A CPU manufacturer is interested in studying the relationship between clock speed and the operating temperature that results at that clock speed for a particular CPU model. Let x be the clock speed in MHz and let Y be the temperature in ^{\circ}C . The following data was collected:i xi yi1 350 31.42 360 35.63 370 41.84 380 51.05 390 56.86 400 62.87 410 67.4a) Find the equation of the regression line.b) Estimate the temperature for clock speed x = 430 MHz.c) Find the 95% confidence interval for \beta .d) Compute the coefficient of determination R^{2} ?. Is this a high quality fit?

Answer: 0.21

Step-by-step explanation:

We know that if two events A and B are independent , then the probability of A and B is given by :-

Given: The probability that an adult possesses a credit card P(A)= 0 .70

The probability that an adult  does not possess a credit card

By assuming the independence, the probability that the first adult possesses a credit card and the second adult does not possess a credit card is given by :-

Hence, the probability that the first adult possesses a credit card and the second adult does not possess a credit card is 0.21.

Answer:

The number of machine produced on Wednesday is 27.5.

Step-by-step explanation:

It is given that the number of machines produced by machinist on Tuesday is 25.

The machinist's goal was to increase his production by at least 10% each day.  

Therefore the number of produced machines on Wednesdays is 1% more than the number of machines produced on Tuesday.

The number of machine produced on Wednesday is,

Therefore the number of machine produced on Wednesday is 27.5.

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following annual growth rates:

land/food = - 1%

food/kcal = 0.5%

kcal/person = 0.1%

population = 1.5%

Σ annual growth rates = (-1 + 0.5 + 0.1 + 1.5)% = 1.1% = 0.011

Exponential growth in Land :

L = Lo * e^(rt)

Where Lo = Initial ; L = increase after t years ; r = growth rate

Time for amount of cultivated land to double

L = 2 * initial

L = 2Lo

2Lo = Lo * e^(rt)

2 = e^(0.011t)

Take the In of both sides

In(2) = 0.011t

0.6931471 = 0.011t

t = 0.6931471 / 0.011

t = 63.01 years

Land per unit of food at t = 63.01 years

L = Fo * e^(rt)

r = growth rate of land required to grow a unit of food = 1% = 0.01

L/Fo = e^(-0.01* 63.01)

L/Fo = e^(−0.6301)

= 0.5325385 = 0.53253 * 100% = 53.25%

Land per unit now takes (100% - 53.25%) = 46.75%

Answer:

The lifetime value needed is 11.8225 hours.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

The lifetime of a certain type of battery is normally distributed with mean value 11 hours and standard deviation 1 hour. This means that .

What lifetime value is such that the total lifetime of all batteries in a package exceeds that value for only 5% of all packages?

This is the value of THE MEAN SAMPLE X when Z has a pvalue of 0.95. That is between Z = 1.64 and Z = 1.65. So we use

Since we need the mean sample, we need to find the standard deviation of the sample, that is:

So:

The lifetime value needed is 11.8225 hours.

4 : 1 and 12 : 9 are not equivalent

Kareem is wrong

Correct question:

Kareem says that the ratio 4:1 is equivalent to the ratio 12:9 because

4 + 8 = 12 and 1 + 8 = 9. Is Kareem correct? Explain how you know

4 : 1 is in its simplest form already

12 : 9

= 12/9

= 4/3

= 4 : 3

Therefore,

4 : 1 and 12 : 9 are not equivalent

Kareem is wrong based on his assumption that 4 + 8 = 12 and 1 + 8 = 9

brainly.com/question/17352744

Kareem's statement: 4:1 is equal to 12:9. Let's see if this is correct.

We have to simplify the ratios. Since 4:1 is already simplified, we do not have to do anything with it. 12:9 could be simplified. To do so, we need to find the greatest common factor (GCF) of both numbers. The GCF of 12 and 9 is 3. Since 3 is the GCF for both numbers, we divide them by 3.

First number: 4

Second number: 3

Ratio: 4:3

We compare the ratio 4:3 to 4:1. Since they have different values, they are not equivalent to each other.

Answer:

C(60) = 2.7*10⁻⁴

t = 1870.72 s

Step-by-step explanation:

Let x(t) be the amount of chlorine in the pool at time t. Then the concentration of chlorine is  

C(t) = 3*10⁻⁴*x(t).

The input rate is 6*(0.001/100) = 6*10⁻⁵.

The output rate is 6*C(t) = 6*(3*10⁻⁴*x(t)) = 18*10⁻⁴*x(t)

The initial condition is x(0) = C(0)*10⁴/3 = (0.03/100)*10⁴/3 = 1.

The problem is to find C(60) in percents and to find t such that 3*10⁻⁴*x(t) = 0.002/100.  

Remember, 1 h = 60 minutes. The initial value problem is  

dx/dt= 6*10⁻⁵ - 18*10⁻⁴x =  - 6* 10⁻⁴*(3x - 10⁻¹)               x(0) = 1.

The equation is separable. It can be rewritten as dx/(3x - 10⁻¹) = -6*10⁻⁴dt.

The integration of both sides gives us  

Ln |3x - 0.1| / 3 = -6*10⁻⁴*t + C    or    |3x - 0.1| = e∧(3C)*e∧(-18*10⁻⁴t).  

Therefore, 3x - 0.1 = C₁*e∧(-18*10⁻⁴t).

Plug in the initial condition t = 0, x = 1 to obtain C₁ = 2.9.

Thus the solution to the IVP is

x(t) = (1/3)(2.9*e∧(-18*10⁻⁴t)+0.1)

then  

C(t) = 3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴t)+0.1)

If  t = 60

We have

C(60) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴*60)+0.1) = 2.7*10⁻⁴

Now, we obtain t such that 3*10⁻⁴*x(t) = 2*10⁻⁵

3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 2*10⁻⁵

t = 1870.72 s