PHYSICS HIGH SCHOOL

Determine the volume at the equivalence point if a 0.100 M NaOH(aq) solution is used to titrate the following acidic solutions: (a) 50.0 mL of 0.200 M HBr(aq) (b) 30.0 mL of 0.150 M HNO3(aq)

Answers

Answer 1

Answer:

Answer:

a) NaOH volume at the equivalence point is 100 ml.

b) NaOH volume at the equivalence point is 45 ml.

Explanation:

To calculate the concentration of acid, we use the equation given y neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid.

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base

a) If a 0.100 M NaOH (aq) solution is used to titrated with 50.0 mL of 0.200 M HBr(aq).

We are given:

$n_1=1\nM_1=0.200M\nV_1=50.0mL\nn_2=1\nM_2=0.100M\nV_2=?mL$

Putting values in above equation, we get:

$1* 0.200M* 50.0 mL=1* 0.100 M* V_2\n\nV_2=100 mL$

b) If a 0.100 M NaOH (aq) solution is used to titrated with 30.0 mL of 0.150 M $HNO_3$ (aq).

We are given:

$n_1=1\nM_1=0.150M\nV_1=30.0mL\nn_2=1\nM_2=0.100M\nV_2=?mL$

Putting values in above equation, we get:

$1* 0.150M* 30.0 mL=1* 0.100 M* V_2\n\nV_2=45 mL$

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Answers

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Explanation:

Given the following data

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