Complete and balance the equation for the following acid-base neutralization reaction. If water is used as a solvent, write the reactants and products as aqueous ions. In some cases, there may be more than one correct answer, depending on the amount of reactants used.(a)Mg(OH)2 + HClO4?
(b)SO3 + H2O? (Assume an excess of water and that the product dissolves)
(c) SrO + H2SO4?

Answers

Answer 1

Answer:

Explanation:

A balanced equation is defined as the one that has equal number of atoms of all the elements present on both reactant and product side.

(a) $Mg(OH)_(2) + HClO_(4) \rightarrow Mg(ClO_(4))_(2) + H_(2)O$

Number of atoms on reactant side are as follows.

Mg = 1

O = 6

H = 3

Cl = 1

Number of atoms on product side are as follows.

Mg = 1

O = 9

H = 2

Cl = 2

So, to balance this equation we multiply $Mg(OH)_(2)$ by 2 on reactant side and multiply $H_(2)O$ by 2 on product side.

Therefore, the balanced reaction equation is as follows.

$2Mg(OH)_(2) + HClO_(4) \rightarrow Mg(ClO_(4))_(2) + 2H_(2)O$

(b) $SO_(3) + H_(2)O \rightarrow H_(2)SO_(4)$

Number of atoms on reactant side are as follows.

S = 1

O = 4

H = 2

Number of atoms on product side are as follows.

S = 1

O = 4

H = 2

Therefore, this equation is balanced as it has same number of atoms on both reactant and product side.

(c) $SrO + H_(2)SO_(4) \rightarrow SrSO_(4) + H_(2)O$

Number of atoms on reactant side are as follows.

Sr = 1

O = 1

H = 2

S = 1

O = 4

Number of atoms on product side are as follows.

Sr = 1

O = 1

H = 2

S = 1

O = 4

Therefore, this equation is balanced.

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How many moles of argon are in 4.80x10^24 atoms of argon

Answers

Answer:

7.97 mol Ar

Explanation:

Use Avogadro's number to convert atoms to moles. This number is the number of atoms in one mole. There are 6.022 × 10²³ atoms in one mole.

Divide the number of atoms given by Avogadro's number.

(4.80 × 10²⁴)/(6.022 × 10²³) = 7.97 mol

There are 7.97 moles of argon.

Answer:

3.0 moles (A P E X)

Explanation:

If you perfom 30 joules of work lifting a 20-N box from the floor to a shelf how high is the shelf

Answers

Answer: 1.5 m

Explanation: E=mgh=Fh

30 J = 20 N * h

h = 30/20 = 1.5 m

Answer:

1.5 m

Explanation:

it just is its easy made A on test

Use the drop-down menus to answer the questions.Which organism begins this food chain and is a producer?
Which organism gains energy from eating the frog?
Which organism has the most available energy in this food chain?

Answers

Answer:

grass

snake

grass

Explanation:

just did it :)

Can you send a picture? That’s the only way I can see the problems

But, the producers should be on the bottom of the food chain, likely grass or something of the sort (plants)

If the frog has a line pointing to another organism, then that’s the organism that gains energy from eating it

Compound X has the formula C8H14.X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethylcyclohexane. Treatment of X with ozone follwed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O). What is the structure of X?

Answers

Answer:

Compound X has the formula C8H14.

X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethyl cyclohexane. Treatment of X with ozone followed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O). What is the structure of X?

Explanation:

The degree of unsaturation in the given molecule C8H14 is:

DU=(Cn+1)-Hn/2-Xn/2+Nn/2

where,

Cn=number of carbon atoms

Hn=number of hydrogen atoms

Xn=number of halogen atoms

Nn=number of nitrogen atoms

C8H14:

DU=(8+1)-14/2

=>DU=9-7 =2

Hence, the given molecule will have either two double bonds or one double bond and one ring or two rings.

X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethylcyclohexane.

This indicates that the molecule X has one double bond and one ring that is cyclohexane ring.

Treatment of X with ozone follwed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O).

So, the molecule has a ring and double bond CH2.

Based on the given data the structure of compound X is shown below:

The reaction sequence is shown below:

Final answer:

Compound X, with the formula C8H14, reacts with hydrogen to form 1,2-dimethylcyclohexane. When treated with ozone and zinc, it yields a ketone and formaldehyde. Therefore, the structure of X is 1,2-dimethylcyclohexane.

Explanation:

X is a compound with the formula C8H14. The reaction of X with hydrogen in the presence of a palladium catalyst produces a mixture of cis- and trans-1,2-dimethylcyclohexane. When X is treated with ozone followed by zinc in aqueous acid, it forms a ketone and formaldehyde (CH2=O).

This information tells us that compound X is a cycloalkane with two methyl groups. Since it reacts with hydrogen to form 1,2-dimethylcyclohexane, we know that X must have a cyclohexane ring with two methyl groups at the 1 and 2 positions. The cis and trans isomers of 1,2-dimethylcyclohexane have different arrangements of the methyl groups relative to each other.

Thus, the structure of compound X is 1,2-dimethylcyclohexane.

Learn more about Structure of Compound X here:

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The half-life of a pesticide determines its persistence in the environment. A common pesticide degrades in a first-order process with a rate constant of 6.5 1/hours. What is the half-life in hours of the breakdown reaction? Enter to 4 decimal places.

Answers

Answer:

0.1066 hours

Explanation:

A common pesticide degrades in a first-order process with a rate constant (k) of 6.5 1/hours. We can calculate its half-life (t1/2), that is, the times that it takes for its concentration to be halved, using the following expression.

t1/2 = ln2/k

t1/2 = ln2/6.5 h⁻¹

t1/2 = 0.1066 h

The half-life of the pesticide is 0.1066 hours.

The half-life of the breakdown reaction is 0.1066 h

The half-life of a substance is simply defined as the time taken for half of the original substance to decay.

The half-life of a first order reaction can be obtained by the following equation:

$t_(1/2) = (0.693)/(K)$

Where:

$t_(1/2)$ is the half-life

K is the decay constant

With the above formula, we can obtain the half-life of the breakdown reaction as follow:

Rate constant (K) = 6.5 h¯¹

Half-life ( $t_(1/2)$ ) =.?

$t_(1/2) = (0.693)/(K) \n\nt_(1/2) = (0.693)/(6.5)\n\nt_(1/2) = 0.1066 h$

Therefore, the half-life of the breakdown reaction is 0.1066 h

Learn more: brainly.com/question/24286055?referrer=searchResults

When the following redox equation is balanced with smallest whole number coefficients, the coefficient for Sn(OH)3– will be _____. Bi(OH)3(s) + Sn(OH)3–(aq) → Sn(OH)62–(aq) + Bi(s) (basic solution)

Answers

Answer:

The coefficient of $Sn(OH)_3^(-)$ is 3 in the balanced redox reaction.

Explanation:

Oxidation reaction is defined as the chemical reaction in which an atom loses its electrons. The oxidation number of the atom gets increased during this reaction.

$X\rightarrow X^(n+)+ne^-$

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

$X^(n+)+ne^-\rightarrow X$