1235678 has how many tens in it? how many hundreds in it? and how many thousands? explain

Answers

Answer 1

Answer: My guess:
It has 7 tens because the 7 is in the tenths place.
It has 6 hundreds in it because a 6 is in the hundredths place.
And 5 thousands because a 5 is in the thousandths place.

My second mathematical guess:
123,567.8 tens because 12345678 divided by ten is that.
123456.78 hundredths because ^^^hundreds
12345.678 thousandths because^^^ thousands
Or another explanation for my second guess is each 0 it has in it is another decimal place moved to the left of the digits 12345678.

Hahaha hope I helped. It's just a guess. Lol

Answer 2

Answer: 7 tens, 6 hundreds, and 5 thousands.

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Which of the following is the greatest common factor of the terms 48s5t3u2 and 40s3tu4?a. 6s2t2u
b. 6s3tu
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d. 8s3tu2

Answers

Answer: Option 'd' is correct.

Step-by-step explanation:

Since we have given that

$48s^5t^3u^2\ and\ 40s^3tu^4$

We need to find the greatest common factor of the above terms:

$48s^5t^3u^2=2* 2* 2* 2* 3* s^5* t^3* u^2\n\nAnd,\n\n40s^3tu^4=2* 2* 2* s^5* t* u^4\n\nGreatest\ common\ factor=2^3* s^3* t* u^2=8s^3tu^2$

Hence, Option 'd' is correct.

48s^5t^3u^2 = 8s^3tu^2 * 6s^2t^2

40s^3tu^4 = 8s^3tu^2 * 5u^2

Answer: D: 8 s^3 t u^2

F(x) = 4x^2 - 3x + 2kx + 1 What's the value of k for which the function has two zeros??
Can someone show me step by step?

Answers

$f(x)=4x^2-3x+2kx+1=4x^2+(2k-3)x+1\n\na=4;\ b=2k-3;\ c=1\n\nfunction\ has\ two\ zeros\ when\ \Delta=b^2-4ac > 0\n\n\Delta=(2k-3)^2-4\cdot4\cdot1=4k^2-12k+9-16=4k^2-12k-7 > 0\n\na_k=4;\ b_k=-12;\ c_k=-7\n\n\Delta_k=(-12)^2-4\cdot4\cdot(-7)=144+112=256\n\nk_1=(-b_k-√(\Delta_k))/(2a_k);\ k_2=(-b_k+√(\Delta_k))/(2a_k)$

$√(\Delta_k)=√(256)=16\n\nk_1=(12-16)/(2\cdot4)=(-4)/(8)=-(1)/(2);\ k_2=(12+16)/(2\cdot4)=(28)/(8)=(7)/(2)\n\na_k=4 > 0\ (up\ parabola\ arms-see\ the\ picture)\n\nAnswer:k\in(-\infty;-(1)/(2))\ \cup\ ((7)/(2);\ \infty)$

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Answers

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Having trouble with trigonometry , please help.

CSCx (1 + SINx) = 1 + CSCx

prove the identity

Answers

Remember that the cosecant is the reciprocal of the sine. CSC(x) = 1/SIN(x).

Now operate on the left side, and see if you can make it look like the right side:

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Substitute for CSCx :

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Multiply them:

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which is the same as 1/SINx + 1
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Answers

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Answers

During meiosis I, homologous chromosomes are pulled apart to produce two daughter cells. These daughter cells then divide again in meiosis II, only now it is the sister chromatids that are split apart. The ploidy of the daughter cells is less than the ploidy of the parent cells, thus resulting in diploid parent cells and haploid daughter cells.

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