Wave X has an amplitude of 5 and wave Y has an amplitude of 4. What will happen when the crest of wave X meets the crest of wave Y?A crest with an amplitude of 1 will form.
A trough with an amplitude of 1 will form.
A crest with an amplitude of 9 will form.
A trough with an amplitude of 9 will form.

Answers

Answer 1
Answer:

Answer: A crest with an amplitude of 9 will form.

Explanation:

From super position principle, we know that when two waves move in same medium meet, then the net amplitude of the super imposed waves is sum of amplitudes of individual waves.

A constructive superposition takes place when crest meets crest and crest is formed of higher amplitude or trough meets trough and forms trough of higher amplitude. A destructive superposition takes place when crest of one meets trough of other -a crest or trough can form depending on the larger amplitude of either.

In the given situation, crest of wave X meets crest of wave Y. The amplitude of the super imposed wave would be = 5 + 4 = 9 and a crest would form.

Answer 2
Answer: The right answer for the question that is being asked and shown above is that: "A crest with an amplitude of 9 will form." Wave X has an amplitude of 5 and wave Y has an amplitude of 4. the crest of wave X meets the crest of wave Y is that A crest with an amplitude of 9 will form.

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Use the H-R diagram to answer the following questions.What is the approximate temperature of the supergiant Betelgeuse?

Which star on this diagram is the most similar to the Sun in luminosity and temperature?

Answers

Answer: The answer is 3000 K and Centauri A.

Explanation:

Just did it and got it right ♡´・ᴗ・`♡

Answer:

What is the approximate temperature of the supergiant Betelgeuse?  

3000 K

Which star on this diagram is the most similar to the Sun in luminosity and temperature?

Centauri A

Given two metal balls (that are identical) with charges LaTeX: q_1q 1and LaTeX: q_2q 2. We find a repulsive force one exerts on the other to be LaTeX: 1.35\times10^{-4}N1.35 × 10 − 4 N when they are 20 cm apart. Accidentally, one the the experimenters causes the balls to collide and then repositions them 20 cm apart . Now the repulsive force is found to be LaTeX: 1.406\times10^{-4}N1.406 × 10 − 4 N. What are the initial charges on the two metal balls?

Answers

Answer:

q_1=\pm0.03 \mu C and q_2=\pm0.02 \mu C.

Explanation:

According to Coulomb's law, the magnitude of  force between two point object having change q_1 and q_2 and by a dicstanced is

F_c=(1)/(4\pi\spsilon_0)(q_1q_2)/(d^2)-\;\cdots(i)

Where, \epsilon_0 is the permitivity of free space and

(1)/(4\pi\spsilon_0)=9*10^9 in SI unit.

Before  dcollision:

Charges on both the sphere are q_1 and q_2, d=20cm=0.2m, and F_c=1.35*10^(-4) N

So, from equation (i)

1.35*10^(-4)=9*10^9(q_1q_2)/((0.2)^2)

\Rightarrow q_1q_2=6*10^(-16)\;\cdots(ii)

After dcollision: Each ephere have same charge, as at the time of collision there was contach and due to this charge get redistributed which made the charge density equal for both the sphere t. So, both have equal amount of charhe as both are identical.

Charges on both the sphere are mean of total charge, i.e

(q_1+q_2)/(2)

d=20cm=0.2m, and F_c=1.406*10^(-4) N

So, from equation (i)

1.406*10^(-4)=9*10^9(\left((q_1+q_2)/(2)\right)^2)/((0.2)^2)

\Rightarrow (q_1+q_2)^2=2.50*10^(-15)

\Rightarrow q_1+q_2=\pm5* 10^(-8)

As given that the force is repulsive, so both the sphere have the same nature of charge, either positive or negative, so, here take the magnitude of the charge.

\Rightarrow q_1+q_2=5* 10^(-8)\;\cdots(iii)

\Rightarrow q_1=5* 10^(-8)-q_2

The equation (ii) become:

(5* 10^(-8)-q_2)q_2=6*10^(-16)

\Rightarrow -(q_2)^2+5* 10^(-8)q_2-6*10^(-16)=0

\Rightarrow q_2=3*10^(-8), 2*10^(-8)

From equation (iii)

q_1=2*10^(-8), 3*10^(-8)

So, the magnitude of initial charges on both the sphere are 3*10^(-8) Coulombs=0.03 \mu C and 2*10^(-8) Colombs or 0.02 \mu C.

Considerion the nature of charges too,

q_1=\pm0.03 \mu C and q_2=\pm0.02 \mu C.

What is the definition for distance?

Answers

distance is an amount of space between two things or people

5.0 Points The blue color of the sky is the result ofa. conduction.
b. scattering.
c. reflection.
d. absorption.

Answers

The blue color of the sky is the result of scattering. The answer is letter B. it is specifically called the Rayleigh scattering. This blue color is the result of the incoming rays of the Sun into the earth’s atmosphere. It has he lowest wavelength which as we all see is the blue spectrum of light.

The photos of an electromagnetic wave us 1. 5 × 10^-24 j of energy , what kind of electromagnetic waves are they ?

Answers

The electromagnetic waves with an energy of 1.5 * 10^(-24)  J are likely X-rays.

The energy of an electromagnetic wave is related to its frequency and wavelength by the equation:

E = hf = hc/λ

where:

E = energy of the electromagnetic wave

h = Planck's constant (6.626 * 10^(-34)  J s)

f = frequency of the electromagnetic wave

c = speed of light (3.00 * 10^8 m/s)

λ = wavelength of the electromagnetic wave

Solving for λ:

λ = hc/E = (6.626 * 10^(-34)  J s)(3.00 * 10^8 m/s)/(1.5 * 10^(-24)  J)

λ ≈ 4.40 * 10^-8 m

This corresponds to a wavelength of about 44 nanometers, which falls in the range of X-rays. Therefore, the electromagnetic waves with an energy of 1.5 * 10^(-24)  J are likely X-rays.

for such more question on electromagnetic Wave

brainly.com/question/25847009

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A typical carbon atom has six protons, six neutrons, and six electrons. Which of these has the least amount of mass?A) one Proton
B) one Neutron
C) six Electrons
D) These masses are too tiny to measure

Answers


One proton or one neutron have very close to the same mass.

Their mass is about the same as the mass of 1,840 electrons !
So six electrons have roughly the same mass as 0.0033 of one
proton or one neutron.

Yes, these masses are very tiny.  None of them was ever measured
until the 20th Century.  But all of them have now been measured,
very precisely and accurately.  This is very impressive, and should
give us a lot of admiration for scientists of the past hundred years.
It would be very interesting to look around online and find out
how they did it.