What's the measure of an arc with a central angle of 90°? question 20 options: 1) π° 2) 90° 3) 360° 4) 180°

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Answer 1

Answer: The measure of an arc with a central angle of 90° is 90°. So the correct answer is 2) 90°.

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It takes 167 kJ of work to accelerate a car from 20.9 m/s to 27.9 m/s. What is the car's mass?

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Answer:

space without opposite should be served

Kepler found that the orbits of the planets were _____. circular amorphous oval elliptical

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Answer:

elliptical

Explanation:

Nicolaus Copernicus gave the heliocentric theory that sun is at the center if the solar system and all the planets and the moons revolved wound it. according to him, the planets revolved around the sun in circular paths.

But Kepler suggested a different shape of the orbit. According to the laws o planetary motion given by Kepler, the planets revolve around the sun in an elliptical orbit. The sun is at one of its focus.

Kepler found that the orbits of the planets were elliptical.
His work was so convincing that to this day, they still are.

Just after a motorcycle rides off the end of a ramp and launches into the air, its engine is turning counterclockwise at 8325 rev/min. The motorcycle rider forgets to throttle back, so the engine's angular speed increases to 12125 rev/min. As a result, the rest of the motorcycle (including the rider) begins to rotate clockwise about the engine at 4.2 rev/min. Calculate the ratio IE/IM of the moment of inertia of the engine to the moment of inertia of the rest of the motorcycle (and the rider). Ignore torques due to gravity and air resistance.

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Answer:

$(Ie)/(lm) = 1.10*10^(-3)$

Explanation:

GIVEN DATA:

Engine operating speed nf = 8325 rev/min

engine angular speed ni= 12125 rev/min

motorcycle angular speed N_m= - 4.2 rev/min

ratio of moment of inertia of engine to motorcycle is given as

$(Ie)/(lm) = (-N)/((nf-ni))$

$(Ie)/(lm) = (-(-4.2))/((12125 - (8325)))$

$(Ie)/(lm) = 1.10*10^(-3)$

Answer: $1.105* 10^(-3)$

Explanation:

Given

Initial angular speed of engine( $\omega _E$ )=8325 rpm

Final angular speed of engine( $\omega _E_f$ )=12125 rpm

Initial angular speed of Motorcycle( $\omega _M$ )=0 rpm

Final angular speed of engine( $\omega _M_f$ )=4.2 rpm

as there is no external torque therefore angular momentum remains conserved

$I_E\omega _E+I_M\omega _M=I_E\omega _E_f+I_M\omega _M_f$

$I_E\omega _E+=I_E\omega _E_f+I_M\omega _M_f$

$I_E\left ( \omega _E-\omega _E_f\right )=I_M\omega _M_f$

$(I_E)/(I_M)=(\omega _M_f)/(\omega _E-\omega _E_f)$

$(I_E)/(I_M)=(-4.2)/(8325-12125)=0.0011052\approx 1.105* 10^(-3)$

The atomic number of an element is equal to the number of _____ contained in one atom of that element.

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the atomic number of an element is equal to the number of protons in an atom

What is the magnitude of the force a 1.5 x 10-3 C charge exerts on a 3.2 x 10-4 C charge located 1.5 m away?

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The magnitude of the force a 1.5 x 10-3 C charge exerts on a 3.2 x 10-4 C charge located 1.5 m away is 1920 Newtons. The formula used to solve this problem is:

F = kq1q2/r^2

where:
F = Electric force, Newtons
k = Coulomb's constant, 9x10^9 Nm^2/C^2
q1 = point charge 1, C
q2 = point charge 2, C
r = distance between charges, meters

Using direct substitution, the force F is determined to be 1920 Newtons.

The collision of two plates causes the formation of

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the collision of two plates causes the formation of MOUNTAINS

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