MATHEMATICS HIGH SCHOOL

Find sin(α+β) if cosα=35 , sinβ=−45 , α is in quadrant I and β is in quadrant III

Answers

Answer 1
Answer: Sin is about 4,.002 ........

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Solve the inequality 6x − 8 > 4x + 26.x < 9

x < 17

x > 9

x > 17

Answers

Answer:

The last option is the correct answer.

Step-by-step explanation:

The given inequality is :

6x-8>4x+26

Pairing the like terms together we have :

6x-4x>26+8

=> 2x>34

Now we will divide both sides by 2;

=> x>17

Thus, the answer is x>17.

The last option is the correct answer.
Hello,
Answer D (x>17)

6x-8>4x+26
==>6x-4x>26+8
==>2x>34
==>x>17

You have two boxes of colored pens. The first box contains a red pen, a blue pen, and a green pen. The second box contains a yellow pen, a red pen, and a black pen. What is the set that represents all the pens? a.{red pen, blue pen, green pen}
b.{red pen}
c.{red pen, red pen, green pen, yellow pen, black pen}
d.{red pen, blue pen, green pen, yellow pen, black pen}

Answers

Thank you for posting your question here. If you have a  two boxes of colored pens. The first box contains a red pen, a blue pen, and a green pen. The second box contains a yellow pen, a red pen, and a red pen, blue pen, green pen, yellow pen, black pen. The answer is D. I hope it helps. 

Answer:

d. {red pen, blue pen, green pen, yellow pen, black pen}

Step-by-step explanation:

Be

A = Colors of pens in the first box

B = Colors of pens in the second box

A = {red, blue, green}

B = {yellow, red, black}

D =? set that represents all the pens

In set theory, the union of two (or more) sets is an operation that results in another set, whose elements are the same as the initial sets, without repeating those that are the same.

Therefore, the set that represents all the pens is:

D = {red, blue, green, yellow, black}

Hope this helps!

Ryan bought a pack of gum for $0.89, a soda for $1.39, and a donut for $0.75 from the convenience store. How much was his total?A : $3.03
B : $2.03
C : $2.83
D : $1.83

Answers

Answer would be: A. $ 3.03

Exponential Form3.log 1/4 1=0
4.log 1/2 32= -5
Evaluate the logarithm
6. log27 3=
8. log 1/4 256=
9. log 10 .001=
10. log 64 2=

Answers

6. 1/3
8. -4
9. -3
10. 1/6
loga n=z  ⇔a^z=n

Therefore:
3)log 1/4  1=0    ⇔(1/4)⁰=1
4)log 1/2  32 -5  ⇔(1/2)⁻⁵=2⁵=32

6)
log 27  3=n  ⇔ 27^n=3 
27=3³
(3³)^n=3  ⇒n=1/3    (3³)¹/³=3³/³=3¹=3

Answer: log 27  3=1/3

7)
log1/4 256=n  ⇔(1/4)^n=256
256=2⁸=4⁴
(1/4)^n=4⁴  ⇒n=-4       [ (1/4)⁻⁴=4⁴=256  ]

Answer: log1/4 256=-4

9)
log 10  0.001=n  ⇔  10^n=0.001
0.001=10⁻³
10^n=10⁻³  ⇒n=-3

answer: log 10    0.001=-3

10)
log 64  2=n  ⇔64^n=2
64=2⁶
(2⁶)^n=2    ⇒2(⁶n)=2¹ ⇒  6n=1  ⇒  n=1/6

answer: log 64    2= 1/6

Solve.
1.5 - 0.25(a + 4)= 3 + 3(0.05 - 0.5a)

Answers

the answer should be 2.12 
Ok HI again but the answer should be -0.68 the steps are below!    Simplifying 5 + -0.25(a + 4) = 3 + 3(0.05 + -0.5a) Reorder the terms: 5 + -0.25(4 + a) = 3 + 3(0.05 + -0.5a) 5 + (4 * -0.25 + a * -0.25) = 3 + 3(0.05 + -0.5a) 5 + (-1 + -0.25a) = 3 + 3(0.05 + -0.5a) Combine like terms: 5 + -1 = 4 4 + -0.25a = 3 + 3(0.05 + -0.5a) 4 + -0.25a = 3 + (0.05 * 3 + -0.5a * 3) 4 + -0.25a = 3 + (0.15 + -1.5a) Combine like terms: 3 + 0.15 = 3.15 4 + -0.25a = 3.15 + -1.5a Solving 4 + -0.25a = 3.15 + -1.5a Solving for variable 'a'. Move all terms containing a to the left, all other terms to the right. Add '1.5a' to each side of the equation. 4 + -0.25a + 1.5a = 3.15 + -1.5a + 1.5a Combine like terms: -0.25a + 1.5a = 1.25a 4 + 1.25a = 3.15 + -1.5a + 1.5a Combine like terms: -1.5a + 1.5a = 0.0 4 + 1.25a = 3.15 + 0.0 4 + 1.25a = 3.15 Add '-4' to each side of the equation. 4 + -4 + 1.25a = 3.15 + -4 Combine like terms: 4 + -4 = 0 0 + 1.25a = 3.15 + -4 1.25a = 3.15 + -4 Combine like terms: 3.15 + -4 = -0.85 1.25a = -0.85 Divide each side by '1.25'. a = -0.68 Simplifying a = -0.68

Teresa stated that the heights of the students in her class were not a function of their ages. Which reasoning could justify Teresa’s statement?A.Two students are the same age but have different heights.
B.Two students have the same height but different ages.
C.No two students are the same age or height.

Answers

Answer:

Option: A is the correct answer.

A.  Two students are the same age but have different heights.

Step-by-step explanation:

The height of a student could not be a function of the ages of a student because two or more students with the same age may have the different heights .

This means that a value on a x-axis (i.e.  age) is mapped to two or more  values i.e. corresponding y-value ( i.e.  different heights) which violates the definition of function.

Hence, option: A is the correct answer.
i think it's a because basically saying their tall but not the it looks like
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