Hello, there are three questions and pictures of them in the links If you could solve them that would be awesome, thank you!

Answers

Answer 1

Answer:

Answer:

1. 1 * $x^(3/6)$ = $x^(3/6)$ (it will be equal to the sixth root of x cube)

2. No, the expression $x^(3)$ X $x^(3)$ X $x^(3)$ will be equal to $x^(3 + 3 + 3 )$ since the powers of numbers with the same base are added

3. B and D 1/ $x^(-1)$ is the same as 'x'

as mentioned in the last answer, powers of numbers with same base are added. hence, option D will be $x^(3/3)$ which will be equal to x

Related Questions

Could you please help with this equation:Simplify the algebraic expression: 4(3x + y) – 2(x – 5y)
Find the slope using the formula.(4, 19) and (2, 11)
A point travels East 3 spaces and South 8 spaces.Write the description in algebraic terms.
A. X=1B. X=3C. X= 1,3D. X= 0,3
(2x - y + 3) (2x - y - 3)using identities

Which of the following correctly describes the graph of this function?

Answers

Answer: The graph of the function is symmetric about the y-axis.

Explanation:

Symmetric about the y-axis means that the graph can be reflected over, in this case the y-axis, without altering it. Your function is able to do this! I’ve attached a picture of the function so that you can visualize what I wrote.

(- 5x + 5) + (- 7x + 9) = 90 degrees

Answers

X=-19/3
Merry Christmas

Answer:

$x = ( - 19)/(3)$

Step-by-step explanation:

$( - 5x + 5) + ( - 7x + 9) = 90$

$= > 5 - 5x - 7x + 9 = 90$

$= > 14 - 12x = 90$

$= > - 12x = 90 - 14$

$= > - 12x = 76$

$= > x = (76)/( - 12) = ( - 19)/(3)$

On a coordinate plane, a line goes through (0, negative 3) and (2, 2). A point is at (2, negative 3).Complete the statements about finding the equation of the line that is parallel to line n and passes through point (2, –3).

The slope of the graphed line is
.
The slope of the parallel line is
.
An equation that can be used to find the y-intercept of the parallel line is
.
The y-intercept of the parallel line is
.
The equation of the parallel line is
.

Answers

Answer:

5/2, 5/2, -3= (5/2)(2)+b, -8, y=(5/2)x-8

Step-by-step explanation:

Answer:

The slope of the graphed line is

✔ 5/2

The slope of the parallel line is

✔ 5/2

An equation that can be used to find the y-intercept of the parallel line is

✔ –3 = (5/2)(2) + b

The y-intercept of the parallel line is

✔ –8

The equation of the parallel line is

✔ y = (5/2)x – 8

Step-by-step explanation:

What is the quotient of 1 over (1 plus the square root of 3)?

Answers

You can rationalize the denominator by multiplying by 1 in the form of the conjugate of the denominator divided by itself.

$(1)/(1+√(3))=(1)/(1+√(3))\cdot (1-√(3))/(1-√(3))\n\n=(1-√(3))/(1^(2)-(√(3))^(2))=(1-√(3))/(1-3)\n\n=(√(3)-1)/(2)$

This eqvaluates to approximately 0.3660254037844386.

The area of a trapezoid is given by the formula A=h/2(a+b) .

Solve the formula for b.

Answers

Answer:

(2A)/h -a =b

Step-by-step explanation:

A= [h(a+b)]/2 I rewrote the formula, because h and a+b are in the numerator.

2A=h(a+b) Multiply both sides of equation by 2

(2A)/h= a+b Divide both side by h

(2A)/h -a= b Subtract a from both sides

In △ABC, point P∈ AB
is so that AP:BP=1:3 and point M is the midpoint of segment
CP
. Find the area of △ABC if the area of △BMP is equal to 21m2.

Answers

Answer:

56 m²

Explanation:

A diagram can be helpful.

Triangles with the same altitude will have areas proportional to the length of their bases.

The altitude from B to PC is the same for triangles BMP and BMC, so they have areas that are in the same proportion as MP : MC. Since M is the midpoint of CP, MP = MC and ABMP = ABMC = 21 m². Then ...

... ACPB = 21 m² + 21 m² = 42 m²

The altitude from C to AB is the same for triangles CPA and CPB, so those triangles have areas in the sampe proportion as AP : BP = 1 : 3. Then ...

... ACPA : ACPB = PA : PB = 1 : 3

... ACPA : 42 m² = 1 : 3

So, the area of ∆CPA is 1/3 of 42 m², or 14 m². The area of ABC is the sum of the areas of CPA and CPB, so is ...

... AABC = ACPA + ACPB = 14 m² + 42 m²

... AABC = 56 m²