A triangle has one angel that measures 51 degrees and one angle that measures 39 degrees. what kind of triangle is it?

Answers

Answer 1

Answer: Those two angles are complementary - which means they both give us 90 degrees. We know that all three angles in any triangle must be exactly 180 degrees, so the third angle will be 180 - 90 = 90 degrees. It means that our triangle is a straight triangle. The figure will look more less like in the attachment.

Answer 2

Answer: it would be a acute because you would do 51+39=90 which u would do 180-90 which would equal 90 and a aucte is a 90 degree angle

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Find both unit rates.$8.40 for 8 ice-cream cones

A.
$0.95 per cone and 1.05 cones per dollar

B.
$1.05 per cone and 0.95 cones per dollar

C.
$2.10 per cone and 1.9 cones per dollar

D.
$1.90 per cone and 2.1 cones per dollar

Answers

$8.40 per eight cones is 8.40/8=1.05 dollars per cone and 8/8.4=.95 cones per dollar.

Find the slope for y = -x - 5 in slope intercept form

Answers

Answer:

Use the slope-intercept form to find the slope and y-intercept.

Slope: −1 y-intercept: (0,−5)

Step-by-step explanation:

PLEASE HELP PICTURE SHOWN

Answers

i think the answer is D.

Determine whether the triangle is acute, right, or obtuse given the sides: 11, 14, 20

Answers

Answer:

317 < 400

The Sum of the squares of the smaller 2 sides (121 + 196 = 317) < longest side squared (400) So, it is an OBTUSE SCALENE TRIANGLE.

Source: http://www.1728.org/triantest.htm

Step-by-step explanation:

Daniel wants to have a 90 average in his math class at the end of the year. He is trying to determine what he needs to get on his final exam, which accounts for 10% of his grade, for this to work. Tests are weighted 50% of the grade, and he currently has a 85 for his test average; quizzes are weighted 15% of his grade, and he currently has a 95 quiz average; homework is weighted 15% of his grade and he currently has a 98 homework average; and projects are weighted 10% of his grade and he currently has a 92 project average. What is the lowest whole percentage Daniel can make on his final exam for him to end up with a 90 in the class?

Answers

Exam + Tests + Quizzes + HW + Projects = 90

Exam = 10% * grade (x) = 0.1 * x

Tests = 50% * 85 = 0.5 * 85 = 42.5

Quizzes = 15% * 95 = 0.15 * 95 = 14.25

HW = 15% * 98 = 0.15 * 98 = 14.7

Projects = 10% * 92 = 0.1 * 92 = 9.2

Exam + Tests + Quizzes + HW + Projects = 90

(0.1 * x) + 42.5 + 14.25 + 14.7 + 9.2 = 90

(0.1 * x) + 80.65 = 90 (subtract 80.65 from each side)

(0.1 * x) = 9.35 (divide 0.1 from each side)

(0.1 * x)/0.1 = 9.35/0.1

x = 0.935

The answer is 93.5%

Answer:

d)94

Step-by-step explanation:

Find the missing endpoint given one endpoint and midpoint
endpoint-(6,-10) midpoint (-1,2)

Answers

$endpoint: \ ( x_(2),y_(2))= (6,-10) , \n midpoint : \(x,y)=(-1,2) \n\nMindpoint \ Formula : \n (x,y)=\left ( (x_(1)+x_(2) )/(2), \frac{y_ {1}+y_(2) }{2} \right )\n\n(-1,2)=\left ( (x_(1)+ 6 )/(2), \frac{y_ {1}-10 }{2} \right )$

$\begin{cases} (x_(1)+ 6 )/(2)= -1 \ \ /\cdot 2 \n \frac{y_ {1}-10 }{2} =2 \ \ / \cdot 2 \end{cases}\n\n\begin{cases} x_(1)+ 6 =-2 \n y_ {1}-10 =4 \end{cases}\n \n\begin{cases} x_(1) =-2-6 \n y_ {1} =4+10 \end{cases}\n \n\begin{cases} x_(1) =-8\n y_ {1} =14 \end{cases} \n \nAnswer : \ second \ endpoint : \ (x_(1),y_(1))=(-8,14)$

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