b) mass percent sucralose:%?
The mass percentage of vitamin C is 74.5% and the mass percentage of sucralose is 25.5%.
Osmotic pressure (π) = iCRT
Where;
π = Osmotic pressure = 3.18 atm
i = Van't Hoff factor = 1 (molecular solution)
C = concentration (in mol/L)
R = gas constant = 0.082 LatmK-1mol-1
T = temperature = 287 K
But C = number of moles(n) /Volume (V)
volume = 41.1 mL or 0.0411 L
Substituting into the given equation;
π = n/V × RT
Make n the subject of the formula;
n = πV/RT
n = 3.18 atm × 0.0411 L/0.082 LatmK-1mol-1 × 287 K
n = 0.0056 moles
Mass of vitamin C = a
Mass of sucralose = b
Mass of sample = 1.149 g
Hence;
a + b = 1.149
b = 1.149 - a
Molar mass of vitamin C = 176 g/mol
Molar mass of sucralose = 398 g/mol
Total number of moles = number of moles of vitamin C + number of moles of sucralose
0.0056 moles = a/176 + (1.149 - a)/398
70048 ( 0.0056 ) = 398a + 176 (1.149 - a)
392.269 = 398a + 202.224 - 176a
392.269 - 202.224 = 398a - 176a
190.045 = 222a
a = 190.045/222
a = 0.856 g
But;
b = 1.149 - a
Where a = 0.856 g
b = 1.149 - 0.856
b = 0.293 g
Mass percent vitamin C = 0.856 g/1.149 g × 100/1
= 74.5%
Mass percent sucralose = 0.293/1.149 g × 100/1
= 25.5%
Learn more: brainly.com/question/14191541
Answer:
Heat capacity units: J/K
Explanation:
Heat capacity (C) is the amount of heat (Q) required to raise the temperature(T) of a substance by a unit degree.
It is usually expressed in terms of J/K
Heat capacity is an intensive property i.e. it is not dependent on the amount of the substance. i.e, the amount of heat required to raise the temperature of 1 g of copper per kelvin would be the same as that corresponding to 100 g.
Answer: 0.469 J / g°C
Explanation:
1) Data:
m = 0.158 kg
Q = 2,150.0 J
ΔT = 61.0°C - 32.0°C
Cs = ?
2) Formula:
Q = m×Cs×ΔT
3) Solution
i) Solve for Cs: Cs = Q / [m×ΔT]
ii) Plug in the data and compute
Cs = 2,150.0 J / [158 g × (61.0°C - 32.0°C) ] = 0.469 J / g°C