Answer:
A' will coincide with C of the pre image, and B' will coincide with D of the pre image.
Step-by-step explanation:
A Regular Hexagon could be imagined as a circle divided into six points on the circle, that are separated by angles of 60° (notice that 6 times 60° is 360°).
Now we name each point as ABCDEF clockwise, and then we rotate the hexagon about its center (counterclockwise)... the original points ABCDEF are renamed as A'B'C'D'E'F' in the rotated hexagon.
As the rotation was of 240°, the points will coincide with some of the original points: point A will "jump" for points, the same as point B.
This means that point A rotated, (wich is A') will coincide with point C pre rotated, and that point B rotated, (wich is B') will coincide with point D pre rotated.
B) 6 seconds
C) 1.5 seconds
D) 3 seconds
So this question is asking for the zeros, or the x-intercepts, of this equation. For this, we have to set h(t) to zero to solve for it.
For this, we will be using the quadratic formula, which is (a = t^2 coefficient, b = t coefficient, and c = constant). In this case, our equation is . From here we can solve for t.
Since we cannot have negative time,the object hits the ground at 3 seconds, or D.
Answer:
2 is the answer
Step-by-step explanation:
(2, -5) and (7, -10)
**check picture below**