111.8 m²/s²
⇒ Vo = 10.6 m/s
ii) time rising
Vf = Vo - gt
Vf = 0 ⇒ Vo = gt ⇒
t = Vo / g = 10.6 m/s / 9.81 m/s² = 1.08 s
3) Ball dropping from 5.7 m to 1.20m above the pavement (free fall)
i) d = 5.7m - 1.20m = 4.5m
ii) d = gt² / 2 ⇒ t² = 2d / g = 2 × 4.5 m / 9.81 m/s² = 0.92 s²
⇒ t = √ (0.92 s²) = 0.96s
4) Total time
t = 1.39s + 1.08s + 0.96s = 3.43s ≈ 3.4s
a.0.14 kg
b.0.37 kg
c.11.9 kg
d.21.82 kg
Answer:
a)0,14 kg
Explanation:
Formula to calculate the gravitational potential energy:
U= m *g*h : equation (1)
U: It's gravitational potential energy in Joules (J)
m: body mass in kilograms (kg)
g= the acceleration of gravity ()
h= the body heigt measured from the floor (m)
Known information:
U= 116.62 J
g = 9.8
h =85m
mass calculation:
We replace the known information in equation 1 :
116.62 = m*9.8*85
m =116.62/(9.8*85)
m= 0,14 kg
The mass of the ball is 0,14 kg
b temperature and pressure only
c. volume and temperature only
d. temperature, pressure, and volume
The combined gas law relates temperature, pressure, and volume and can be represented by the equation P1V1 / T1 = P2V2 / T2.
The combined gas law relates temperature, pressure, and volume. It states that the product of the initial pressure, volume, and temperature of a gas is equal to the product of the final pressure, volume, and temperature. This law can be represented by the equation:
P1V1 / T1 = P2V2 / T2
where P1 and P2 are the initial and final pressures, V1 and V2 are the initial and final volumes, and T1 and T2 are the initial and final temperatures.
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