What is the pressure in atm exerted by 2.48 moles of a gas in a 250.0 ml container at 58c?
Answers
Explanation:
The given data is as follows.
V = 250.0 ml, T = 58^{o}C = 58 + 273 = 331 K
n = 2.48 moles, P = ? , R = 0.082 atm L /K mol
Therefore, calculate the pressure using ideal gas equation as follows.
PV = nRT
P =
=
= 0.269 atm
Thus, we can conclude that pressure of the given gas is 0.269 atm.
R = 0.082 atm
V = 250.0 mL / 1000 = 0.25 L
P = n x R x T / V
P = 2.48 x 0.082 x 331.15 / 0.25
P = 67.342 / 0.25
P = 269.368 atm
hope this helps!
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Decomposers
Primary consumers
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Answers
Answer:
Explanation:
The atomic number of zinc is 30, which means that the neutral atom has equal numbers of protons and electrons, so a neutral atom of zinc would have 30 electrons.
The electron configuration of a neutral zinc atom is 1s
2
2s
2
2p
6
3s
2
3p
6
3d
10
4s
2
.
The Zn
2+
ion has lost two electrons, which leaves it with 30 protons and 28 electrons.
The electron configuration of Zn
2+
is 1s
2
2s
2
2p
6
3s
2
3p
6
3d
10
.
Answers
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Explanation:
According to the melting points reported, at 5°C canola oil, whose melting point is 10°C, will freeze (become solid), while the other three, corn oil, sunflower oil, and peanut oil, having melting points several degrees below 5°C, will remain in liquid state.
Therefore, by decantation or filtration, which are processes that permit separate solids from liquids in a mixture, you can separate easily the solid canola oil from the other three liquid oils.
After separating the canola oil, If you continue cooling the mixture and reach a temperature of - 5°C. the peanut oil, whose melting point is -2°C, whill freeze and you will be able to separate it (again by decantation or filtration).
The same operation, cooling a third time until a temperature around 12°C, will permit you to separate the remaining two oils.
As you see, the knowledge of the physical properties of the substances is a useful tool to separate mixtures.