Consider the daily market for hot dogs in a small city. Suppose that this market is in long-run competitive equilibrium with many hot dog stands in the city, each one selling the same kind of hot dogs. Therefore, each vendor is a price taker and possesses no market power.

Answers

Answer 1

Answer:

The graph show\ing the demand (D) and supply (S = MC) curves in the market for hot dogs indicate: Competitive market.

Competitive market

In a market were their is competition, when demand and supply curves intersect this indicate market equilibrium.

Based on the graph the market equilibrium price will be $1.50 per hot dog while on the other hand the market equilibrium quantity will be 250 hot dogs which is the point were demand and supply intersect.

Inconclusion the market for hot dogs indicate: Competitive market.

Learn more about competitve market here:brainly.com/question/25717627

Answer 2

Answer:

Answer:IF each vendor has his own price or (ppower) so far every single vendor will have his own price.

Step-by-step explanation:

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A CPU manufacturer is interested in studying the relationship between clock speed and the operating temperature that results at that clock speed for a particular CPU model. Let x be the clock speed in MHz and let Y be the temperature in ^{\circ}C . The following data was collected:i xi yi1 350 31.42 360 35.63 370 41.84 380 51.05 390 56.86 400 62.87 410 67.4a) Find the equation of the regression line.b) Estimate the temperature for clock speed x = 430 MHz.c) Find the 95% confidence interval for \beta .d) Compute the coefficient of determination R^{2} ?. Is this a high quality fit?
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A random sample of size 13 is selected from men with hypertension. For each person, systolic blood pressure was measured right before and one hour after taking the medicine. The mean reduction of the blood pressures was 10.1 and the standard deviation of the difference was 11.2. Test if there is sufficient evidence to conclude that the hypertension medicine lowered blood pressure. What is the value of the test statistic (round off to second decimal place)

Answers

Answer:

Yes, hypertension drugs lowers blood pressure.

Step-by-step explanation:

Claim: The hypertension medicine lowered blood pressure.

The null and alternative hypothesis is

H0:\mu_{d}\geq 0

H1:\mu_{d}< 0

Level of significance = 0.05

Sample size = n = 13

Sample mean of difference = \bar{d} = 10.1

Sample standard deviation of difference = s_{d} = 11.2

Test statistic is

t=\frac{\bar{d}}{s_{d}/\sqrt{n}}

t = ((10.1) / (11.2 /squre root of 13)) = 3.251

Degrees of freedom = n - 1 = 13 - 1 = 12

Critical value =2.179( Using t table)

Test statistic | t | > critical value we reject null hypothesis.

In Conclusion: The hypertension medicine lowered blood pressure

If f(x) = 7 sin x + 10 cos x,

Answers

Answer:

7+1x=8, 8+10 =x18 is your answer

A random survey of teachers found that 224 of 395 elementary school teachers, and 126 of 266 high school teachers, were very satisfied with their work. Find a 95% confidence interval for the difference (elementary minus high school) in proportions of teachers who are very satisfied with their work.

Answers

Answer: 95% confidence interval would be (0.013,0.167).

Step-by-step explanation:

Since we have given that

survey of teachers found that 224 of 395 elementary school teachers,

So, n₁ = 395

x₁ = 224

So, $p_1=(224)/(395)=0.567$

n₂ = 266

x₂ = 126

So, $p_2=(x_2)/(n_2)=(126)/(266)=0.473$

At 95% confidence level, z = 1.96

So, interval would be

$(p_1-p_2)\pm z\sqrt{((p_1(1-p_1))/(n_1)+(p_2(1-p_2))/(n_2)}}\n\n=(0.567-0.473)\pm 1.96\sqrt{(0.567* 0.433)/(395)+(0.527* 0.473)/(266)}}\n\n=0.09\pm 1.96* 0.0394\n\n=0.09\pm 0.077\n\n=(0.09-0.077,0.09+0.077)\n\n=(0.013,0.167)$

Hence, 95% confidence interval would be (0.013,0.167).

The midpoint of a line segment is (−3,2). One endpoint of the line segment is (4,−7).What are the coordinates of the other endpoint of the line segment?

Answers

The coordinates of the other endpoint of the line segment are $Y(x,y) = (-10, 11)$ .

Vectorially speaking, the midpoint of a line segment is determined by the following expression:

$M(x,y) = (1)/(2)\cdot X(x,y) + (1)/(2)\cdot Y(x,y)$ (1)

Where:

$M(x,y)$ - Midpoint.
$X(x,y)$ , $Y(x,y)$ - Endpoints of the line segment.

If we know that $M(x,y) = (-3, 2)$ and $X(x,y) = (4, -7)$ , then the coordinates of the other endpoint is:

$(1)/(2)\cdot Y(x,y) = M(x,y) -(1)/(2)\cdot X(x,y)$

$Y(x,y) = 2\cdot M(x,y) -X(x,y)$

$Y(x,y) = 2\cdot (-3,2)-(4,-7)$

$Y(x,y) = (-6, 4) - (4, -7)$

$Y(x,y) = (-10, 11)$

The coordinates of the other endpoint of the line segment are $Y(x,y) = (-10, 11)$ .

We kindly invite to check this question on midpoints: brainly.com/question/17506315

For spirit week at a local high school, students were encouraged to wear their school colors of green and white. 1,500 students wore their school colors while 300 students did not wear green and white. What percent of the school population did not wear their school colors?

Answers

Answer:

17%

Step-by-step explanation:

1,500 + 300 = 1,800

300/1,800 ≈ 17%

Select all of the numbers that Brooke could multiply by 2386 to get a product greater than 2386

Answers

Answer:

Step-by-step explanation:

Any number greater than 1 will give a number greater than 2386

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Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ability to hit the ball so far. Designers, therefore, have proposed that new golf courses need to be built expecting that the average golfer can hit the ball more than 230 yards on average. A random sample of 177 golfers show that their mean driving distance is 230.7 yards, with a standard deviation of 41.8.1. Set up the null and alternative hypotheses to test for the designers belief.a. H0 : µ ≥ 230 versus Ha : µ < 230b. H0 : µ = 230.7 versus Ha : µ ≠ 230.7c. H0 : µ ≥ 230.7 versus Ha : µ < 230.7d. H0 : µ ≤ 230.7 versus Ha : µ > 230.7e. H0 : µ ≤ 230 versus Ha : µ > 2302. Find the value of the standardized test statistic.a. 0.125b. -0.125c. 0.223d. -0.7e. 0.73. Find the P-value for the above mentioned test.a. 0.8237b. 0.0228c. 0.5871d. 0.4118e. 0.0871