The Lewis structure for the molecule CH3CH2NH3+ (ethylammonium) showcases hydrogen atoms bonded to carbon and nitrogen atoms. The positive charge resides on the nitrogen atom.
The molecule CH3CH2NH3+ is also known as ethylammonium, a form of a substituted ammonium ion. The Lewis structure of this molecule can be drawn based on the concept that hydrogen has one bond, carbon has four bonds, and nitrogen has three bonds and one lone pair of electrons. The positive charge in CH3CH2NH3+ is located on the nitrogen atom.
Here’s a simple way to draw it:
1. Draw a C atom connected to three H atoms, signifying the CH3 group.
2. Draw another C atom bonded to the first C and two H atoms, signifying the CH2 group.
3. Draw the N atom connected to the second C and three H atoms, signifying the NH3 group.
4. Mark a + sign near the N atom to indicate the positive charge.
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B. Uranium
C. Lead
D. Thallium
Thallium has 81 protons in the nuclei of its atoms.
Answer: 2.93 L
Explanation:
AI-generated answer
To find the volume occupied by 0.108 mol of helium gas at a pressure of 0.909 atm and a temperature of 306 K, we can use the ideal gas law equation:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Rearranging the equation to solve for V:
V = (nRT) / P
Plugging in the given values:
n = 0.108 mol
R = 0.0821 L·atm/(mol·K) (the ideal gas constant)
T = 306 K
P = 0.909 atm
V = (0.108 mol * 0.0821 L·atm/(mol·K) * 306 K) / 0.909 atm
Calculating this expression, we find that the volume occupied by 0.108 mol of helium gas at a pressure of 0.909 atm and a temperature of 306 K is approximately 2.93 L.
Now, let's consider the second part of the question: Would the volume be different if the gas was argon (under the same conditions)?
The volume would be the same for argon gas.
According to the ideal gas law, at the same temperature, pressure, and number of moles, the volume occupied by a gas is the same regardless of the gas's identity. Therefore, if we replaced helium gas with argon gas while keeping the same conditions of pressure, temperature, and number of moles, the volume occupied by argon gas would be the same, approximately 2.93 L.
Answer:
covalent bonding, hydrogen bonding
Explanation:
The molecular formula of water is in which the two hydrogen atoms are connected to the oxygen atom via covalent bonds which means that the electrons are shared in the bond.
Hydrogen bonding is a special type of the dipole-dipole interaction and it occurs between hydrogen atom that is bonded to highly electronegative atom which is either fluorine, oxygen or nitrogen atom.
Partially positive end of the hydrogen atom is attracted to partially negative end of these atoms which is present in another molecule. It is strong force of attraction between the molecules.
Thus, when multiple water molecules are there, there are connected by hydrogen bonding.
(2) reduction (4) nuclear fusion
Answer:
Nuclear Fusion
Explanation:
In nuclear fusion two lighter nuclei combine together in order to form one heavier nucleus.
For example, the energy generated from the Sun is made by nuclear fusion: Two hydrogen (H, atomic number 1) nuclei combine in order to form one helium (He, atomic number 2) nucleus.
Nuclear fission is the opposite reaction, in which one heavier nucleus splits into two lighter nuclei.
o helium (He)
o hydrogen (H)
sodium (Na)
O argon (Ar)
Answer: helium(He)
Explanation: Helium has only 2 electrons in the outermost energy level, but all of the other elements in its column have eight.