Choose All correct statements about the crystal structure of materials Select one or more: a. Isotopic properties are the characteristics of polycrystalline materials. b. The crystal structure of metals is very complicated. c. Presence of various elements in the metallic crystal structures is the main contributor to its densely packed structure. d. Metal's crystalline structure tends to be densely packed. e. Anisotropic materials have their properties varying with the direction of measurement. f. The directional characteristic of metallic bonds is one of the reason for the densely packed crystalline structure of metals.

Answers

Answer 1

Answer:

Answer:

c. Presence of various elements in the metallic crystal structures is the main contributor to its densely packed structure

d. Metal's crystalline structure tends to be densely packed.

e. Anisotropic materials have their properties varying with the direction of measurement.

Explanation:

a. Isotopic properties are the characteristics of polycrystalline materials.

False because crystalline solids are anisotropic in nature because some properties like refractive index change in different direction in crystalline solids .

b. The crystal structure of metals is very complicated

false - crystalline solids have fixed and ordered pattern. so it has simple structure .

c. false - there is only one element . packed structure is because of short bond length .

d. true - metals are closely packed and in order manner

e. true - they have different properties in all direction like electrical conductivity and refractive index

f. False - metallic bonds are indirectional in nature .

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An element is to a __ as an organ is to a ___

Answers

An element is to an atomas an organ is to a cell. Just as atoms are the fundamental building blocks of elements, cells are the basic units of living organisms.

Elements are composed of atoms, each characterized by a specific number of protons, neutrons, and electrons.

Similarly, organs are composed of cells, each with specialized structures and functions that collectively contribute to the overall function of the organ.

The analogy highlights the hierarchical organization of matter and life, emphasizing how complex structures are formed from simpler components.

Just as elements combine to create diverse substances, cells come together to form intricate organs essential for life processes.

Know more about organs:

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Answer:

An element is to a compound as an organ is to tissue

Explanation:

Treatment of (S)-( )-5-methyl-2-cyclohexenone with lithium dimethylcuprate gives, after protonolysis, a good yield of a mixture containing mostly a dextrorotatory ketone A and a trace of an optically inactive isomer B. Treatment of A with zinc amalgam and HCl affords an optically active, dextrorotatory hydrocarbon C. Identify compounds A, B, and C, including stereochemical configurations. Be sure to explicitly draw H and both wedge/dash bonds at any configuration center.

Answers

Answer:

use google and use the first link

Explanation:

Final answer:

Treatment of (S)-( )-5-methyl-2-cyclohexenone with lithium dimethylcuprate followed by protonolysis produces dextrorotatory ketone A and a trace of isomer B. Compound A can yield optically active, dextrorotatory hydrocarbon C when treated with zinc amalgam and HCl.

Explanation:

Treatment of (S)-( )-5-methyl-2-cyclohexenone with lithium dimethylcuprate followed by protonolysis yields a mixture containing primarily a dextrorotatory ketone A and a trace of an optically inactive isomer B. Compound A can be treated with zinc amalgam and HCl to produce an optically active, dextrorotatory hydrocarbon C.

To provide a specific identification and stereochemical configuration of compounds A, B, and C, I would need additional information or further context about the starting components and reaction conditions, as well as any other relevant data or observations.

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Wich substances is most likely to form in a precipitation reaction?

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Answer:

A precipitation reaction refers to the formation of an insoluble salt when two solutions containing soluble salts are combined. The insoluble salt that falls out of solution is known as the precipitate, hence the reaction's name.

Explanation:

What is the maximum mass in grams of NH3 that can be produced by the reaction of of 2.5 g N2 with 2.5 g of H2 via the equation below?N2 (g) + 3 H2 (g) → 2 NH3 (g)

Answers

Answer: The mass of $NH_3$ produced is, 3.03 grams.

Explanation : Given,

Mass of $N_2$ = 2.5 g

Mass of $H_2$ = 2.5 g

Molar mass of $N_2$ = 28 g/mol

Molar mass of $H_2$ = 2 g/mol

First we have to calculate the moles of $N_2$ and $H_2$ .

$\text{Moles of }N_2=\frac{\text{Given mass }N_2}{\text{Molar mass }N_2}=(2.5g)/(28g/mol)=0.089mol$

and,

$\text{Moles of }H_2=\frac{\text{Given mass }H_2}{\text{Molar mass }H_2}=(2.5g)/(2g/mol)=1.25mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

From the balanced reaction we conclude that

As, 1 mole of $N_2$ react with 3 mole of $H_2$

So, 0.089 moles of $N_2$ react with $0.089* 3=0.267$ moles of $H_2$

From this we conclude that, $H_2$ is an excess reagent because the given moles are greater than the required moles and $N_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NH_3$

From the reaction, we conclude that

As, 1 mole of $N_2$ react to give 2 mole of $NH_3$

So, 0.089 mole of $N_2$ react to give $0.089* 2=0.178$ mole of $NH_3$

Now we have to calculate the mass of $NH_3$

$\text{ Mass of }NH_3=\text{ Moles of }NH_3* \text{ Molar mass of }NH_3$

Molar mass of $NH_3$ = 17 g/mole

$\text{ Mass of }NH_3=(0.178moles)* (17g/mole)=3.03g$

Therefore, the mass of $NH_3$ produced is, 3.03 grams.

To test Döbereiner’s idea, predict:(a) The boiling point of HBr from the boiling points of HCl (- 84.9°C) and HI (-35.4°C) (actual value = -67.0°C)
(b) The boiling point of AsH₃ from the boiling points of PH₃ (- 87.4°C) and SbH₃ (-17.1°C) (actual value = -55°C)

Answers

Answer:

a) Approximate boiling point of HBr = -60.15 °C

b) Approximate boiling point of AsH₃ = -52.25 °C

Explanation:

Döbereiner stated that some elements could be arranged in groups of 3 similar elements ( known as "triads) , and the element of the middle ( elements are ordered with respect to their atomic mass) would have properties between the other 2 ( the average value)

a) In the first case the triad would be the halogen triad ( Cl , Br and I ) . And according to Döbereiner , the boiling point of HBr should be the average of HCl and HI . Therefore

Approximate boiling point of HBr = [(- 84.9°C) + (-35.4°C)]/2 = -60.15 °C

b) Simmilarly for AsH₃ , PH₃ and SbH₃ , the boiling point of AsH₃ would be

Approximate boiling point of AsH₃ = [(- 87.4°C) + (-17.1°C)]/2 = -52.25 °C

Which enzymes show very broad substrate specificity and can therefore be used to produce several higher alcohols.Select one:

a. 2-keto acid decarboxylase AND alcohol dehydrogenase
b. alcohol dehydrogenase
c. transaminase
d. acetolactate synthasee. 2-ketoacid decarboxylase

Answers

Answer:

A. 2-keto acid decarboxylase and alcohol dehydrogenase

Explanation:

2-keto acid decarboxylase and alcohol dehydrogenase are used to produce many higher alcohols. These enzymes also display a high degree of specificity on their substrate

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