What is the square root of 38.7

Answers

Answer 1

Answer:

Answer:

6.220932406

Why on Earth would you need that??

Related Questions

On August 8, 1981, American Savings offered an insured tax-free account paying 23.24% compounded monthly. If you had invested $90,000 at that time, how much would you have on August 8, 2014, assuming that you could have locked the interest rate at the time of deposit? Someone please help me!!
In the xy-plane, the point (p,r) lies on the line with equation y=x+b, where b is a constant. The point with coordinates (2p,5r) lies on the line with equation y=2x+b. If p≠0, what is the value of r/p?
8 gallons equals how many pints? a. 2 pt. b. 128 pt. c. 32 pt. d. 64 pt.
What is the basic unit of weight in the metric system
A martini glass has the shape of a cone (on a stem). If 1cm^3 =1mL, how many milliliters of liquid can the glass hold. Use x=3.14 (10.9 cm left to right) and (4.8cm top to bottom)

The difference between the highest and lowest single game point totals for the MIDDLE HALF of the data is ______ points less for Joe's data than Sam's data. Therefore, the MIDDLE HALF of Joe's single game point totals are less varied than Sam's.

Answers

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the required data to answer the question are missing.

However, the interpretation of the question is to determine the interquartile range (IQR) of a certain dataset.

Then get the difference between the calculated IQR & Joe's data and also the difference between the calculated IQR & Sam's data

Then, make comparison

To do this, I will use the following assumed datasets.

$Data: 62, 63, 64, 64, 70, 72, 76, 77, 81, 81$

IQR is calculated as:

$IQR = Q_3 - Q_1$

$Q_3$ is $the\ median$ of the upper half

$Q_1$ is $the\ median$ of the lower half

For Joe, we have:

$Lower\ half: 62, 63, 64, 64, 70$

$Upper\ half: 72, 76, 77, 81, 81$

The median is then calculated as:

$M = (N + 1)/(2)$

For, the lower half:

$Q_1 = (5 + 1)/(2) = (6)/(2) = 3rd$

So:

$Q_1 = 64$

For the upper half:

$Q_3 = (5 + 1)/(2) = (6)/(2) = 3rd$

So:

$Q_3 = 77$

When the same process is applied to Sam's data,

$Q_1 = 52$

$Q_3 = 58$

$IQR = Q_3 - Q_1$

$IQR = 77 - 64$

$IQR = 13$

Assume that:

$Joe = 60$

$Sam = 65$

$Joe - IQR = 60 - 13 = 47$

$Sam- IQR = 65- 13 = 52$

Hence, the IQR is 47 points less for Joe's data than Sam's

the hypotenuse of a right triangle is 16 and one of the angle is 45 . find the length of the side opposite to that angle ?

Answers

In a 90 45 45 triangle, the 2 legs each have a
length = hypotenuse / square root of 2
length = 16 / square root of 2
length =16 / 1.4142135624
length =11.313708499

What is the factored form of the polynomial z² − 10z + 25?

Answers

Answer:

( z - 5 ) ( z - 5 )

Step-by-step explanation:

z² − 10z + 25

= z² − 5z - 5z + 25

= z ( z - 5 ) - 5 ( z - 5 )

= ( z - 5 ) ( z - 5 )

Which equation represents a line which is parallel to the line 4y-3x=-8

Answers

Answer:

y=3/4x

Step-by-step explanation:

Answer:

-8y+6x=-8

Step-by-step explanation:

Can't promise this is 100% correct, but I tried.

-4(-2)+(-12)÷(+3)+-20+(+4)+(-6)

Answers

Answer:

-18

Step-by-step explanation:

-4(-2)+(-12)÷(+3)+-20+(+4)+(-6). [B.E.D.M.A.Srule](Firstbracket)

= 8 - 12 ÷ 3 - 20 + 4 - 6. (Thendivision)

= 8 - 4 - 20 + 4 - 6. (Thenafteraddition)

= 8 + 4 - 4 - 20 - 6

= 12 - 30. (Atlastsubtraction)

= -18 (Ans)

Answer:

-18

Step-by-step explanation:

$-4(-2)+((-12))/(+3)-20+(+4)+(-6)=8-(12)/(3)-20+4-6=8-4-20+4-6=-18$

Given the Vertices of ΔABC are A (2, -5,) B (-4, 6) and C (3, 1), find the vertices following each of the transformations FROM THE ORIGINAL vertices :(I honestly have no idea what to do and I really need help with this one)

Answers

Answer:

I. A' = (5,-5), B' = (-1,6), C' = (6,1)

II. A' = (5,-11), B' = (-1,0), C' = (6,-5)

III. A' = (-5,-2), B = (6,4), C' = (1,-3)

Step-by-step explanation:

We are given the vertices of ΔABC as A = (2,-5), B = (-4,6) and C = (3,1).

I. It is required to 'reflect the triangle about the line x= 3'.

This rule changes (x,y) to (x+3,y).

So, the new vertices are given by,

A' = (2+3,-5) = (5,-5)

B' = (-4+3,6) = (-1,6)

C' = (3+3,1) = (6,1)

II. It is required to 'translate the triangle 3 units to the right and 6 units down'.

This rule changes (x,y) to (x+3,y-6).

So, the new vertices are given by,

A' = (2+3,-5-6) = (5,-11)

B' = (-4+3,6-6) = (-1,0)

C' = (3+3,1-6) = (6,-5)

III. It is required to 'rotate the triangle by 90° about the origin counter-clockwise'.

This rule changes (x,y) to (y,-x).

So, the new vertices are given by,

A = (2,-5) implies A' = (-5,-2)

B = (-4,6) implies B = (6,4)

C = (3,1) implies C' = (1,-3)

Other Questions

Lara constructed angle POQ and then used a compass and straightedge to accurately construct line segment OS, as shown in the figure below:Which could be the measures of angle POS and angle POQ?

Which of the following formulas would find the lateral area of a right cylinder with height equal to h and r as the radius?A. LA = 2r2 B. LA = 2r C. LA = 2rh D. LA = 2r2 + 2rh

The expression 4x gives the perimeter of a square with a side length of x units.What is the perimeter of a square with a side length of 5/7 units?

Help me factor the trinomial completely-r^2+6r-9